7.1.3 Geometry of Horizontal Curves
ESSENTIALS 0F TRANSPORTATION ENGINEERING
Chapter 7 Highway Design for Safety
7.1.3 Geometry of Horizontal Curves
The horizontal curves are, by definition, circular curves of radius R. The elements of a horizontal curve are
shown in Figure 7.9 and summarized (with units) in Table 7.2.
Figure 7.9b
Figure 7.9a The elements of a horizontal curve
Table 7.2 A summary of horizontal curve elements
Symbol
PC
PT
PI
D
R
L
?
T
M
LC
E
Name
Point of curvature, start of horizontal curve
Point of tangency, end of horizontal curve
Point of tangent intersection
Degree of curvature
Radius of curve (measured to centerline)
Length of curve (measured along centerline)
Central (subtended) angle of curve, PC to PT
Tangent length
Middle ordinate
Length of long chord, from PC to PT
External distance
Units
degrees per 100 feet of centerline
feet
feet
degrees
feet
feet
feet
feet
The equations 7.8 through 7.13 that apply to the analysis of the curve are given below.
Fricker and Whitford
D=
36,000 5729.6
=
2¦ÐR
R
(7.8)
L=
100 ?
D
(7.9)
7.11
Chapter 7.1
ESSENTIALS 0F TRANSPORTATION ENGINEERING
Chapter 7 Highway Design for Safety
T = R tan
1
?
2
(7.10)
1 ?
?
M = R ?1 ? cos ? ?
2 ?
?
LC = 2R sin
(7.11)
1
?
2
(7.12)
?
?
?
?
1
? 1?
E = R?
1
?
?
? cos ? ?
2
?
?
(7.13)
Example 7.5
A 7-degree horizontal curve covers an angle of 63o15¡¯34¡±. Determine the radius, the length of the curve, and the
distance from the circle to the chord M.
Solution to Example 7.5
Rearranging Equation 7.8,with D = 7 degrees, the curve¡¯s radius R can be computed. Equation 7.9 allows
calculation of the curve¡¯s length L, once the curve¡¯s central angle is converted from 63o15¡¯34¡± to 63.2594 degrees.
The middle ordinate calculation uses Equation 7.11. These computations are shown below.
5729.6
= 818.5feet
7
100 ¡Á 63.2594¡ã
L=
= 903.7feet
7
M = 818.5 * (1 ? cos 31.6297¡ã) = 121.6feet
R=
If metric units are used, the definition of the degree of the curve must be carefully examined. Because the
definition of the degree of curvature D is the central angle subtended by a 100-foot arc, then a ¡°metric D¡± would be
the angle subtended by a 30.5-meter arc. The subtended angle ? does not change, but the metric values of R, L, and
M become
R=
5729.6
= 249.55 meters
7 * 3.28
1
? = 31.6297
2
100 * 63.2594¡ã
L=
= 275.52 meters
7 * 3.28
M = 249.55 * (1 ? cos 31.6297¡ã) = 37.07 meters
? = 63.2594 o ;
Fricker and Whitford
7.12
Chapter 7.1
................
................
In order to avoid copyright disputes, this page is only a partial summary.
To fulfill the demand for quickly locating and searching documents.
It is intelligent file search solution for home and business.
Related download
- proof of circle theorems solutions
- circle theorems cambridge university press
- highway engineering field formulas
- chord and angle properties of circles
- section i simple horizontal curves types of curve points
- 10 6 segment lengths in circles
- exercise 17 a page 210 byju s
- circle geometry
- rules for dealing with chords secants tangents in circles
- circles cmu
Related searches
- 7 1 ratios and proportions geometry answers
- horizontal curves formulas
- 1 3 cup of butter in tablespoons
- 1 3 stick of butter
- 1 3 cup of butter
- 1 3 transformation of function graphs answer
- 1 3 transformations of function graphs answer
- guided reading activity 1 3 types of government
- capitulo 7 1 or 3 396 396 1 0 0 0 1
- capitulo 7 1 or 3 2 0 5 396 396
- capitulo 7 1 or 3 268 268 1 0 0 0 1
- capitulo 7 1 or 3 2 0 5 268 268