Solving Exponential and Logarithmic Equations - University of Waterloo
= log2(2x — 2) 5 — log2(x — 1) Illustrate graphically. Solution (1) (2) 32 o o o x 1) 25 Method 2 — Method 1 = — 30 2(x2 — — 15) —3, but x > 1 _ Therefore So x 5, —3 is an extraneous root). Examples Example 8 Calculate all possible ratios, 3 log5(x + 2y) — log5(y) ................
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