S `iAA .ac.th

(4sinx+2cosx)dx = U7V(3 ... (1−cos2x) 1t KTH2eXe1p Hm i2! sin3xdxX 1t KTH2eXd1p Hm i2! cos5xdxX kyeRRR,* H+mHmbR + /2KB+v2 `kykR. RR9 1t KTH2eX31p Hm i2! sin2x cos3xdxX 1t KTH2eXN1p Hm i2! cos1/3 xsin3 xdxX 1t KTH2eXRy1p Hm i2! $ 1+sinx % 2 ................
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