Y =logb x - FRC Precaculus 40S
8.1 Understanding Logarithms
R7
(p. 370-379)
The logarithmic function is the inverse of the exponential function.
Remember, to find the inverse of a function we switch the x and y values and
then solve for y.
Exponential function
y= bx
Inverse function
x = bY
Notice that the y-value is now an exponent.
In order to isolate and manipulate exponents, we must use something called the logarithm function.
y =logb x
where
b base of the log
y the logarithm (the answer) x ----> the argument
Exl: Sketch the graph of y = 2x and its inverse. 1
--
-1
1 2')< X Cf
Z
I 2.. 0
Q.1-k X
If
2.
S-14itck X .41
Note: The equation of the graph of the inverse is y = log2 X
Page 2
Ex2: Express m = 4" in logarithmic form.
109 Li hfl h
Itlypikhvc
Ex3: Express log2 8 = 3 in exponential form.
WE ktow fids
Lx_
fric_tv
Ex4: Evaluate he following expressions:
108 a) log2 16 = x
x
a N.NP61::
b) log2
dcl lr
hol -them
2"
X
0 log3 (-27)
het+ posJal (es to ce_i CU
t \r-AVA4 ?
h 0 soh-)
Thus, logB A = C where A > 0, B> 0, and B I
Note: The base of a logarithms cannot be negative. The argument (A) of a logarithm is always positive.
Page 3
Ex5: Solve the following equations: 1
a) logx 5 =
b) log x = --3 I 0
0 0
e=niti
)e.
Note: When the base is not indicated, this means that there is a base of 10. logx = log10 x
Some Basic Logs to Remember: "Quicksnappers"
a) log 1 = 0
c_x
---
b) logc=
-
c) logc cY =
`0
X
x
2,1
c,
e) C y --
"7:-- CA,_
0 IiN
A--tP
c174
Page 3
Try these; Evaluate
iii) log10 \
1(1
Ex6: Estimate the following value:
1 g 30
C6 n
--a-
OLI
Homework: Page 380 #1-5, 7-10, 13-15
Page 4
8.2 Transformations of Logarithmic Functions
R9
(p. 383-391)
Exl : Sketch the graphs of the functions y = 3x and y = log3 x .
Note that these two functions are inverses of each other.
vo(A. f Eiv k).
10(1 Ab ,
2
Note: The graph of Y = log3 x has a vertical asymptote at x = 0 because x > 0 is a restriction of the argument.
Page 6
Ex2: Sketch the graphs of the following functions on the same Cartesian plane.
a) y = log, x
b) y = log4 x
y = log x d) Y =
Note: All the graphs pass through the point (1,0). The base of the logarithm determines the next point.
Base 2-->(2,l) Base 4 (4,1) Base 10 --> (10,1)
y = log2 x 2Y = x
2 _> (2,1)
Page 6
\90V 5171p
Ex3: Sketch the graph of the function Y = 1,0k5 + 2)-1. (PR 2) down ?
State the domain: Ex>
or E21 ot) )
N
109 5 6A + 2) -
Determine the y-intercept:
y 109 5 (pi 2.) 1
0 B1318 \60/
y lv;
( y a 5.7
)(+2>() -Z ?
ato
t (1 o f
bin( l'Atortrel
Page 8
xt3) ((x-3)
Ex4:
Sketch
the
graph
of
the
function
.3)
=
10 base
3
-- x) + op /
1o? rvtehrerdo- yi\1s.,1.1.31_
3
-2
x c )
3- 1 ') 3 3 -' -3
3 =
x -22'3
Equation of the asymptote:
>< =3
Homework: Page 389 #1, 3-9, 15
IQ33 (3-6) + 1 y 193 3 +- I
Page 9
................
................
In order to avoid copyright disputes, this page is only a partial summary.
To fulfill the demand for quickly locating and searching documents.
It is intelligent file search solution for home and business.
Related download
- solving equations using logs
- get all the a level maths help you need at
- name solve 3e3x 92x 3 2 2 8 11 14 17 20 log3 x
- prop solving notes weebly
- northern york county school district
- petal school district overview
- name date period skills
- logaritmi liceul bratianu
- scanned by camscanner weebly
- condense each expression to a single logarithm algebra 2