CHEM 1411 Chapter 12 Homework Answers

(a) n = PV P = 2.50 x 10-9 torr ∣ 1 atm ∣ = 3.29 x 10-12 atm RT ∣ 760 torr ∣ n = (3.29 x 10-12 atm)(1.00 L) = 3.27 x 10-14 mol O 2 (0.0821 L·atm/mol·K)(1225 K) 3.27 x 10-14 mol ∣ 6.02 x 1023 molecules∣ = 1.97 x 1010 molecules O 2 ∣ 1 mole ∣ ................
................