Physics Challenge Question 2: Displacement and velocity



Physics Challenge Question 2: Solutions

Question 1:

Time: 0.0 sec 1.0 sec 2.0 sec 3.0 sec 4.0 sec 5.0 sec 6.0 sec

[pic] [pic] [pic] [pic] [pic] [pic] [pic]

Distance: 0.0 ft 5.0 ft 15 ft 25 ft 35 ft 55 ft 60 ft

Velocity:

Here, I just calculate the displacement and divide it by the time interval (each of those is 1 sec). For example, the second interval is, with 2 significant figures,

[pic]

Question 2:

The average velocity is

[pic]

Question 3:

I can use the first and last measurement to calculate the average velocity over the whole stretch. This is no coincidence – what happens in between doesn’t matter for the average velocity!

[pic]

Question 4:

1 ft = 0.3048 m, so [pic]

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5.0 ft/s

10 ft/s

10 ft/s

10 ft/s

20 ft/s

5.0 ft/s

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