Physics Challenge Question 2: Displacement and velocity
Physics Challenge Question 2: Solutions
Question 1:
Time: 0.0 sec 1.0 sec 2.0 sec 3.0 sec 4.0 sec 5.0 sec 6.0 sec
[pic] [pic] [pic] [pic] [pic] [pic] [pic]
Distance: 0.0 ft 5.0 ft 15 ft 25 ft 35 ft 55 ft 60 ft
Velocity:
Here, I just calculate the displacement and divide it by the time interval (each of those is 1 sec). For example, the second interval is, with 2 significant figures,
[pic]
Question 2:
The average velocity is
[pic]
Question 3:
I can use the first and last measurement to calculate the average velocity over the whole stretch. This is no coincidence – what happens in between doesn’t matter for the average velocity!
[pic]
Question 4:
1 ft = 0.3048 m, so [pic]
-----------------------
5.0 ft/s
10 ft/s
10 ft/s
10 ft/s
20 ft/s
5.0 ft/s
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