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2) use the indicated bin size to construct a frequency table for the set of data. include columns for relative frequency and cumulative frequency. the weekly incomes (in dollars) of 20 college students are shown below. 120,178,90,74,180,215,144,136,240,268,336,85,330,0,115,165,165,305,0,62 use 50-point bins (0-49, 50-99, etc.Interval Frequency Relative Frequency Cumulative Frequency0-49 2 0.1 (10%) 250-99 4 0.2 (20%) 6100-149 4 0.2 (20%) 10150-199 4 0.2 (20%) 14200-249 2 0.1 (10%) 16250-299 1 0.05 (5%) 17300-349 3 0.15(15%) 203)use the empirical method to estimate the probablility. round your answer to 2 decimal places when necessary. you count 60heads when you toss a coin 100 times. if your dont know whether the coin is fair, what is the probablility that the next toss will be heads.Work: 60/100=0.6Answer: 0.64) find the indicated probability. round your answer to 6 decimal places when necessary. when two balanced dice are rolled, there are 36 possible outcomes. what is the probability that the sum of the numbers on the dice is 6 or 9. Work:P(sum=6)=P((1,5)U(2,4)U(3,3)U(4,2)U(5,1))=P(1,5)+…+P(5,1)=5/36P(sum=9)=P((3,6)U(4,5)U(5,4)U(6,3))=P(3,6)+….+P(6,3)=4/36P(sum=6 or sum=9)=P(sum=6)+P(sum=9)= 5/36+4/36=9/36=1/4Answer: 1/45) use that at least once rule to find the indicated probability. find the probability of at least on 3 in 8 rolls of a fair die. WorkP(at least one 3)=1-P(no 3)=1-(5/6)8=0.767Answer: 0.7676) find the expected value. you are given 8 to 1 odds against rolling a sum of 6 with the roll of tow fair dice, meaning you win $8 if your succeed and you lose $1 if you fail. find the expected value (to you ) of the game. Work:P(sum=6)=5/36E(X)= 8(5/36)+(-1)(31/36)=9/36=1/4Answer: 1/47)an insurance policy sells for $710. based on past data, an average of 1 in 70 policyholders will file a $10,000 claim, and average of 1 in 100 policyholders will file a $20,000 claim, and a average of 1 in 400 policyholders will file a $50,000 claim. what is the expected value to the company per policy sold. P(no claim)=1-1/70-1/100-1/400= 1-0.0268=0.9732P(claim=$10,000)=1/70P(claim=$20,000)=1/100P(claim=$50,000)=1/400E(X)=710(0.9732)-10000/70-20000/100-50000/400=223.115Answer: $223.1158)solve the problem. round your answer to 2 decimal places when necessary. in the year 2000, a country with ta pupulation of 108 million had 17,496 traffic fatalities. find the 2000 fatality rate in deaths per 100,000 population. Work:We have to find x where x/100,000 = 17496/108,000,000x = 100,000(17496)/108,000,000 = 16.2Answer: rate is 16.2 deaths per 100,0009) in the year 2000, a u.s city with a population of 1.8 million reported 31,975 births. what was the birth rate in births per 1000 people. solve the problem.Work:We have to find x where x/1,000 = 31,975/1,800,000x = 1,000(31,975)/1,800,000 = 17.76 (rounded to 2 dp)Answer: rate is 17.76 deaths per 1,00010) a basball manager has 11 players of the same ability. how many 9 player starting lineups can he create. Work:11C9=11!/2!9!=55Answer: 5511)there are 10 members on a board of directions. if they must form a subcommittee of 6 members, how many diffrent subcommittees are possible. Work:10C6=10!/4!6!=210Answer: 21012) 8 basketball players are to be selected to play in a special game. the players will be selected from a list of 27 players. if the players are selected randomly, what is the probability that the 8 talles players will be selected.Work:1/27C8= 1/(27!/19!8!)=1/2,220,075 =4.504 x 10-7Answer: 4.504 x 10-7 ................
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