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sinx. cos. dx. Let u = cosx, du. dx = -sinx, du = -sinx dx, 30. Then ∫ tan xdx −∫- sinx. cos. dx −∫ − du. u = - ln u + c = ln u-1 + c. u c ln. 1 ln. 1. cos x c = ln (secx) + c. we write ∫tan xdx = ln secx c. showing that ln of negative values does not exist. b) Find ∫cot xdx ∫ cot xdx ∫ ................
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