JustAnswer
atistical Analysis II – Set # 2
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|Question 1 of 40 |
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|Nonparametric statistical measures: |
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|A. compare population means or proportions to determine the relationship between variables. |
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|B. can only be used with independent samples. |
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|C. allow for testing procedures that eliminate some of the unrealistic assumptions required for testing by parametric measures. |
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|D. ignore individual measures, and, instead, focus on computed summary statistics of the populations being measured. |
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|Question 2 of 40 |
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|The chi-square distribution: |
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|A. compares sample observations to the expected values of a given variable. |
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|B. can be used to analyze both ordinal and nominal level data. |
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|C. is normally distributed. |
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|D. Both A and B |
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|Question 3 of 40 |
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|The chi-square test statistic: |
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|A. is computed from the actual and expected frequencies of the given set of data. |
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|B. is computed from the same distribution regardless of the number of degrees of freedom involved. |
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|C. is more commonly used for quantitative population variables. |
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|D. does not measure independence between events normal distribution (Wilcoxon matched-pair signed rank test). |
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|Question 4 of 40 |
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|Use the following data to answer questions 4-6: |
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|A random sample of cars passing through a service station showed the following results: |
|Blue |
|Red |
|Gray |
|Black |
|White |
|Green |
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|18 |
|24 |
|16 |
|21 |
|23 |
|18 |
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|For a X2 goodness-of-fit test, the null hypothesis is: |
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|A. there are more red cars on the road than any other color of car. |
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|B. the distribution of colors for cars on the road is uneven. |
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|C. there is an even number of cars on the road for all given colors. |
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|D. None of the above |
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|Question 5 of 40 |
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|The expected frequency for each color of car is: |
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|A. 10. |
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|B. 12. |
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|C. 20. |
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|D. 24. |
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|Question 6 of 40 |
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|The computed value of X2 is __________ indicating that we should __________ the null hypothesis. |
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|A. 0; reject |
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|B. 2.5; fail to reject |
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|C. 5.41; fail to reject |
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|D. 12.5; fail to reject |
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|Question 7 of 40 |
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|The X2 distribution: |
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|A. is normally distributed for observation sets with unequal expected frequencies. |
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|B. is normally distributed for large sample sizes. |
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|C. is negatively skewed for small sample sizes and a low number of degrees of freedom. |
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|D. approaches a normal distribution as the number of degrees of freedom increases. |
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|Question 8 of 40 |
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|The X2 distribution: |
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|A. can be applied to observation sets where the expected frequencies of only 3 of 10 observations is less than 5. |
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|B. should not be used in experiments with two cells with expected frequencies of less than 5. |
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|C. can be used as long as (fo- fe)2 is large. |
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|D. cannot be used if the expected frequencies are unequal. |
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|Question 9 of 40 |
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|A contingency table: |
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|A. is constructed from the expected frequencies of a variable. |
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|B. uses actual total population data to develop a hypothesis for dependence or independence. |
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|C. allows for statistical determinations to be made without the use of a test statistic. |
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|D. shows the frequency level of every possible combination of attributes in a given set of data. |
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|Question 10 of 40 |
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|A question has these possible choices — excellent, very good, good, fair, and unsatisfactory. How many degrees of freedom are there using |
|the goodness-of-fit test to the sample results? |
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|A. 0 |
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|B. 2 |
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|C. 4 |
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|D. 5 |
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|Question 11 of 40 |
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|What is the critical value at the 0.05 level of significance for a goodness-of-fit test if there are six categories? |
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|A. 3.841 |
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|B. 5.991 |
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|C. 7.815 |
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|D. 11.070 |
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|Question 12 of 40 |
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|A distributor of personal computers has five locations in the city. The sales in units for the first quarter of the year were as follows: |
|Location |
|Observed Sales (Units) |
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|North Side |
|70 |
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|Pleasant Township |
|75 |
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|Southwyck |
|70 |
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|I-90 |
|50 |
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|Venice Avenue |
|35 |
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|Total |
|300 |
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|What is the critical value at the 0.01 level of risk? |
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|A. 7.779 |
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|B. 15.033 |
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|C. 13.277 |
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|D. 5.412 |
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|Question 13 of 40 |
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|What is our decision for a goodness-of-fit test with a computed value of chi-square of 1.273 and a critical value of 13.388? |
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|A. Do not reject the null hypothesis |
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|B. Reject the null hypothesis |
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|C. Unable to reject or not reject the null hypothesis based on data |
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|D. Should take a larger sample |
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|Question 14 of 40 |
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|A student asked the statistics professor if grades were marked “on the curve.” The professor decided to give the student a project to |
|determine if last year's statistics grades were normally distributed. The professor told the student to assume a mean of 75 and a standard |
|deviation of 10 and to use the following results. |
|Letter Grade |
|Grade Average |
|Observed |
|Expected |
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|Over 100 |
|0 |
|0.70 |
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|A |
|90 up to 100 |
|15 |
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|B |
|80 up to 90 |
|20 |
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|C |
|70 up to 80 |
|40 |
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|D |
|60 up to 70 |
|30 |
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|F |
|50 up to 60 |
|10 |
|7.00 |
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|Under 50 |
|0 |
|0.00 |
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|What is the null hypothesis? |
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|A. Observed grades are not normally distributed. |
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|B. Observed grades are normally distributed with a mean = 75 and a standard deviation = 10. |
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|C. Observed grades are normally distributed with a mean = 80 and a standard deviation = 10. |
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|D. Observed grades are normally distributed with a mean = 70 and a standard deviation = 10. |
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|Question 15 of 40 |
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|Using the results in Question #14, what is the expected number of B's? |
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|A. 44.0 |
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|B. 14.5 |
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|C. 12.6 |
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|D. 27.8 |
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|Question 16 of 40 |
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|Use the following to answer Questions 16–20: |
|Recently, students in a marketing research class were interested in the driving behavior of students driving to school. Specifically, the |
|marketing students were interested if exceeding the speed limit was related to gender. They collected the following responses from 100 |
|randomly selected students: |
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|Speeds |
|Does Not Speed |
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|Males |
|40 |
|25 |
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|Females |
|10 |
|25 |
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|What is the null hypothesis for the analysis? |
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|A. There is no relationship between gender and speeding. |
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|B. The correlation between gender and speeding is zero. |
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|C. As gender increases, speeding increases. |
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|D. The mean of gender equals the mean of speeding. |
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|Question 17 of 40 |
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|The degrees of freedom for the analysis is/are: |
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|A. 1. |
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|B. 2. |
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|C. 3. |
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|D. 4. |
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|Question 18 of 40 |
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|Using 0.05 as the significance level, what is the critical value for the test statistic? |
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|A. 3.841 |
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|B. 5.991 |
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|C. 7.815 |
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|D. 9.488 |
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|Question 19 of 40 |
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|What is the value of the test statistic? |
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|A. 100 |
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|B. 9.89 |
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|C. 50 |
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|D. 4.94 |
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|Question 20 of 40 |
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|Based on the analysis, what can be concluded? |
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|A. Gender and speeding are correlated. |
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|B. Gender and speeding are not related. |
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|C. Gender and speeding are related. |
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|D. No conclusion is possible. |
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Top of Form
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|Question 21 of 40 |
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|The __________ test is useful for before/after experiments. |
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|A. goodness-of-fit |
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|B. sign |
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|C. median |
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|D. chi-square |
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|Question 22 of 40 |
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|The __________ test is useful for drawing conclusions about data using nominal level of measurement. |
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|A. goodness-of-fit |
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|B. sign |
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|C. median |
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|D. chi-square |
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|Question 23 of 40 |
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|In an experiment, a sample size of 10 is drawn, and a hypothesis test is set up to determine: H0 : p = 0.50; H1:p < or = 0.50; for a |
|significance level of .10, the decision rule is as follows: |
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|A. Reject H0 if the number of successes is 2 or less. |
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|B. Reject H0 if the number of successes is 8 or more. |
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|C. Reject H0 if the number of successes is three or less. |
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|D. Reject H0 if the number of successes is less than 2 or more than 8. |
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|Question 24 of 40 |
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|For a "before and after" test, 16 of a sample of 25 people improved their scores on a test after receiving computer-based instruction. For |
|H0 : p = 0.50; H1:p is not equal to 0.50; and a significance level of .05: |
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|A. z = 1.2, fail to reject the null hypothesis. |
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|B. z = 1.4, reject the null hypothesis. |
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|C. z = 1.4, fail to reject the null hypothesis. |
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|D. z = 1.64, reject the null hypothesis. |
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|Question 25 of 40 |
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|A sample group was surveyed to determine which of two brands of soap was preferred. H0 :p = 0.50; H1: p is not equal to 0.50. Thirty-eight |
|of 60 people indicated a preference. At the .05 level of significance, we can conclude that: |
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|A. z = 0.75, fail to reject H0. |
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|B. z = 1.94, fail to reject H0. |
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|C. z = 1.94, reject H0. |
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|D. z = 2.19, reject H0. |
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|Question 26 of 40 |
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|The performance of students on a test resulted in a mean score of 25. A new test is instituted and the instructor believes the mean score is|
|now lower. A random sample of 64 students resulted in 40 scores below 25. At a significance level of α = .05: |
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|A. H0 : p = 0.50; H1:p < 0.50. |
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|B. H0 : p = 0.50; H1:p > 0.50. |
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|C. H0 : p = 25; H1:p > 25. |
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|D. H0 : p = 25; H1:p < 25. |
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|Question 27 of 40 |
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|From the information presented in question #6: |
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|A. z = 3.75, we can reject the null hypothesis. |
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|B. z = 1.875, we fail to reject the null hypothesis. |
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|C. z = -1.625, we fail to reject the null hypothesis. |
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|D. z = -1.875, we can reject the null hypothesis. |
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|Question 28 of 40 |
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|A golf club manufacturer claims that the median length of a drive using its driver is 250 yards. A consumer group disputes the claim, |
|indicating that the median will be considerably less. A sample of 500 drives is measured; of these 220 were above 250 yards, and none was |
|exactly 250 yards. The null and alternate hypotheses are: |
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|A. Ho: 0 = 250; H1: 0 < 250. |
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|B. Ho: median = 250; H1: median > 250. |
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|C. Ho: 0 > 250; H1: 0 < 250. |
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|D. Ho: median = 250; H1: median < 250. |
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|Question 29 of 40 |
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|From the information presented in question #8, using a level of significance = .05: |
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|A. z = -1.74; we should fail to reject the null hypothesis. |
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|B. z = 2.64; we should fail to reject the null hypothesis. |
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|C. z = -2.72; we should fail to reject the null hypothesis. |
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|D. z = -3.17; we should reject the null hypothesis. |
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|Question 30 of 40 |
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|The Wilcoxon rank-sum test: |
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|A. is a nonparametric test for which the assumption of normality is not required. |
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|B. is used to determine if two independent samples came from equal populations. |
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|C. requires that the two populations under consideration have equal variances. |
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|D. Both A and B |
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|Question 31 of 40 |
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|A nonparametric test which can evaluate ordinal-scale data of a non-normal population is called the: |
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|A. Wilcoxon signed rank test. |
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|B. Kruskal-Wallis test. |
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|C. sign test. |
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|D. median test. |
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|Question 32 of 40 |
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|A researcher wishes to test the differences between pairs of observations with a non-normal distribution. She should apply the: |
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|A. Wilcoxon signed rank test. |
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|B. Kruskal-Wallis test. |
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|C. Wilcoxon rank-sum test. |
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|D. t test. |
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|Question 33 of 40 |
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|The data below indicate the rankings of a set of employees according to class theory and on-the-job practice evaluations: |
|Theory |
|1 |
|7 |
|2 |
|10 |
|4 |
|8 |
|5 |
|3 |
|6 |
|9 |
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|Practice |
|2 |
|8 |
|1 |
|7 |
|3 |
|9 |
|6 |
|5 |
|4 |
|10 |
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|What is the Spearman correlation of coefficient for the data? |
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|A. -0.0606 |
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|B. 0.1454 |
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|C. 0.606 |
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|D. 0.8545 |
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|Question 34 of 40 |
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|For the value of rs determined, a test of significance indicates that: |
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|A. t = -0.45, a weak negative relationship between the two variables. |
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|B. t = - 0.06, a strong negative relationship between the variables. |
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|C. t = 0.45, a weak positive relationship between the two variables. |
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|D. t = 4.65, a strong positive relationship between the variables. |
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|Question 35 of 40 |
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|To determine whether four populations are equal, a sample from each population was selected at random and using the Kruskal-Wallis test, H |
|was computed to be 2.09. What is our decision at the 0.05 level of risk? |
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|A. Fail to reject the null hypothesis because 0.05 < 2.09 |
| |
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|[pic] |
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| |
|B. Fail to reject the null hypothesis because 2.09 < 7.815 |
| |
| |
|[pic] |
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| |
|C. Reject the null hypothesis because 7.815 is > 2.09 |
| |
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|[pic] |
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|D. Reject the null hypothesis because 2.09 > critical value of 1.96 |
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|Question 36 of 40 |
| |
| |
|A soap manufacturer is experimenting with several formulas of soap powder and three of the formulas were selected for further testing by a |
|panel of homemakers. The ratings for the three formulas are as follows: |
|A |
|35 |
|36 |
|44 |
|42 |
|37 |
|40 |
| |
|B |
|43 |
|44 |
|42 |
|32 |
|39 |
|41 |
| |
|C |
|46 |
|47 |
|40 |
|36 |
|45 |
|49 |
| |
|What is the value of chi-square at the 5% level of significance? |
| |
| |
| |
|[pic] |
| |
| |
|A. 6.009 |
| |
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|[pic] |
| |
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|B. 6 |
| |
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|[pic] |
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| |
|C. 5.991 |
| |
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|[pic] |
| |
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|D. 5 |
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| |
|Question 37 of 40 |
| |
| |
|Which of the following values of Spearman's coefficient of rank correlation indicates the strongest relationship between two variables? |
| |
| |
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|[pic] |
| |
| |
|A. –0.91 |
| |
| |
|[pic] |
| |
| |
|B. –0.05 |
| |
| |
|[pic] |
| |
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|C. +0.64 |
| |
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|[pic] |
| |
| |
|D. +0.89 |
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| |
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| |
|Question 38 of 40 |
| |
| |
|Suppose ranks are assigned to a set of data from low to high with $10 being ranked 1, $12 being ranked 2, and $21 being ranked 3. What ranks|
|would be assigned to $26, $26 and $26? |
| |
| |
| |
|[pic] |
| |
| |
|A. 4, 5, 6 |
| |
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|[pic] |
| |
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|B. 4, 4, 4 |
| |
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|[pic] |
| |
| |
|C. 5, 5, 5 |
| |
| |
|[pic] |
| |
| |
|D. 5.5, 5.5, 5.5 |
| |
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| |
|Question 39 of 40 |
| |
| |
|Two movie reviewers gave their ratings (0 to 4 stars) to ten movies released this past month as follows: |
|Movie |
|A |
|B |
|C |
|D |
|E |
|F |
|G |
|H |
|I |
|J |
| |
|S's Rating |
|4 |
|2 |
|3.5 |
|1 |
|0 |
|3 |
|2.5 |
|4 |
|2 |
|0 |
| |
|T's Rating |
|3 |
|3 |
|3 |
|2.5 |
|1.5 |
|3.5 |
|4 |
|3 |
|2 |
|1 |
| |
|What is the rank order correlation? |
| |
| |
| |
|[pic] |
| |
| |
|A. 48 |
| |
| |
|[pic] |
| |
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|B. 0.7091 |
| |
| |
|[pic] |
| |
| |
|C. 2.306 |
| |
| |
|[pic] |
| |
| |
|D. 2.844 |
| |
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| |
|Question 40 of 40 |
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| |
|What is a requirement that must be met before the Kruskal-Wallis one-way analysis of variance by ranks test can be applied? |
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| |
|[pic] |
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|A. Populations must be normal or near normal |
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|[pic] |
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| |
|B. Samples must be independent |
| |
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|[pic] |
| |
| |
|C. Population standard deviations must be equal |
| |
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|[pic] |
| |
| |
|D. Data must be at least interval level |
| |
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| |
| |
21,22,26,27,29,31,32,34,35,36,40
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