Ecuaciones trigonométricas resueltas
Segunda solución: cos7x−cos210º=0 ; 7x=210º ; x=30º 4. Simplifica: sen2x 1 cos2x Sustituimos las fórmulas de sen y del coseno del ángulo doble en la ecuación: sen2x 1 cos2x = 2senx⋅cosx 1 cos2x−sen2x = 2senx⋅cosx 1 −sen2x cos2x cos2x = 2senx⋅cosx cos2x cos2x = 2senx⋅cosx 2cos2x = sen x cosx =tg x 5. Resuelve: sen2x=cos3x ................
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