PHYSICAL SCIENCES MEMORANDUM/ EXPECTED ANSWER MARCH TEST ...
1
PHYSICAL SCIENCES
MEMORANDUM/ EXPECTED ANSWER MARCH TEST 2018 ? GRADE 11
MARKS
: 75
TIME
: 1 Hrs
QUESTION 1
1.1 D
1.2 A
1.3 A
1.4 C
1.5 C
_____________________________________________________________________________[10]
QUESTION 2
2.2 Resultant is the vector sum of two or more vectors, i.e. a single vector having the
same effect as two or more vectors together.
(2)
2.2.1 Fx = -3 + 4 + 2 cos 30?
Fx = 2,73 N
(2)
2.2.2 Fy = 5 + ? 2 sin 30?
Fy = 4 N
(2)
2.2.3 Fnet2 = Fx2 + Fy2
Fnet = (2,73)2 + (4)2
Fnet = 4.84 N
tan = ,
= 55,7?
(5)
_____________________________________________________________________________[11]
QUESTION 3
3.1 State Newton's second law of motion: When a resultant/net force acts on an object,
the object will accelerate in the direction of the (net) force
at an acceleration directly proportional to the (net) force and inversely proportional
to the mass of the object.
(2)
3.2
(4) 3.3.1 Fnet on the car Fnet = ma FTx ? fk = ma FTx ? 1456 = 1100a FTx = 1100a + 1456 ... (1) Fnet on the truck Fnet = ma Fapp(engine) - *FTx ? fk = ma 15 000 - FTx ? 4520 = 4000a -FTx = 4000a ? 10480 ... (2) (1) = (2) 1100a + 1456 = -(4000a ? 10480) a = 1.77 m?s-2 right
3.3.2 Substitute a in (1) or (2) FTx = 1100a + 1456 Tcos 30? = 1100a + 1456 Tcos 30? = 1100(1.77) + 1456
T = 3929.45 N
Car
*The Tx of the cable exerts a force to the left on the truck.
(6)
? FTX = Tcos30? ? + from 3.3.1 for acceleration.
(3)
1
2
3.5 (Wrong numbering.) x = vi t + a
? + from 3.3.1.
= 0 + (1.77) (4)2
= 14.16 m
(2)
3.6 A body will remain in its state of rest or motion at constant velocity unless a non-zero
resultant/net force acts on it.
(2)
3.7 If the rope breaks/snaps, the car will continue forward at the same speed as before and will
crash into the back of the tow truck.
(2)
3.8 1890 N Newton's Third law. The truck exerts the same force on the car.
(2)
_____________________________________________________________________________[23]
QUESTION 4
4.1 fk = ukN
fk = 0,2(4)(9,8)cos40?
fk = 6,01 N up the slope
(4)
4.2
(5)
8 kg
4 kg
fk = ukN fk = 0,2(8)(9,8) fk = 15.68N Fnet = ma T? 15.68 = 8a
a = (T ? 15.68) / 8
fk = 6.01 Fg// = mg sin40?
= (4)(9.8)sin40?
= 25.19 N Fnet =ma Fg// - T ? fk = ma 25.19 ? T ? 6.01 = 4a
25.19 - T - 6.01 = 4 (T ? 15.68) / 8 T =18.01 N
4.2 (Sorry for the wonky numbering.)
(2)
Greater than . The Fg// increases hence Fnet increases
_____________________________________________________________________________[11]
QUESTION 5
5.1 Each particle in the universe attracts every other particle with a gravitational force
that is directly proportional to the product of their masses and inversely proportional
to the square of the distance between their centres.
(2)
5.2 F =
F= .
, ,
,
F= 3,70 10 N
(4)
5.3 Equal to . Newton's third law obeyed
(2)
_____________________________________________________________________________[08]
QUESTION 6
6.1 Electronegativity is a measure of the tendency of an atom in a molecule to attract
bonding electrons.
(2)
6.2.1 CH4 =
tetrahedral shape
CO2 =
linear shape
H2O =
angular/bent
(3)
6.2.2
6.3 CH4 =
non-poplar
CO2 =
non-polar
H2O =
polar
(3)
6.3 Hydrogen bonds
(1)
________________________________________________________________________[12]
TOTAL = 75
2
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