Example 2. f x) = x n where n = 1 2 3 - MIT OpenCourseWare
Δy n n ) n = ( x+Δ )n (−x = x+ n(Δ )(n−1 O(Δ 2 −x = nx n −1+O(Δx) Δx Δx Δx As it turns out, we can simplify the quotient by canceling a Δx in all of the terms in the numerator. When we divide a term that contains Δx2 by Δx, the Δx2 becomes Δx and so our O(Δx2) becomes O(Δx). When we take the limit as x approaches 0 we get: ................
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