Geometry



Geometry Name _______________

Practice Test

Unit 2 Period _____

1. Find the measure of each angle in the diagram. What geometric relationship did you use to find angles c, g, and k.

Explanation for (c:

Explanation for (g:

Explanation for (k:

2. Draw in two different heights for each figure.

a) parallelogram b) triangle

|Answers |

|50° (x2) |

|55° (x4) |

|75° (x2) |

|104 |

|125° (x2) |

|130 |

|150 |

[pic] [pic]

3. Find the area for each of the following.

|a) parallelogram |b) trapezoid |

|[pic] |[pic] |

4. Solve for x:

a) [pic] b) [pic]

5. Can a triangle have sides of length 8 feet, 15 feet, and 6 feet? Explain your reasoning.

|6. Two sides of a triangle have lengths of 10 feet and 4 feet. Give a range of|7. What name is given to the principle illustrated in |

|possible lengths for the third side. |problems 5 and 6? |

|8. Plot the points A(2, 2), B(5, 2), and C(4, 5). |[pic] |

|a) Reflect ΔABC across the x-axis and draw ΔA'B'C'. | |

|b) Rotate ΔABC 90° around the origin counterclockwise and make | |

|ΔA"B"C". | |

|c) Translate ΔABC so that the new coordinates of C are (−3, 0). | |

9. Show the dissections or subproblems that would give the area of the shaded region, then find its area.

|Answers |

|2 |

|3 |

|72 |

|(-6, -9 ) |

|(20, 34) |

[pic]

10. Where do the following two lines cross? Justify your response.

a) y = 3x+9 b) y = 2x − 6

y = x-3 3y − 5x = 2

|11. If the m∠1 = 120, then find the measures of the other angles and give the reasons |[pic] |

|justifying your answers. | |

| |Reason |

|m∠1=120 |Given information |

|m∠2= | |

|m∠3= | |

|m∠4= | |

|m∠5= | |

|m∠6= | |

|m∠7= | |

|m∠8= | |

12. Graph y = − x + 8 and y = x − 4 using the axes below. Then find the area of the figure enclosed by the two lines and the y-axis.

|Answers |

|36 |

|60° (x4) |

|120° (x3) |

[pic]

-----------------------

|Angle |Measure |

|a | |

|b | |

|c | |

|d | |

|e | |

|f | |

|g | |

|h | |

|i | |

|j | |

|k | |

e

b

c

d

a

f

g

h

i

j

k

50°

125°

................
................

In order to avoid copyright disputes, this page is only a partial summary.

Google Online Preview   Download