Week 1: Calculus I Practice Problem Solutions

x!0 cos( x) 1 x2 = lim x!0 sin( x) 2x = lim x!0 2 cos( x) 2 = 2 2: Problem 4. Let c>0. Find the minimum value of f(x) = ex cxamong x2R. Solution. Setting the derivative to zero shows that extreme points occur when ex c= 0 x= log(c): The second derivative of fis always positive so any extreme point is … ................
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