Ecuaciones trigonométricas resueltas - BlogosferaSEK
Pero 1−sen2x=cos2x por tanto: cos2x cos2x−cosx−2cosx⋅cos 2x =0 , es decir: 2cos 2 x −cos x −2cos x ⋅cos 2x =0 y, de nuevo, podemos extraer, en este caso, cos x factor común: ................
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