TOPIC 10. CHEMICAL CALCULATIONS IV - solution stoichiometry.
mole of NaCl (= 22.99 + 35.45 g) dissolved in enough water so that the final volume of the solution was 1 litre. Note: The molarity applies to the solute formula. Thus, while the amount of sodium chloride, NaCl, dissolved is 1 mole, there are actually 1 mole of Na+ ions and 1 mole of Cl– ions present in that solution. Similarly, a 1 M ... ................
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