ICSE Class 8 Maths Selina Solutions Chapter 2 Exponents ...

Exercise 2(A)

Question 1. Evaluate: (i) (3-1 ? 9-1) ? 3-2 Solution:

(ii) (3-1 ? 4-1) ? 6-1 Solution:

(iii) (2-1 + 3-1)3 Solution:

(iv) (3-1 ? 4-1)2 Solution:

(v) (22 + 32) ? (1/2)2

ICSE Class 8 Maths Selina Solutions Chapter 2 Exponents (Powers)

ICSE Class 8 Maths Selina Solutions Chapter 2 Exponents (Powers) Solution: = (2 ? 2) + (3 ? 3) ? (? ? ?) = 4 + 9 ? ? = 13/4 = 3? (Simplifying the given equation) (vi) (52 - 32) ? (2/3)-3 Solution:

(vii) Solution:

(viii) Solution:

(ix) Solution:

ICSE Class 8 Maths Selina Solutions Chapter 2 Exponents (Powers)

(x) (5-1 ? 3-1) + 6-1 Solution:

Question 2. 1125 = 3m ? 5n; find m and n Solution: 1125 = 32 ? 53 The factors of 1125 are 3 ? 3 ? 5 ? 5 ? 5

Therefore 1125 = 3 ? 3 ? 5 ? 5 ? 5 Now comparing, 32 ? 53 = 3m ? 5n Therefore m=2, n=3 Question 3. Find x, if 9 ? 3x = (27)2x - 3 Solution: 9 ? 3x = (27)2x - 3 32 ? 3x = (3 ? 3 ? 3)2x - 3 (Simplifying the given equation) 3x + 2 = (3)3(2x - 3) 3x + 2 = (3)6x - 9 Since bases are same, compare them, x + 2 = 6x - 9 6x ? x = 9 + 2 5x = 11 x = 11/2 (Shifting the terms)

ICSE Class 8 Maths Selina Solutions Chapter 2 Exponents (Powers)

Exercise 2(B)

Question 1. Compute:

(i) 18 ? 30 ? 53 ? 22

Solution:

18 ? 30 ? 53 ? 22

= 1 ? 1 ? 5 ? 5 ? 5 ? 2 ? 2

= 125 ? 4

(Simplifying the given equation)

= 500

(ii) (47)2 ? (4-3)4

Solution: (47)2 ? (4-3)4 = 414 ? 4-12 = 414 ? 12 = 42

= 4 ? 4 = 16

(Simplifying the given equation)

(iii) (2-9 ? 2-11)3

Solution: = (2-9 + 11)3 = (22)3 = 26

(Simplifying the given equation)

= 2 ? 2 ? 2 ? 2 ? 2 ? 2 = 64

(iv)

Solution:

(v) Solution:

ICSE Class 8 Maths Selina Solutions Chapter 2 Exponents (Powers)

(vi) (12)-2 ?33 Solution: = (2 ? 2 ? 3)-2 ? 33 = (22 ? 3)-2 ? 33 = 2- 2 ? 2 ? 3-2 ? 33 =2-4 ? 3-2 + 3 ? 33 = 2-4 ? 31

(vii) (-5)4 ? (-5)6 ? (-5)9 Solution: = (-5)4 + 6 - 9 = (-5)1 = -5 (viii) Solution:

(ix) 90 ? 4-1 ? 2-4 Solution:

= 24-2 = 22 = 4

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