GRADE 12 JUNE 2021 MATHEMATICAL LITERACY P1 MARKING GUIDELINE (EXEMPLAR)
NATIONAL SENIOR CERTIFICATE
GRADE 12
JUNE 2021
MATHEMATICAL LITERACY P1 MARKING GUIDELINE (EXEMPLAR)
MARKS: 100
Symbol M MA CA A C S RT/RG/RM F SF J P
R AO NPR
Explanation Method Method with accuracy Consistent accuracy Accuracy Conversion Simplification Reading from a table/Reading from a graph/Reading from a map Choosing the correct formula Substitution in a formula Justification Penalty, e.g. for no units, incorrect rounding off etc.
Rounding Off/Reason Answer only No penalty for rounding
This marking guideline consists of 11 pages.
2
MATHEMATICAL LITERACY P1
MARKING GUIDELINE
(EC/JUNE 2021)
NOTE:
? If a candidate answers a question TWICE, only mark the FIRST attempt. ? If a candidate has crossed out (cancelled) an attempt to a question and NOT redone
the solution, mark the crossed out (cancelled version) ? Consistent accuracy (CA) applies in ALL aspects of the marking guidelines,
however it stops at the second calculation error. ? If the candidate presents any extra solution when reading from a graph, table, layout
plan and map, then penalise for every extra incorrect item presented.
LET WEL:
? As kandidaat vraag TWEE keer beantwoord, merk slegs die EERSTE poging. ? As kandidaat antwoord van vraag doodtrek (kanselleer) en nie oordoen nie,
merk die doodgetrekte (gekanselleerde) poging. ? Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyn toegepas,
maar dit hou by die tweede berekeningsfout op. ? Wanneer kandidaat aflesings vanaf grafiek, tabel, uitlegplan en kaart geneem en
ekstra antwoorde gee, penaliseer vir elke ekstra verkeerde item.
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(EC/JUNE/2021)
MATHEMATICAL LITERACY P1
3
QUESTION 1 [20 MARKS] INTEGRATED QUESTION Question Solution
1.1 1.1.1 1.1.2
VAT inclusive price means the price that has added VAT value J
M M % Profit== 0,30 ? 100 = 42,86% CA
0,70
1.1.3 Joy's profit= 2 ? 50 ? 0,30 RT =R 30,00 CA
1.2 1.2.1
Rate = R96,61
100
C
= R0,9661 per kWh CA
1.2.2 Total amount = 96,61 ? 50 = 4830,5 cents M
Explanation/Marks AO: FULL MARKS
2A justification
(2)
1M subtraction for profit
1M division and
multiplication by100
1CA
(2)
1 RT correct values 1CA answer.
(2)
Topic/L F L1 F L1
F L1
1C Conversion 1CA rate
F L1 (2)
1M multiply by 50
=
4830,5 100
CA =R48,30
OR
F L1
1CA amount
Total amount = R 0,9661 ? 50 M = R48,30 CA
NPR
1M multiply by 50 1CA amount
(2)
1.2.3 Maximum kWh = 400 - 50 M
= 350 kWh CA
1M subtracting 50
F
L1
1CA maximum number
(2)
1.3 1.3.1 % of energy produced by Others
D
= 100% (85,7+5,2+3,2+1,7+0,9+0,9) M 1M subtracting from 100% L1
= 2,4% CA
all values 1CA simplifying. (2)
1.3.2
M
Natural Gas =
3,2 85,7
? 237,006
= 8,85 GWh CA
1M dividing correct values
D
1CA simplification and
L1
answer
NPR
(2)
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MATHEMATICAL LITERACY P1
(EC/JUNE 2021)
1.3.3 Nuclear: Diesel 5,2 : 1,7 RT A
1.3.4 Production from coal = 1 000 000 ?237,006 RT M
= 237 006 000 KWh
1RT correct values
D
1S simplification
L1
(2)
D
1 RT production
L1
1M multiplication by
1 000 000
1CA answer
(3)
[21]
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(EC/JUNE/2021)
MATHEMATICAL LITERACY P1
5
QUESTION 2 [27 MARKS] FINANCE Question Solution 2.1 2.1.1 Number of copies 2A
2.1.2 ANNEXURE C: GRAPH
Explanation/Marks
2A number of copies
(2)
T/L
F L1
COST OF OPTIONS(IN RANDS)
1600 GRAPH FOR THE NUMBER OF COPIES AND COSTS
1400
S
XL
1200
1000
M
800
600
400
200
0
0
100
200
300
400
500
600
700
NUMBER OF COPIES
S
M
XL
1 mark for starting point (0;500) 1 mark any other correct point plotted correctly 1mark for the straight line
F (3) L2
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