Week 1: Calculus I Practice Problem Solutions
x!0 log(1 + sin(2x)) x = exp lim x!0 2cos(2x)=(1 + sin(2x)) 1 = e2: Christian Parkinson GRE Prep: Calculus I Practice Problem Solutions 6 Note: to be more rigorous, you would actually need to show that F0(0) exists and is equal to this limit; on the GRE you can dispose of theoretical concerns like this for the sake of time, ................
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