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1.5 1a. [2 marks] Markscheme700 × 18.86? ? ? (M1)Note: Award (M1) for multiplication by 18.86.= 13?200 (13?202) (MXN)? ? ? (A1) (C2)?[2 marks]Examiners report [N/A] 1b. [2 marks] Markscheme2400 × 0.035? ? ? ?(M1)Note: Award (M1) for multiplication by 0.035.= 84 (MXN) ??? (A1) (C2)?[2 marks]Examiners report [N/A] 1c. [2 marks] Markscheme? ? ??(M1)Note: Award (M1) for dividing 2400 minus their part (b), by 17.24. Follow through from part (b).= 134.34 (USD)? ? ? ?(A1)(ft) (C2)Note: Award at most (M1)(A0) if final answer is not given to nearest cent.?[2 marks]Examiners report [N/A] 2a. [3 marks] Markscheme? ? ?(M1)(A1)Note: Award (M1) for substitution in compound interest formula, (A1) for correct substitution.OR N = 5I = 3.5PV = 1000P/Y = 1C/Y = 4Note: Award (A1) for?C/Y?= 4 seen, (M1) for other correct entries.ORN?= 5?× 4I?= 3.5PV?= 1000P/Y?= 1C/Y?= 4Note:?Award?(A1)?for?C/Y?= 4 seen,?(M1)?for other correct entries.= 1190.34 (USD)? ? ?(A1)Note: Award (M1) for substitution in compound interest formula, (A1) for correct substitution.[3 marks]Examiners report [N/A] 2b. [1 mark] Markscheme190.34 (USD)? ? ? (A1)(ft) (C4)Note: Award (A1)(ft) for subtraction of 1000 from their part (a)(i). Follow through from (a)(i).[1 mark]Examiners report [N/A] 2c. [2 marks] Markscheme? ? ?(M1)Note: Award (M1) for division of 170 by their part (a)(ii).= 0.89? ? ?(A1)(ft) (C2)Note: Follow through from their part (a)(ii).[2 marks]Examiners report [N/A] 3a. [3 marks] Markscheme? ? ?(M1)(A1)Note: Award (M1) for substitution into the compound interest formula, (A1) for correct substitution. Award at most (M1)(A0) if not equated to 17500.ORN = 5PV =?±14000FV = 17500P/Y = 1C/Y = 1? ? ?(A1)(M1)Note: Award (A1) for C/Y = 1 seen, (M1) for all other correct entries. FV and PV must have opposite signs.= 4.56 (%)? (4.56395… (%))? ? ?(A1) (G3)[3 marks]?Examiners report [N/A] 3b. [2 marks] Markscheme14000 × 66.91? ? ?(M1)Note: Award (M1) for multiplying 14000 by 66.91.936740 (INR)? ? ?(A1) (G2)Note: Answer must be given to the nearest whole number.[2 marks]Examiners report [N/A] 3c. [3 marks] Markscheme? ? ?(M1)(A1)(ft)Note: Award (M1) for substitution into the compound interest formula, (A1)(ft) for their correct substitution.OR N =?60I% = 5.2PV = ±936740P/Y=?12C/Y= 12? ? (A1)(M1)Note: Award (A1) for C/Y?= 12 seen, (M1) for all other correct entries.OR N?=?5I% = 5.2PV?= ±936740P/Y=?1C/Y= 12? ??(A1)(M1)Note: Award (A1) for?C/Y?= 12 seen,?(M1)?for?all?other correct entries= 1214204 (INR)? ? ?(A1)(ft) (G3)Note: Follow through from part (b). Answer must be given to the nearest whole number.[3 marks]Examiners report [N/A] 3d. [3 marks] Markscheme? ? ?(M1)Note: Award (M1) for dividing their (c) by 67.16. (USD)? ? ?(M1)(A1)(ft) (G3)Note: Award (M1) for finding the difference between their conversion and 17500. Answer must be given to the nearest whole number. Follow through from part (c).[3 marks]Examiners report [N/A] 4a. [2 marks] MarkschemeNote: ? ? In this question, the first time an answer is not to 2 dp the final (A1) is not awarded.? ? ? (M1)?Note: ? ? Award (M1) for dividing 350 by 0.1559.? ? ? (A1) ? ? (C2)[2 marks]Examiners report [N/A] 4b. [2 marks] Markscheme ? ? (M1)?Note: ? ? Award (M1) for multiplying their answer to part (a) by 1.02.? ? ? (A1)(ft) ? ? (C2)OR ? ? (M1)?Note: ? ? Award (M1) for multiplying their answer to part (a) by 0.02.? ? ? (A1)(ft) ? ? (C2)?Note: ? ? Follow through from part (a).?[2 marks]Examiners report [N/A] 4c. [2 marks] Markscheme ? ? (M1)?Note: ? ? Award (M1) for dividing 4228.38 by 585.? ? ? (A1) ? ? (C2)[2 marks]Examiners report [N/A] 5a. [3 marks] Markscheme ? ? (M1)(M1)?Note: ? ? Award (M1) for subtracting 5 from 85, (M1) for multiplying by 3.25.Award (M1) for , (M1) for subtracting .? ? ? (A1) ? ? (C3)[3 marks]Examiners report [N/A] 5b. [3 marks] Markscheme ? ? (M1)(M1)?Note: ? ? Award (M1) for multiplying by 0.96 (or equivalent), (M1) for dividing by 9.6. If division by 3.25 seen in part (a), condone multiplication by 9.6 in part (b).? ? ? (A1) ? ? (C3)[3 marks]Examiners report [N/A] 6a. [3 marks] Markscheme ? ? (M1)(M1)?Note: ? ? Award (M1) for multiplying 8000 by 0.09819, (M1) for multiplying by 0.98 (or equivalent).?769.81 (EUR) ? ? (A1) ? ? (C3)[3 marks]Examiners report [N/A] 6b. [3 marks] Markscheme ? ? (M1)(M1)?Note: ? ? Award (M1) for dividing 85 by 0.08753, and (M1) for multiplying their by and equating to 14.57.?OR ? ? (M1)?Note: ? ? Award (M1) for dividing 85 by 0.08753.?OR ? ? (M1)?Note: ? ? Award (M1) for dividing 14.57 by 9.71095… or equivalent.? ? ? (A1) ? ? (C3)[3 marks]Examiners report [N/A] 7a. [2 marks] MarkschemeThe first answer not given correct to two decimal places is not awarded the final (A1).Incorrect rounding is not penalized thereafter. ? ?(M1)?Note: ? ? Award (M1) for multiplying 3000 by 6.3021.? ? ??(A1) ? ? (C2)[2 marks]Examiners report [N/A] 7b. [4 marks] Markscheme ? ?(M1)(M1)(M1)?Note: ? ? Award (M1) for subtracting 12 000 from their answer to part (a) OR for 6906.30 seen, (M1) for dividing their amount by 8.7268 (can be implied if 791.389… seen) and (M1) for ?OR 750 seen.? ? ?(A1)(ft) ? ? (C4)?Note: ? ? Follow through from part (a).?[4 marks]Examiners report [N/A] 8a. [2 marks] Markscheme ? ? ? (M1) ? ? ? (A1) ? ?(C2)Note: Award (M1) for multiplication by . Answer must be an integer for the (A1) to be awarded.Examiners reportQuestion 9: Currency exchangeIn this question, incorrect rounding was once again the cause of many lost marks. It was surprising how many candidates have little idea about currency exchange and even less about the notion of commission. This part of the course is tested every year. 8b. [4 marks] Markschemei) ? ? ? ? ? (M1) ? ? ? (A1)Note: Award (M1) for division by . Answer must be an integer for the (A1) to be awarded.?ii) ? ? ? ? ?? (M1) ? ? ??(A1)(ft) ?(C4)Note: Award (M1) for multiplying their answer to part (b)(i) by . Follow through from part (b)(i). Answer must be an integer.Examiners reportIn this question, incorrect rounding was once again the cause of many lost marks. It was surprising how many candidates have little idea about currency exchange and even less about the notion of commission. This part of the course is tested every year. 9a. [2 marks] Markscheme ? ? ? (M1) ? ? ? (A1) ? ?(C2)Note: Award (M1) for correct division.Examiners reportQuestion 10: Currency conversion and compound interest.Currency conversion was done well by all but the weakest candidates. Most of the candidates that used the compound interest formula did a correct substitution but some did not equate this to the future value and found solving an equation to be challenging. Candidates that used the financial application on their GDC almost always wrote down a correct unrounded answer. 9b. [4 marks] Markscheme ? ? ? ? ?(M1)(A1)Note: Award (M1) for substitution into compound interest formula equated to , (A1) for correct substitution.OR ? ? ? ? ?(A1)(M1)Note: Award (A1) for seen, (M1) for other correct entries. and must have opposite sign. ? ? ? ? ?(A1) ? ? ? ? ?(A1)(ft)? ? ? ?(C4)Note: Award the final (A1)(ft)?for the correct rounding up, of their unrounded answer, to complete years.Examiners reportQuestion 10: Currency conversion and compound interest.Currency conversion was done well by all but the weakest candidates. Most of the candidates that used the compound interest formula did a correct substitution but some did not equate this to the future value and found solving an equation to be challenging. Candidates that used the financial application on their GDC almost always wrote down a correct unrounded answer. 10a. [2 marks] Markscheme ? ? (M1)Note: Award (M1) for multiplication by .? ? ? (A1) ? ? (C2)Examiners reportMany candidates lost at least two marks on this question for using an incorrect rate. The difference between “Bank buys” and “Bank sells” was not understood by many candidates. Their use of the table was often not consistent, leading to the candidates losing 4 marks, 2 in part (a) and 2 in part (b). Only very few candidates were confused on when to multiply and when to divide by a conversion rate. It was disappointing to see that so many candidates were not able to apply their knowledge of currency conversion in the real world context where both rates are given and the candidate had to decide which one to use. Methods marks were given out frequently, showing candidates were confident to calculate currency conversion with given rates. 10b. [4 marks] Markscheme ? ? (A1)(M1)(M1)Notes: Award (M1) for multiplication by a GBP rate (?or ), (M1) for division by a USD rate (?or ), (A1) for two correct rates used.? ? ? (A1) (C4)Note: Award a maximum of (A1)(ft)(M1)(M1)(A1)(ft) for , if in part (a) a rate of ?is used.Award a maximum of (A1)(ft)(M1)(M1)(A1)(ft) if division by an EUR rate is seen in part (a) and multiplication by ?and division by ?is seen in (b).Examiners reportMany candidates lost at least two marks on this question for using an incorrect rate. The difference between “Bank buys” and “Bank sells” was not understood by many candidates. Their use of the table was often not consistent, leading to the candidates losing 4 marks, 2 in part (a) and 2 in part (b). Only very few candidates were confused on when to multiply and when to divide by a conversion rate. It was disappointing to see that so many candidates were not able to apply their knowledge of currency conversion in the real world context where both rates are given and the candidate had to decide which one to use. Methods marks were given out frequently, showing candidates were confident to calculate currency conversion with given rates. 11a. [6 marks] Markscheme(i) ? ? ? ? (M1)Note: Award (M1) for correct substitution into Pythagoras’ formula.Accept correct alternative method using trigonometric ratios.? ? ? (A1) ? ? (AG)Note: The unrounded and rounded answer must be seen for the (A1) to be awarded.?OR ? ? (M1)Note:?Award (M1) for correct substitution into Pythagoras’ formula.? ? ? (A1) ? ? (AG)Note: The exact answer must be seen for the final (A1) to be awarded.?(ii) ? ? ? ? (M1)(M1)(M1)Note: Award (M1) for correct substitution into the volume of a cylinder formula, (M1) for correct substitution into the volume of a cone formula, (M1) for adding both of their volumes.? ? ? (A1)(G3)Examiners report [N/A] 11b. [2 marks] Markscheme ? ? (M1)Note:?Award (M1) for correct substitution into the volume of a cylinder formula.Accept alternative methods. Accept ?() from using rounded answers in .? ? ? (A1)(G2)Examiners report [N/A] 11c. [4 marks] Markscheme ? ? (M1)(M1)(M1)Note: Award (M1) for correct substitution into curved surface area of a cylinder formula, (M1) for correct substitution into the curved surface area of a cone formula, (M1) for adding the area of the base of the cylinder to the other two areas.? ? ? (A1)(G3)Examiners report [N/A] 11d. [4 marks] Markscheme ? ? (M1)(M1)Notes: Award (M1) for dividing their answer to (c) by , (M1) for multiplying by . Accept equivalent methods.? ? ? (A1)(ft)(G2)Notes: The (A1) is awarded for their correct answer, correctly rounded to 2 decimal places. Follow through from their answer to part (c). If rounded answer to part (c) is used the answer is ?(ZAR).Examiners report [N/A] 11e. [2 marks] Markscheme ? ? (M1)Note: Award (M1) for dividing ?by .? ? ? (A1)(G2)Note: The (A1) is awarded for the correct answer rounded to 2 decimal places, unless already penalized in part (d).Examiners report [N/A] 12a. [4 marks] Markscheme ? ? (M1)(M1)(M1)Note: Award (M1) for seen, (M1) for , (M1) for division by .?OR ? ? (M1)(M1)(M1)Note: Award (M1) for seen, (M1) for subtracting from , (M1) for division by .? ? ? (A1) ? ? (C4)Examiners report [N/A] 12b. [2 marks] Markscheme ? ? (M1)Note: Award (M1) for subtraction of from their product of .??? ? (A1) ? ? (C2)Notes: Award at most (M1)(A0) for an answer of , but only if working seen.Examiners report [N/A] 13a. [2 marks] Markscheme ? ? (M1) ? ? (A1) ? ? (C2)[2 marks]Examiners report [N/A] 13b. [2 marks] Markscheme ? ? (M1) ? (accept 84) ? ? (A1) ? ? (C2)[2 marks]Examiners report [N/A] 13c. [2 marks] Markscheme ? ? (M1)OR ? ? (M1) ? ? (A1)(ft) ? ? (C2)?Notes:?Follow through from their answer to part (b).?Note:?Do not penalize in part (c) if conversion process has been reversed consistently ie, multiplication by in part (a) and division by in part (c).?[2 marks]Examiners report [N/A] 14a. [2 marks] Markscheme ? ? (M1) ? ? (A1) ? ? (C2)[2 marks]Examiners report [N/A] 14b. [4 marks] Markscheme(i) ? ? ? ? (M1) ? ??(A1)?Note:?Accept ().? ? ?Award (M1) for .? ? ?Award (A0) for ?(ii) ? ? No, the part (b)(i) rate is not better value than the part (a) rate. ? ? (A1)(ft) ? ? (R1)ORNo, the part (b)(i) rate is not better value than the part (a) rate. ? ? (A1)(ft) ? ??(R1) ? ? (C4)?Note: Accept “part (a) rate is better” for the (A1)(ft).? ? ?Follow through from part (b)(i).? ? ?A numerical comparison must be seen to award (R1).?[4 marks]Examiners report [N/A] 15a. [2 marks] MarkschemeThe first answer not given to two decimal places is not awarded the final (A1). Incorrect rounding is not penalized thereafter.? ? ? (M1) ? ? (A1)(G2)[2 marks]Examiners reportDespite the fact that “Give all answers in this question correct to two decimal places” was written in bold at the top of the question, many candidates lost one (and only one) mark for giving at least one answer to only a single decimal place. There was a lot of reading in this question and some candidates seemed to lose their way as their solution developed and, as a consequence, lost marks in the latter part of the question. A significant number of candidates obtained nearly full marks for parts (a) through to (d). The marks which tended to not be awarded were not giving the required answer to two decimal places and not adding the amount invested onto the interest earned in part (c). Indeed, many candidates were able to correctly determine the depreciated value of the car on August 2009 by simply finding 91% of the original price. However, part (e) proved to be elusive for many candidates as some simply treated the problem as a ‘reverse simple interest problem’ and subtracted 9% for each of a further 3 years. As a consequence, erroneous answers of the form 17,361.60, from , were often conveniently ignored and rounded to the required answer of 18,600 GBP. Such a method earned no marks at all. There was a lot of information given in the stem to the last part of the question and, as a consequence, many candidates were unable to achieve full marks here. There was certainly a great deal of confusion as to what to divide by 0.8694 (seeing was not uncommon) and even introducing the original exchange rate of 0.7234 caused confusion. As a further example, an incorrect value carried forward from part (c) (1,250.55) led to a negative result. Provided the method was correct (despite an incorrect value carried forward), the three method marks were awarded. However, the negative result of –7,667.53 should have flagged to the candidate that something was wrong somewhere and this could only be in the current part of the question or part (c). 15b. [1 mark] MarkschemeThe first answer not given to two decimal places is not awarded the final (A1). Incorrect rounding is not penalized thereafter.? ? ??(A1)(ft)(G1)?Note: Follow through from part (a) irrespective of whether working is seen.?[1 mark]Examiners reportDespite the fact that “Give all answers in this question correct to two decimal places” was written in bold at the top of the question, many candidates lost one (and only one) mark for giving at least one answer to only a single decimal place. There was a lot of reading in this question and some candidates seemed to lose their way as their solution developed and, as a consequence, lost marks in the latter part of the question. A significant number of candidates obtained nearly full marks for parts (a) through to (d). The marks which tended to not be awarded were not giving the required answer to two decimal places and not adding the amount invested onto the interest earned in part (c). Indeed, many candidates were able to correctly determine the depreciated value of the car on August 2009 by simply finding 91% of the original price. However, part (e) proved to be elusive for many candidates as some simply treated the problem as a ‘reverse simple interest problem’ and subtracted 9% for each of a further 3 years. As a consequence, erroneous answers of the form 17,361.60, from , were often conveniently ignored and rounded to the required answer of 18,600 GBP. Such a method earned no marks at all. There was a lot of information given in the stem to the last part of the question and, as a consequence, many candidates were unable to achieve full marks here. There was certainly a great deal of confusion as to what to divide by 0.8694 (seeing was not uncommon) and even introducing the original exchange rate of 0.7234 caused confusion. As a further example, an incorrect value carried forward from part (c) (1,250.55) led to a negative result. Provided the method was correct (despite an incorrect value carried forward), the three method marks were awarded. However, the negative result of –7,667.53 should have flagged to the candidate that something was wrong somewhere and this could only be in the current part of the question or part (c). 15c. [3 marks] MarkschemeThe first answer not given to two decimal places is not awarded the final (A1). Incorrect rounding is not penalized thereafter. ? ? (A1)(M1)?Note: Award (A1) for seen or equivalent, (M1) for their multiplied by ?OR ? ? (A1)(M1)?Note:?Award (A1) for seen, and (M1) for .? ? ? (A1)(ft)(G2)?Note:?Follow through from part (a).?[3 marks]Examiners reportDespite the fact that “Give all answers in this question correct to two decimal places” was written in bold at the top of the question, many candidates lost one (and only one) mark for giving at least one answer to only a single decimal place. There was a lot of reading in this question and some candidates seemed to lose their way as their solution developed and, as a consequence, lost marks in the latter part of the question. A significant number of candidates obtained nearly full marks for parts (a) through to (d). The marks which tended to not be awarded were not giving the required answer to two decimal places and not adding the amount invested onto the interest earned in part (c). Indeed, many candidates were able to correctly determine the depreciated value of the car on August 2009 by simply finding 91% of the original price. However, part (e) proved to be elusive for many candidates as some simply treated the problem as a ‘reverse simple interest problem’ and subtracted 9% for each of a further 3 years. As a consequence, erroneous answers of the form 17,361.60, from , were often conveniently ignored and rounded to the required answer of 18,600 GBP. Such a method earned no marks at all. There was a lot of information given in the stem to the last part of the question and, as a consequence, many candidates were unable to achieve full marks here. There was certainly a great deal of confusion as to what to divide by 0.8694 (seeing was not uncommon) and even introducing the original exchange rate of 0.7234 caused confusion. As a further example, an incorrect value carried forward from part (c) (1,250.55) led to a negative result. Provided the method was correct (despite an incorrect value carried forward), the three method marks were awarded. However, the negative result of –7,667.53 should have flagged to the candidate that something was wrong somewhere and this could only be in the current part of the question or part (c). 15d. [3 marks] MarkschemeThe first answer not given to two decimal places is not awarded the final (A1). Incorrect rounding is not penalized thereafter. ? ? (M1)(A1)(ft)?Notes:?Award (M1) for substituted compound interest formula, (A1)(ft) for correct substitution.?? ? Follow through from part (a).?OR ? ? (M1)(A1)(ft)?Notes:?Award (M1) for substituted geometric sequence formula, (A1)(ft) for correct substitution.?? ? Follow through from part (a).?OR (lists (i)) ? ? (M1)(A1)(ft)?Notes:?Award (M1) for at least the term correct (calculated from their ). Award (A1)(ft) for four correct terms (rounded or unrounded).?? ? Follow through from part (a).?? ? Accept list containing the last three terms only ( may be implied).?OR (lists(ii)) ? ? (M1)(A1)(ft)?Notes:?Award (M1) for subtraction of four terms from .?? ? Award (A1) for four correct terms (rounded or unrounded).?? ? Follow through from part (a).? ? ? (A1)? ? ? (AG)?Note:?The final (A1) is not awarded unless both the unrounded and rounded answers are seen.?[3 marks]Examiners reportDespite the fact that “Give all answers in this question correct to two decimal places” was written in bold at the top of the question, many candidates lost one (and only one) mark for giving at least one answer to only a single decimal place. There was a lot of reading in this question and some candidates seemed to lose their way as their solution developed and, as a consequence, lost marks in the latter part of the question. A significant number of candidates obtained nearly full marks for parts (a) through to (d). The marks which tended to not be awarded were not giving the required answer to two decimal places and not adding the amount invested onto the interest earned in part (c). Indeed, many candidates were able to correctly determine the depreciated value of the car on August 2009 by simply finding 91% of the original price. However, part (e) proved to be elusive for many candidates as some simply treated the problem as a ‘reverse simple interest problem’ and subtracted 9% for each of a further 3 years. As a consequence, erroneous answers of the form 17,361.60, from , were often conveniently ignored and rounded to the required answer of 18,600 GBP. Such a method earned no marks at all. There was a lot of information given in the stem to the last part of the question and, as a consequence, many candidates were unable to achieve full marks here. There was certainly a great deal of confusion as to what to divide by 0.8694 (seeing was not uncommon) and even introducing the original exchange rate of 0.7234 caused confusion. As a further example, an incorrect value carried forward from part (c) (1,250.55) led to a negative result. Provided the method was correct (despite an incorrect value carried forward), the three method marks were awarded. However, the negative result of –7,667.53 should have flagged to the candidate that something was wrong somewhere and this could only be in the current part of the question or part (c). 16a. [2 marks] Markscheme5000 × 0.024 ? ? (M1)Note: Award (M1) for multiplication by 0.024.=120???? (A1) ? ? (C2)Examiners reportMarks were awarded in part (a) for multiplication by 0.024 in part (b) for division by 1.2945 and in part (c) for multiplication by 19495. Candidates did not follow specified levels of accuracy. Candidates were able to answer later parts of the question even if they did not answer the first parts correctly. 16b. [2 marks] Markscheme ??? (M1)Note: Award (M1) for multiplication by .= 3769.80 ? ? (A1)(ft)???? (C2)Note: Correct answer to 2 dp only. Follow through from their part (a).Examiners reportMarks were awarded in part (a) for multiplication by 0.024 in part (b) for division by 1.2945 and in part (c) for multiplication by 19495. Candidates did not follow specified levels of accuracy. Candidates were able to answer later parts of the question even if they did not answer the first parts correctly. 16c. [2 marks] Markscheme ? ? (M1)Note: Award (M1) for . ? ? (A1) ? ? (C2)Notes: Correct answer to nearest 1000 only. Do not penalize incorrect accuracy in (c) if this has already been penalized in part (b).Examiners reportMarks were awarded in part (a) for multiplication by 0.024 in part (b) for division by 1.2945 and in part (c) for multiplication by 19495. Candidates did not follow specified levels of accuracy. Candidates were able to answer later parts of the question even if they did not answer the first parts correctly. 17a. [2 marks] Markscheme ? ? (M1)Note: Award (M1) for multiplication by 0.006. ??? (A1)???? (C2)Examiners report [N/A] 17b. [4 marks] Markscheme???? (M1)(M1)(M1)Note: Award (M1) for subtracting 426.70 from their answer to part (a), (M1) for division by 0.673, (M1) for multiplication by 0.985 (or equivalent).OR???? (M1)(M1)(M1)Note: Award (M1) for subtracting 426.70 from their answer to part (a), (M1) for division by 0.673, (M1) for multiplication by 0.015 (or equivalent) and subtraction from their 173.30.254???? (A1)(ft) ? ? (C4)Notes: Follow through from their part (a). In order to award the final (A1)(ft) the answer must be given correct to the nearest dollar. If division used in part (a) and multiplication in part (b) award at most (M1)(M1)(M1)(A0).Examiners report [N/A] 18a. [2 marks] Markscheme1240 × 0.7681???? (M1)Note: Award (M1) for multiplying by 0.7681?= 952.44???? (A1) ? ? (C2)[2 marks]Examiners reportThis question was generally well done with the majority of candidates correctly using the currency conversions (multiplying in part (a) and dividing in part (b)) and, in most cases, working out the commission correctly in part (b). On a few scripts, candidates failed to round either one or both of their answers correctly to two decimal places and, as a consequence, lost a mark. 18b. [4 marks] Markscheme???? (M1)(M1)(M1)?Note: Award (M1) for dividing by 0.7470, (M1) for subtracting 0.0312 from 1, (M1) for multiplying by the (1 – 0.0312).?OR???? (M1)1004.016... × 0.0312 (= 31.325...) ? ? (M1) 1004.016... ? 31.325...???? (M1)?Note: Award (M1) for dividing by 0.7470, (M1) for multiplication by 0.0312, (M1) for subtraction of their 31.325 from their 1004.016.?OR750 × 3.12 % = 23.4 ? ? (M1)750 ? 23.4 = 726.60 ? ? (M1)???? (M1)?Note: Award (M1) for multiplication by 3.12 %, (M1) for subtraction of their 23.4 from 750, (M1) for division by 0.7470.?= 972.69???? (A1)???? (C4)Note: If division by 0.7681 is used in part (a) then award (M1) for multiplying by 0.7470 in part (b).[4 marks]Examiners reportThis question was generally well done with the majority of candidates correctly using the currency conversions (multiplying in part (a) and dividing in part (b)) and, in most cases, working out the commission correctly in part (b). On a few scripts, candidates failed to round either one or both of their answers correctly to two decimal places and, as a consequence, lost a mark. 19a. [2 marks] Markscheme650×12.50???? (M1)8125 (MXN)???? (A1)???? (C2)Note: Accept 8130.[2 marks]Examiners reportA lot of good work was seen in this question with many completely correct solutions. The two marks which were seen to be lost more often than others were the answer to part (b) where 182.16. 19b. [1 mark] Markscheme23 (MXN) ? ? (A1)???? (C1)[1 mark]Examiners reportA lot of good work was seen in this question with many completely correct solutions. The two marks which were seen to be lost more often than others were the answer to part (b) where 182.16. 19c. [3 marks] Markscheme???? (M1)Note: Award (M1) for setting up the expression.?182.16 (USD)???? (A1)(ft)?Note: Follow through from their answer to part (b).?182 (USD) ? ? (A1)(ft)???? (C3)?Notes: Award final (A1) for their answer correct to the nearest USD.[3 marks]Examiners reportA lot of good work was seen in this question with many completely correct solutions. The two marks which were seen to be lost more often than others were the answer to part (b) where 182.16. 20a. [3 marks] Markscheme350 × 10.275 × 0.02???? (M1)(M1)Note: Award (M1) for ×10.275, (M1) for ×0.02.71.93 (SEK) ? ? (A1) ? ? (C3)[3 marks]Examiners reportA common error in Question 9 was finding the amount of money received for part (a) rather than just the commission. Some candidates had difficulties giving the appropriate number of decimal places. 20b. [1 mark] Markscheme3524.33(SEK) ? ? (A1)(ft)???? (C1)Note: Accept 3524.32. Follow through from their answer to part (a).[1 mark]Examiners reportA common error in Question 9 was finding the amount of money received for part (a) rather than just the commission. Some candidates had difficulties giving the appropriate number of decimal places. 20c. [2 marks] Markscheme ??? (M1)9.25 ? ? (A1)???? (C2)[2 marks]Examiners reportA common error in Question 9 was finding the amount of money received for part (a) rather than just the commission. Some candidates had difficulties giving the appropriate number of decimal places. 21a. [2 marks] MarkschemeThe first time the answer is not given to 2 decimal places the final (A1) in that part is not awarded, incorrect rounding, following correct method, can be ignored in subsequent parts. ??? (M1) ??? (A1) ? ? (C2)[2 marks]Examiners reportAt whatever ability, there were good attempts by all candidates on this question with an overwhelming majority scoring half marks or more. Indeed, three out of the first four marks were invariably earned with only answers of EUR losing the final mark in part (b). In part (c), errors were invariably caused by candidates ignoring the commission charge or multiplying by rather than dividing by this value. Another common, but incorrect, method seen was multiply by , giving the wrong answer of USD. Both marks were lost in all the cases listed. 21b. [2 marks] MarkschemeThe first time the answer is not given to 2 decimal places the final (A1) in that part is not awarded, incorrect rounding, following correct method, can be ignored in subsequent parts. ? ? (M1) ? ? (A1)???? (C2)[2 marks]Examiners reportAt whatever ability, there were good attempts by all candidates on this question with an overwhelming majority scoring half marks or more. Indeed, three out of the first four marks were invariably earned with only answers of EUR losing the final mark in part (b). In part (c), errors were invariably caused by candidates ignoring the commission charge or multiplying by rather than dividing by this value. Another common, but incorrect, method seen was multiply by , giving the wrong answer of USD. Both marks were lost in all the cases listed. 21c. [2 marks] MarkschemeThe first time the answer is not given to 2 decimal places the final (A1) in that part is not awarded, incorrect rounding, following correct method, can be ignored in subsequent parts. ? ? (M1)Note: Follow through from their answer to part (b).? ? ? (A1)(ft) ? ? (C2)Note: Follow through from part (b).[2 marks]Examiners reportAt whatever ability, there were good attempts by all candidates on this question with an overwhelming majority scoring half marks or more. Indeed, three out of the first four marks were invariably earned with only answers of EUR losing the final mark in part (b). In part (c), errors were invariably caused by candidates ignoring the commission charge or multiplying by rather than dividing by this value. Another common, but incorrect, method seen was multiply by , giving the wrong answer of USD. Both marks were lost in all the cases listed. 22a. [2 marks] Markscheme ? ? OR???? ? ? (M1)???? (A1)???? (C2)[2 marks]Examiners reportThis question was generally well answered with much correct working seen in parts (a) and (b). The most popular incorrect answer in part (a) was – candidates simply stating the number of defective items rather than the number of non-defective items. Unfortunately in part (c) many candidates multiplied by rather than divided and proved a popular, but erroneous, answer. 22b. [2 marks] Markscheme ? ? (M1)???? (A1)(ft)???? (C2)Note: Follow through from their answer to part (a).[2 marks]Examiners reportThis question was generally well answered with much correct working seen in parts (a) and (b). The most popular incorrect answer in part (a) was – candidates simply stating the number of defective items rather than the number of non-defective items. Unfortunately in part (c) many candidates multiplied by rather than divided and proved a popular, but erroneous, answer. 22c. [2 marks] Markscheme ??? (M1) ??? (A1)???? (C2)Note: If division used in part (b) and multiplication used in part (c), award (M0)(A0) for part (b) and (M1)(A1)(ft) for part (c).[2 marks]Examiners reportThis question was generally well answered with much correct working seen in parts (a) and (b). The most popular incorrect answer in part (a) was – candidates simply stating the number of defective items rather than the number of non-defective items. Unfortunately in part (c) many candidates multiplied by rather than divided and proved a popular, but erroneous, answer. 23a. [2 marks] Markscheme4000?× 0.97 = 3880.00 (3880)???? (M1)(A1)(G2)Note: Award (M1) for multiplication of correct numbers.OR3 % of 4000 = 120 ? ? (A1)4000 – 120 = 3880.00 (3880)???? (A1)(G2)[2 marks]?Examiners reportMost of the students were penalized in this question for not given their money answers correct to the specified accuracy (2 decimal places).The first three parts were well done. Some students gave their answer to part (d) in (e) and their answer to (e) in (d). This means that when reading commission they directed their answers to a percentage (commission rate). 23b. [2 marks] Markscheme3880?× 0.3071 = 1191.55 ? ? (M1)(A1)(ft)(G2)Note: Award (M1) for multiplication of correct numbers. Follow through from their answer to part (a).[2 marks]Examiners reportMost of the students were penalized in this question for not given their money answers correct to the specified accuracy (2 decimal places).The first three parts were well done. Some students gave their answer to part (d) in (e) and their answer to (e) in (d). This means that when reading commission they directed their answers to a percentage (commission rate). 23c. [2 marks] Markscheme???? (M1)= 1280.00 (1280) ? ? (A1)(G2)Note: Award (M1) for division of correct numbers.[2 marks]?Examiners reportMost of the students were penalized in this question for not given their money answers correct to the specified accuracy (2 decimal places).The first three parts were well done. Some students gave their answer to part (d) in (e) and their answer to (e) in (d). This means that when reading commission they directed their answers to a percentage (commission rate). 23d. [1 mark] Markscheme63.20 (A1)(ft) Note: Follow through (their (c) –1216.80).[1 mark]Examiners reportMost of the students were penalized in this question for not given their money answers correct to the specified accuracy (2 decimal places).The first three parts were well done. Some students gave their answer to part (d) in (e) and their answer to (e) in (d). This means that when reading commission they directed their answers to a percentage (commission rate). 23e. [2 marks] Markscheme???? (M1)t = 4.94???? (A1)(ft)(G2) Note: Follow through from their answers to parts (c) and (d).[2 marks]Examiners reportMost of the students were penalized in this question for not given their money answers correct to the specified accuracy (2 decimal places).The first three parts were well done. Some students gave their answer to part (d) in (e) and their answer to (e) in (d). This means that when reading commission they directed their answers to a percentage (commission rate). 23f. [3 marks] Markscheme???? (M1)(A1)(A1)= 1109.70???? (AG)Notes: Award (M1) for substitution into correct formula, (A1) for correct substitution, (A1) for unrounded answer. If 1109.70 not seen award at most (M1)(A1)(A0).OR???? (M1)(A1)A = 1109.7023... ? ? (A1)= 1109.70 ? ? (AG) Note: Award (M1) for substitution into correct formula, (A1) for correct substitution, (A1) for unrounded answer.[3 marks]Examiners reportMost of the students were penalized in this question for not given their money answers correct to the specified accuracy (2 decimal places).Most of the students used the correct formula but not all made the correct substitution. From those that made the correct substitution, very few showed the unrounded answer. Part (b) was well done. In part (c) the majority did not put the interest (only) in the formula but the total amount $1109.70. 23g. [1 mark] Markscheme109.70 ? ? (A1)Note: No follow through here.[1 mark]Examiners reportMost of the students were penalized in this question for not given their money answers correct to the specified accuracy (2 decimal places).Most of the students used the correct formula but not all made the correct substitution. From those that made the correct substitution, very few showed the unrounded answer. Part (b) was well done. In part (c) the majority did not put the interest (only) in the formula but the total amount $1109.70. 24a. [2 marks] Markscheme1500 21.03464???? (M1)???? (A1)???? (C2)[2 marks]Examiners reportThe vast majority of candidates answered at least part of this question with a significant number achieving full marks. A number did have a financial penalty applied for not giving their answers according to the specified accuracy level for the question. The most difficult part turned out to be (c) and a number of students didn’t attempt it at all. There were very few candidates who used the incorrect conversion. 24b. [2 marks] Markscheme???? (M1)???? (A1)???? (C2)[2 marks]Examiners reportThe vast majority of candidates answered at least part of this question with a significant number achieving full marks. A number did have a financial penalty applied for not giving their answers according to the specified accuracy level for the question. The most difficult part turned out to be (c) and a number of students didn’t attempt it at all. There were very few candidates who used the incorrect conversion. 24c. [2 marks] Markscheme???? (M1)1 SGD = 6406 IDR ? ? (A1)???? (C2)?Note: Accept 6406.?[2 marks]Examiners reportThe vast majority of candidates answered at least part of this question with a significant number achieving full marks. A number did have a financial penalty applied for not giving their answers according to the specified accuracy level for the question. The most difficult part turned out to be (c) and a number of students didn’t attempt it at all. There were very few candidates who used the incorrect conversion. 25a. [2 marks] Markscheme5000 + 3 × 230 = 5690 ? ? (M1)(A1)(G2)?Note: Accept alternative method.?[2 marks]Examiners reportMost of the students read carefully the instruction written in the heading of the question and therefore gave their answers with the accuracy stated but some did not. Simple interest was well done as well as compound interest with only a small minority of candidates making no progress. A number of students lost the answer mark in (b) for not showing the unrounded answer before writing the answer given. It is also important to mention that calculator commands are not accepted as correct working and therefore full marks are not awarded. Also, some candidates wrote their answers without showing any working leading to a number of marks being lost. 25b. [3 marks] Markscheme or equivalent???? (M1)(A1) ? ? (A1)???? (AG)?Note: Award (M1) for correct substituted compound interest formula, (A1) for correct substitutions, (A1) for unrounded answer seen.If final line not seen award at most (M1)(A1)(A0).?[3 marks]Examiners reportMost of the students read carefully the instruction written in the heading of the question and therefore gave their answers with the accuracy stated but some did not. Simple interest was well done as well as compound interest with only a small minority of candidates making no progress. A number of students lost the answer mark in (b) for not showing the unrounded answer before writing the answer given. It is also important to mention that calculator commands are not accepted as correct working and therefore full marks are not awarded. Also, some candidates wrote their answers without showing any working leading to a number of marks being lost. 25c. [3 marks] Markscheme5000(1.042)n?> 6500? ? ?(M1)(A1)?Notes: Award (M1) for setting up correct equation/inequality, (A1) for correct values.Follow through from their formula in part (b).?ORList of values seen with at least 2 terms ? ? (M1)Lists of values including at least the terms with n = 6 and n = 7 ? ? (A1)?Note: Follow through from their formula in part (b).?ORSketch showing 2 graphs, one exponential, the other a horizontal line ? ? (M1)Point of intersection identified or vertical line ? ? (M1)Note: Follow through from their formula in part (b).n = 7???? (A1)(ft)(G2)?[3 marks]Examiners reportMost of the students read carefully the instruction written in the heading of the question and therefore gave their answers with the accuracy stated but some did not. Simple interest was well done as well as compound interest with only a small minority of candidates making no progress. A number of students lost the answer mark in (b) for not showing the unrounded answer before writing the answer given. It is also important to mention that calculator commands are not accepted as correct working and therefore full marks are not awarded. Also, some candidates wrote their answers without showing any working leading to a number of marks being lost. 25d. [3 marks] Markscheme5000(1.042)n > 5000 + 230n ? ? (M1)(A1)?Note: Award (M1) for setting up correct equation/inequality, (A1) for correct values.?OR2 lists of values seen (at least 2 terms per list)???? (M1)Lists of values including at least the terms with n = 5 and n = 6???? (A1)Note: One of the lists may be written under (c).ORSketch showing 2 graphs of correct shape ? ? (M1)Point of intersection identified or vertical line???? (M1)n = 6 ? ? (A1)(ft)(G2)Note: Follow through from their formulae used in parts (a) and (b).?[3 marks]Examiners reportMost of the students read carefully the instruction written in the heading of the question and therefore gave their answers with the accuracy stated but some did not. Simple interest was well done as well as compound interest with only a small minority of candidates making no progress. A number of students lost the answer mark in (b) for not showing the unrounded answer before writing the answer given. It is also important to mention that calculator commands are not accepted as correct working and therefore full marks are not awarded. Also, some candidates wrote their answers without showing any working leading to a number of marks being lost.It was nice to see many students recovering after part (d) and to gain full marks in the last two parts of the question. 25e. [4 marks] Markscheme6610?× 0.735???? (M1)= 4858.35 ? ? (A1)4858.35?× 0.982(= 4770.8997...) ? ? (M1)= 4771 Euros???? (A1)(ft)(G3)?Note: Accept alternative method.?[4 marks]Examiners reportMost of the students read carefully the instruction written in the heading of the question and therefore gave their answers with the accuracy stated but some did not. Simple interest was well done as well as compound interest with only a small minority of candidates making no progress. A number of students lost the answer mark in (b) for not showing the unrounded answer before writing the answer given. It is also important to mention that calculator commands are not accepted as correct working and therefore full marks are not awarded. Also, some candidates wrote their answers without showing any working leading to a number of marks being lost.It was nice to see many students recovering after part (d) and to gain full marks in the last two parts of the question. 25f. [5 marks] Markscheme800 × 1.29 (= 1032 USD) ? ? (M1)(A1)Note: Award (M1) for multiplying by 1.29, (A1) for 1032. Award (G2) for 1032 if product not seen.(1032 – 1006.20 = 25.8)???? (A1)(M1)?Note: Award (A1) for 25.8 seen, (M1) for multiplying by .?OR???? (M1)(A1)OR???? (M1)(A1)???? (A1)(G3)?Notes: If working not shown award (G3) for 2.5.Accept alternative method.?[5 marks]Examiners reportMost of the students read carefully the instruction written in the heading of the question and therefore gave their answers with the accuracy stated but some did not. Simple interest was well done as well as compound interest with only a small minority of candidates making no progress. A number of students lost the answer mark in (b) for not showing the unrounded answer before writing the answer given. It is also important to mention that calculator commands are not accepted as correct working and therefore full marks are not awarded. Also, some candidates wrote their answers without showing any working leading to a number of marks being lost.It was nice to see many students recovering after part (d) and to gain full marks in the last two parts of the question. 26a. [2 marks] Markschemek = 2.034?× 0.632???? (M1)= 1.29 (1 GBP = 1.29 EUR) ? ? (A1)???? (C2)Note: Accept 1.29 only?[2 marks]Examiners reportMost students gained full marks on this question. However, some students found the required format of the answer in part (a) confusing. 26b. [4 marks] MarkschemeFinancial penalty (FP) applies in part (b).?400?× 0.632???? (M1)= 252.80 EUR???? (A1)2 % of 252.80 = 5.06 EUR???? (A1)(FP)? ? ?She receives 247.74 EUR???? (A1)OR(FP)? ? ?0.98 × 252.80 = 247.74 EUR???? (A1)(A1)???? (C4)Note: Accept (A1) for 0.98 seen.?[4 marks]??Examiners reportMost students gained full marks on this question. However, some students found the required format of the answer in part (a) confusing. 27a. [2 marks] MarkschemeNote: Financial penalty (FP) applies in this part?(FP)? ? ? ? ? (M1)(A1)?Note: Award (M1) for multiplication by 0.6337.?[2 marks]Examiners reportThis question was well answered by many candidates, particularly part (a), however a significant number lost the financial penalty mark for not giving an answer correct to two decimal places, as stated in the question. 27b. [2 marks] MarkschemeNote: Financial penalty (FP) applies in this part? ?? (M1) Note: Award (M1) for multiplication by 3/100.?(FP) ? ? ? ? (A1)(ft)OR ? ? (M1)(FP) ? ? ??? (A1)(ft)???? (C4)[2 marks]Examiners reportThis question was well answered by many candidates, particularly part (a), however a significant number lost the financial penalty mark for not giving an answer correct to two decimal places, as stated in the question. 27c. [2 marks] Markscheme?Note: Financial penalty (FP) applies in this part?(FP) ? ? ??? (M1)(A1)???? (C2)Notes: Award (M1) for dividing by 0.6337.?[2 marks]Examiners reportThis question was well answered by many candidates, particularly part (a), however a significant number lost the financial penalty mark for not giving an answer correct to two decimal places, as stated in the question. 28a. [2 marks] MarkschemeFinancial penalty (FP) applies in this question.???? (M1)FP???? ???? (A1)???? (C2)Note: (M1) for multiplication by [2 marks]Examiners reportThis caused problems for many candidates. The form of the exchange rate proved difficult. 28b. [2 marks] Markscheme ??? (M1) ??? (A1)???? (C2)If Award (M1)(A0)[2 marks]Examiners reportMost candidates managed to answer this correctly. 28c. [2 marks] MarkschemeFinancial penalty (FP) applies in this question.???? (M1)(ft)FP???? ???? (A1)(ft)OR???? (M1)(ft)FP???? ???? (A1)(ft)OR???? (M1)(ft)FP???? ???? (A1)(ft)???? (C2)Note: (ft) in (c) if the conversion process is reversed consistently through the question, i.e. multiplication in (a) followed by division in (c). [2 marks]Examiners reportThis part also proved problematic for many candidates. 29a. [1 mark] MarkschemeFinancial penalty (FP) may apply in this question.(FP)???? (accept )???? (A1)???? (C1)[1 mark]Examiners reportThis question was well answered by a number of the candidates although a significant number lost a mark due to a financial penalty through not giving an answer correct to 2 decimal places. A very common mistake was to use () for () as the multiplier in part (c). 29b. [3 marks] MarkschemeFinancial penalty (FP) may apply in this question. ??? (A1) ??? (A1)(ft)(FP)???? ??? (A1)(ft)???? (C3)[3 marks]Examiners reportThis question was well answered by a number of the candidates although a significant number lost a mark due to a financial penalty through not giving an answer correct to 2 decimal places. A very common mistake was to use () for () as the multiplier in part (c). 29c. [2 marks] MarkschemeFinancial penalty (FP) may apply in this question.???? (A1)(ft)(FP)???? She lost ???? (A1)(ft)???? (C2)Notes: The word ‘lost’ is not required.If candidate has divided in (a) and multiplied in (b) and (c) consistently award (A0)(A1)(ft)(A1)(ft) for answers of for left and in (b) and (A1)(ft)(A1)(ft) for and in (c).[2 marks]Examiners reportThis question was well answered by a number of the candidates although a significant number lost a mark due to a financial penalty through not giving an answer correct to 2 decimal places. A very common mistake was to use () for () as the multiplier in part (c). 30a. [2 marks] MarkschemeFinancial accuracy penalty (FP) is applicable where indicated in the left hand column.Multiplying by or ??? (M1)(FP)???? ??? (A1)???? (C2)[2 marks]Examiners reportThis question was well answered by a number of candidates with few confusing the conversions. Some found the last part difficult with many leaving it out. 30b. [2 marks] MarkschemeFinancial accuracy penalty (FP) is applicable where indicated in the left hand column.Dividing by or ??? (M1)(FP)???? ??? (A1)???? (C2)Note: If candidate has divided in (a) and multiplied in (b) award (M1)(A1)(ft) for in (b).[2 marks]Examiners reportThis question was well answered by a number of candidates with few confusing the conversions. Some found the last part difficult with many leaving it out. 30c. [2 marks] MarkschemeFinancial accuracy penalty (FP) is applicable where indicated in the left hand column.(FP)???? allow and/or ???? (M1) ???? (A1)???? (C2)Note: The (M1) is being allowed for misreading values from the table but do not (ft) to candidate’s answers.[2 marks]Examiners reportThis question was well answered by a number of candidates with few confusing the conversions. Some found the last part difficult with many leaving it out. 31a. [1 mark] MarkschemeUnit penalty (UP) is applicable in part (i)(a)(c)(d)(e) and (f)(UP) 90°C???? (A1)[1 mark]Examiners reportMany candidates who had not lost a UP in question 2 lost one here. Parts (a), (c) and (d) were reasonably well tackled. Almost everybody had difficulty with the equation of the horizontal asymptote, a common answer being y = 20. Most of the candidates realised that 30 seconds was 0.5 minutes and calculated part (e) correctly. Part (f), solving an exponential equation, was a good discriminator. Trial and error was expected but many students did not think of doing this. 31b. [1 mark] Markschemey = 16???? (A1)[1 mark]Examiners reportMany candidates who had not lost a UP in question 2 lost one here. Parts (a), (c) and (d) were reasonably well tackled. Almost everybody had difficulty with the equation of the horizontal asymptote, a common answer being y = 20. Most of the candidates realised that 30 seconds was 0.5 minutes and calculated part (e) correctly. Part (f), solving an exponential equation, was a good discriminator. Trial and error was expected but many students did not think of doing this. 31c. [1 mark] MarkschemeUnit penalty (UP) is applicable in part (i)(a)(c)(d)(e) and (f)(UP) 16°C (ft) from answer to part (b)???? (A1)(ft)[1 mark]Examiners reportMany candidates who had not lost a UP in question 2 lost one here. Parts (a), (c) and (d) were reasonably well tackled. Almost everybody had difficulty with the equation of the horizontal asymptote, a common answer being y = 20. Most of the candidates realised that 30 seconds was 0.5 minutes and calculated part (e) correctly. Part (f), solving an exponential equation, was a good discriminator. Trial and error was expected but many students did not think of doing this. 31d. [1 mark] MarkschemeUnit penalty (UP) is applicable in part (i)(a)(c)(d)(e) and (f)(UP) 25.4°C ? ? (A1)[1 mark]?? Examiners reportMany candidates who had not lost a UP in question 2 lost one here. Parts (a), (c) and (d) were reasonably well tackled. Almost everybody had difficulty with the equation of the horizontal asymptote, a common answer being y = 20. Most of the candidates realised that 30 seconds was 0.5 minutes and calculated part (e) correctly. Part (f), solving an exponential equation, was a good discriminator. Trial and error was expected but many students did not think of doing this. 31e. [3 marks] MarkschemeUnit penalty (UP) is applicable in part (i)(a)(c)(d)(e) and (f)for seeing 20.75 or equivalent???? (A1)for multiplying their (d) by their 20.75 ??? (M1)(UP) 42.8°C???? (A1)(ft)(G2)[3 marks]Examiners reportMany candidates who had not lost a UP in question 2 lost one here. Parts (a), (c) and (d) were reasonably well tackled. Almost everybody had difficulty with the equation of the horizontal asymptote, a common answer being y = 20. Most of the candidates realised that 30 seconds was 0.5 minutes and calculated part (e) correctly. Part (f), solving an exponential equation, was a good discriminator. Trial and error was expected but many students did not think of doing this. 31f. [4 marks] MarkschemeUnit penalty (UP) is applicable in part (i)(a)(c)(d)(e) and (f)for seeing? ? ? (A1)for seeing a value of t between 1.54 and 1.56 inclusive ? ? (M1)(A1)(UP) 1.55 minutes or 92.9 seconds ? ? (A1)(G3)[4 marks]Examiners reportMany candidates who had not lost a UP in question 2 lost one here. Parts (a), (c) and (d) were reasonably well tackled. Almost everybody had difficulty with the equation of the horizontal asymptote, a common answer being y = 20. Most of the candidates realised that 30 seconds was 0.5 minutes and calculated part (e) correctly. Part (f), solving an exponential equation, was a good discriminator. Trial and error was expected but many students did not think of doing this. 31g. [3 marks] MarkschemeFinancial accuracy penalty (FP) is applicable in part (ii) only.(FP) ???? (A1)= 160.29 euros (correct answer only) ? ? (M1)first (A1) for 117 seen, (M1) for multiplying by 1.37???? (A1)(G2)[3 marks]Examiners reportThe financial part was the best done question in the paper and a large majority of candidates gained full marks here. 31h. [3 marks] MarkschemeFinancial accuracy penalty (FP) is applicable in part (ii) only.(FP) ???? (A1)(M1)9.85 GBP (answer correct to 2dp only)first (A1) is for 13.5 seen, (M1) for dividing by 1.37 ? ? (A1)(ft)(G3)[3 marks]Examiners reportThe financial part was the best done question in the paper and a large majority of candidates gained full marks here. 32. [2 marks] MarkschemeFinancial accuracy penalty (FP)?is?applicable where indicated in the left hand column.1 BRL = 2.607 ZAR?(FP) (i) ???? (A1)Note: 782.1 is (A0)(FP)(FP) (ii) ??? (A1)(ft)Note: Follow through only if processes are reversed.???? (C2)?[2 marks]Examiners reporta) Was well done, though many were awarded financial penalty with an answer of 782.1 for a(i).Printed for International School of Europe ? International Baccalaureate Organization 2019 International Baccalaureate? - Baccalauréat International? - Bachillerato Internacional? ................
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