C
Suppose your electric lights use 400 watts per hour and average four hours per day, every day for one year. a.) How many kWh per year does this represent? 400 W= 400 J/s. 400 J/s ( 4h/d)(3600 sec/h) (365 d/yr) ( 1kWh/ 3.6 x 10 6 J)= 584 kWh/yr. b.) If replacing the lights with a fluorescent bulb would save 60 w per night, what savings in kWh ... ................
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