Multiple Choice - Weebly



Practice 1.2D SolutionsMotion Graphs 2Multiple ChoiceAt time t = 0, car X traveling with speed v0 passes car Y which is just starting to move. Both cars then travel on two parallel lanes of the same straight road. The graphs of speed v versus time t for both cars are shown above.Which of the following is true at time t = 20 seconds?(A) Car Y is behind car X. (B) Car Y is passing car X. (C) Car Y is in front of car X.(D) Both cars have the same acceleration. (E) Car X is accelerating faster than car Y.The area under the curve is the displacement. There is more area under the curve for Car X.From time t = 0 to time t = 40 seconds, the areas under both curves are equal. Therefore, which of the following is true at time t = 40 seconds?(A) Car Y is behind car X. (B) Car Y is passing car X. (C) Car Y is in front of car X.(D) Both cars have the same acceleration. (E) Car X is accelerating faster than car Y.Area under the curve is the displacement. Car Y is moving faster as they reach the same pointAbove is a graph of the distance vs. time for car moving along a road. According the graph, at which of the following times would the automobile have been accelerating positively?0, 20, 38, & 60 min. (B) 5, 12, 29, & 35 min. (C) 5, 29, & 57 min. (D) 12, 35, & 41 min.(E) at all times from 0 to 60 minPositive acceleration is an increasing slope (including negative slope increasing toward zero) orupward curvatureWhich of the following sets of graphs might be the corresponding graphs of Position, Velocity, and Acceleration vs. Time for a moving particle?The velocity-time graph should represent the slope of the position-time graph and the acceleration-time graph should represent the slope of the velocity-time graphAnswer: CConsider the motion of an object given by the position vs. time graph shown. For what time(s) is the speed of the object greatest?(A) At all times from t = 0.0 s→ t = 2.0 s (B) At time t = 3.0 s (C) At time t = 4.0 s(D) At all times from t = 5.0 s → t = 7.0 s (E) At time t = 8.5 sSpeed is the slope of the line.Free ResponseProblem 1A group of students measures the motion of a cart in a long hallway. Use methods practiced in this class (think first week of school). time (s)displacement (m)252.89.83.616.24.424.25.233.86456.857.87.672.28.488.29.2105.810125Use excel to find the acceleration of the cart, according to the data.Looking at the graph above, you can create the equationY= mx+bIn this case b appears to be 0 soY= mxY= displacement x= time^2 and the slope of the graph is 1.25 soDisplacement = 1.25 t2Keep in mind that when an object starts from rest one of its acceleration equations is D= (1/2) at2So 1.25 = (1/2)aa= 2.5 m/s/sIf you were a teacher and a group turned these values in to you, would you be suspicious. If you had to confront them about cooking the data, what compelling evidence would you have?Their R2 value is 1, which is pretty difficult to get with something as inexact as measuring a cart with stopwatches.Problem 2True or False?? The cart in the above graphs in traveling in a positive directionTrueTrue or False?? the cart is experiencing a constant positive acceleration.TrueWhat is the cart's initial speed?5m/sWhat is the cart's initial position?4mHow much did the cart's velocity change from 2 to 14 seconds?36 m/sWhat is the cart's final velocity at 14 seconds?41 m/sHow fast was the cart traveling at 8 seconds?23 m/sHow far did the cart travel between 2 and 14 seconds?276 mWhat is the cart's final position at 14 seconds?280 mThe following equations describe the motion of an object. Use the power rule of derivation to find the equation for the velocity of the object. Then, state the velocity of the object at t= 2s.ft=5 0, 0m/sft=-2t-2, -2m/sft= -2t+2-2, -2m/sft=-2t2-5-4x, -8 m/sft=2t4+t3-t2+48t3 + 3t2 -2t, 72 m/s ................
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