1
27.29 First, the 2nd-order ODE can be reexpressed as the following system of 1st-order ODE’s (a) Shooting method: These can be solved for two guesses for the initial condition of z. For our cases we used –1 and 0.5. We solved the ODEs with the 4th-order RK method using a step size of 0.125. The results are. z(0) 1 0.5 T(10) 570 565 ................
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