0580 w20 ms 21 - PapaCambridge

3 1.75 3 M2 for (13.72 – 2.8 × 2.65) ÷ 3.6 oe or M1 for 2.8 × 2.65 4(a) 4 points correctly plotted 2 B1 for 2 or 3 points correctly plotted 4(b) Negative 1 4(c) Correct ruled line of best fit 1 4(d) 10 to 12 1 FT their straight line of best fit 5 50 –1 0 4 2× M1 Allow M1 for 3 out of 4 values correctly ................
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