Z



z

1. Find the indicated critical value 0.02 =?

Using a table:



This is the left tailed test critical value, with 0.02 prob.

answer is:

-2.054

2. The lengths of pregnancies are normally distributed with a mean of 267 days and a standard deviation of 15 days. A. Find the probability of a pregnancy lasting 307 days or longer. B. If the length of pregnancy is in the lowest 2%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

A. The probability that a pregnancy will last 307 days or longer is ?

A:

z = (x-mu)/sigma

Z = (307-267)/15

Z = 2.66667

Prob(z > 2.66667) from a z table:

0.0038

B:

The z value for the lowest 2% is: -2.054

X = z*sigma + mu

X = -2.054*15 + 267

X = 236.19 days

3. Find the area of the shaded region. The graph depicts the standard normal distribution with mean 0 and standard deviation 1. z=0.13 The area of the shaded region is ?

Prob(z < 0.13)

= 0.5517

4. Assume the readings on the thermometers are normally distributed with a mea of 0 celcius and a standard diviation of 1.00 C. Find the probability that a randomly selected thermometer reads greater than -1.99. What is the probability?

z = (x-mu)/sigma

z = (-1.99-0)/1

= -1.99

Prob(z > -1.99) from the table:

0.9767

................
................

In order to avoid copyright disputes, this page is only a partial summary.

Google Online Preview   Download