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Exhibit 10-1 Salary information regarding male and female employees of a large company is shown below.Male FemaleSample Size 64 36Sample Mean Salary (in $1,000) 44 41Population Variance (σ?) 128 72Solution: margin of error is: z(0.025)√(128/45+72/36) = 1.96(2) = 3.92Refer to Exhibit 10-1. At 95% confidence, the margin of error isa. 1.645 b. 1.96 c. 2.000 d. 3.920 _____________2. Refer to Exhibit 10-1. If you are interested in testing whether or not the average salary of males is significantly greater than that of females, the test statistic isSolution: statistic = (44-41)/ √(128/45+72/36) = 3/2 = 1.51.96 b. 2.0 c. 1.5 d. 1.645 ________________________________4. Exhibit 10-3Today Five Years Agox?(xbar) 82 88σ? 112.5 54n 45 36Refer to Exhibit 10-3. The p-value for the difference between the two population means isSolution: statistic = (82-88)/√112.5/45+54/36) = -6/2 = -3p-value = 2P(z<-3) = 2(0.0013) = 0.0026a. .0026 b. .4987 c. .9987 d. .0013 _____________________________________________________5.Exhibit 12-1When individuals in a sample of 150 were asked whether or not they supported capital punishment, the following information was obtained.Do you support capital punishment? # of individualsYes 40No 60No Opinion 50We are interested in determining whether or not the opinions of the individuals (as to Yes, No, and No opinion) are uniformly distributed. The conclusion of the test (at 95% confidence) is that theSolution:Ho: Opinions are uniformly distributedHa: Opinions are not uniformly distributed Yes No No opinión TotalFo 40 60 50 150Fe 50 50 50 150(Fo-Fe)2/Fe 2 2 0 4Statistical value = 4Df = 2, p-value = P(chi2 > 4) = 0.1353 > 0.05We fail to reject Hoa. test is inconclusive b. distribution is not uniform c. distribution is uniform d. none of these alternatives is correct _______________________________6. Exhibit 12-2Last school year, the student body of a local university consisted of 30% freshmen, 24% sophomores, 26% juniors, and 20% seniors. A sample of 300 students taken from this year’s student body showed the following number of students in each classificationFreshmen 83Sophomores 68Juniors 85Seniors 64We are interested in determining whether or not there has been a significant change in the classifications between the last school year and this school year. Solution:Ho: Opinions are uniformly distributedHa: Opinions are not uniformly distributed Freshmen Sophomores Juniors Seniors Total TotalFo 83 68 85 64 300Fe 90 72 78 60 300(Fo-Fe)2/Fe 0.5444 0.2222 0.6282 0.2667 1.6615 Statistical value = 1.6615Refer to Exhibit 12-2. The calculated value for the test statistic equalsa. 300 b. 1.6615 c. 6.6615 d. 0.5444 _________________________________7. In a sample of 100 Republicans, 60 favored the President's anti-drug program. While in a sample of 150 Democrats, 84 favored his program. At 95% confidence, test to see if there is a significant difference in the proportions of the Democrats and the Republicans who favored the President's anti-drug program.a.State the hypotheses involved in this test.Η 0: P1 - P2 - Select your answer -greater thangreater than or equal to equal to less than or equal toless thannot equal toItem 1 0Η a: P1 - P2 - Select your answer -greater thangreater than or equal toequal toless than or equal toless than not equal to Item 2 pute the value of the z test statistic (to 2 decimals).Solution: p1-hat = 60/100 = 0.6p2-hat = 84/150 = 0.56p-hat = (60+84)/(100+150) = 0.576Statistic = z = (0.6-0.56)/√[0.56(1-0.56)(1/100+1/150)] = 0.6269623 Answer: 0.63c.What is the p-value (to 4 decimals)?Solution: p-value = 2P(z>0.63) = 0.5287Answer: 0.5287d.What is your conclusion?- Select your answer -Conclude there is a significant difference between the proportions of Democrats and Republicans who favor the president's anti-drug plan Do not conclude there is a significant difference between the proportions of Democrats and Republicans who favor the president's anti-drug plan _______________________________________________8.For a one-tailed test (upper tail), a sample size of 26 at 90% confidence, t =a. 1.316 b. 1.740 c. -1.740 d. -1.316 __________________________________________________9. The average hourly wage of computer programmers with 2 years of experience has been $21.80. Because of high demand for computer programmers, it is believed there has been a significant increase in the average wage of computer programmers. To test whether or not there has been an increase, the correct hypotheses to be tested area. H0: μ > 21.80 Ha: μ ≤ 21.80b. H0: μ = 21.80 Ha: μ ≡ 21.80c. H0: μ ≤ 21.80 Ha: μ > 21.80d. H0: μ < 21.80 Ha: μ ≥ 21.8010. A weatherman stated that the average temperature during July in Chattanooga is 80 degrees or less. A sample of 32 Julys is taken. The correct set of hypotheses is??a.H0: μ ≤ 80 Ha: μ > 80 ?b.H0: μ ≡ 80 Ha: μ = 80 ?c.H0: μ ≥ 80 Ha: μ < 80 ?d.H0: μ < 80 Ha: μ > 80 11. A group of young businesswomen wish to open a high fashion boutique in a vacant store but only if the average income of households in the area is at least $25,000. A random sample of 9 households showed the following results.?$28,000 $24,000 $26,000 $25,000$23,000 $27,000 $26,000 $22,000$24,000Assume the population of incomes is normally distributed.1. Compute the sample mean and the standard deviation (to 2 decimals, if necessary).?x?? = 25,000 and σ = 1936.492. State the hypotheses for this problem.Η 0: μ - Select your answer -greater than greater than or equal to equal toless than or equal toless thannot equal to 25,000Η a: μ - Select your answer -greater thangreater than or equal toequal toless than or equal to less than not equal to 25,0003. Compute the test statistic.Answer: 0?12. The average starting salary of students who graduated from colleges of Business in 2009 was $48,400. A sample of 100 graduates of 2010 showed an average starting salary of $50,000. Assume the standard deviation of the population is known to be $8,000. We want to determine whether or not there has been a significant increase in the starting salaries.1. State the null and alternative hypotheses to be tested.Ho: μ ≤ 48,400?Ha: μ > 48,400??2. Compute the test statistic.Answer: 23. The null hypothesis is to be tested at 95% confidence. Determine the critical value for this test (to 2 decimals).Answer: 1.654. What do you conclude?We reject Ho (there has been a significant increase in the starting salaries)5. Compute the p-value (to 4 decimals).%Answer: 0.0228?13. A department store believes that telephone calls come into the switchboard at 10-minute intervals, according to a Poisson distribution. Before ordering new equipment, the store wishes to determine whether the Poisson model is a valid assumption. Records on the number of calls received were kept for a random selection of 150 ten-minute intervals. The results are shown below.Number of Calls Frequency0 51 182 243 304 325 136 207 8 ___ 150???1. What is the average number of calls during these ten-minute intervals (to 1 decimal)?Answer: 3.52. Generate the expected number of calls using a Poisson probability table (to 3 decimals).Number of Calls ei 0 or 1 20.3832 27.7443 32.3684 28.3225 19.8256 11.5657 or more 9.7933. 4. Give the null and alternative hypotheses for the appropriate test.Η 0: - Select your answer -The number of telephone calls during a 10 minute interval follows a Poisson distributionThe number of telephone calls during a 10 minute interval does not follow a Poisson distribution Η a: - Select your answer -The number of telephone calls during a 10 minute interval follows a Poisson distributionThe number of telephone calls during a 10 minute interval does not follow a Poisson distribution 5. Determine the number of degrees of freedom for this test.Let k = number of categories or classes remaining after combining classesk = 7, Df = k-1 = 7-1 = 6Answer: df = 66. Calculate the value of the test statistic (to 2 decimals).χ2 = (23-20.343)2/20.343 +…..+(8-9.793)2/9.793 = 9.99Answer: 9.997. Based on the p-value what is your conclusion? If we use ??= 0.05 p-value = P(chi>9.99)= 0.1251 > 0.05 Answer: we fail to reject Ho- Select your answer -The Poisson distribution is not a valid modelThe Poisson distribution is a valid model ? ................
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