Radicals - Mixed Index
8.7
Radicals - Mixed Index
Knowing that a radical has the same properties as exponents (written as a ratio)
allows us to manipulate radicals in new ways. One thing we are allowed to do is
reduce, not just the radicand, but the index as well. This is shown in the following example.
Example 1.
p
8
x6 y 2
(x6 y 2)
6
8
x y
3
4
Rewrite as raitonal exponent
1
5
Multiply exponents
2
8
Reduce each fraction
1
4
All exponents have denominator of 4, this is our new index
Our Solution
x y
p
4
x3 y
What we have done is reduced our index by dividing the index and all the exponents by the same number (2 in the previous example). If we notice a common
factor in the index and all the exponnets on every factor we can reduce by
dividing by that common factor. This is shown in the next example
Example 2.
¡Ì
a6b9c15
¡Ì
8
a2b3c5
24
Index and all exponents are divisible by 3
Our Solution
We can use the same process when there are coefficients in the problem. We will
first write the coefficient as an exponential expression so we can divide the
exponet by the common factor as well.
Example 3.
¡Ì
9
8m6n3
¡Ì
9 3 6 3
2mn
¡Ì
3
2m2n
Write 8 as 23
Index and all exponents are divisible by 3
Our Solution
We can use a very similar idea to also multiply radicals where the index does not
match. First we will consider an example using rational exponents, then identify
the pattern we can use.
1
Example 4.
¡Ì
¡Ì
3
4
ab2 a2b
2
1
3
2
(ab ) (a b)
1
3
2
3
2
4
a b a b
4
12
8
12
6
12
1
4
1
4
3
12
a b a b
¡Ì
12 4 8 6 3
abab
¡Ì
12 10 11
a b
Rewrite as rational exponents
Multiply exponents
To have one radical need a common denominator, 12
Write under a single radical with common index, 12
Add exponents
Our Solution
To combine the radicals we need a common index (just like the common denominator). We will get a common index by multiplying each index and exponent by
an integer that will allow us to build up to that desired index. This process is
shown in the next example.
Example 5.
¡Ì
¡Ì
4
6
a2b3 a2b
¡Ì
12
a6b9a4b2
¡Ì
12 10 11
a b
Common index is 12.
Multiply first index and exponents by 3, second by 2
Add exponents
Our Solution
Often after combining radicals of mixed index we will need to simplify the
resulting radical.
Example 6.
p
p
5
x3 y 4 3 x2 y
p
15
x9 y 12x10y 5
p
15 19 17
x y
p
xy 15 x4 y 2
Common index: 15.
Multiply first index and exponents by 3, second by 5
Add exponents
Simplify by dividing exponents by index, remainder is left inside
Our Solution
Just as with reducing the index, we will rewrite coefficients as exponential expressions. This will also allow us to use exponent properties to simplify.
Example 7.
p
p
3
4x2 y 4 8xy 3
p
p
3
22x2 y 4 23xy 3
p
12
24x8 y 429x3 y 9
p
12 13 11 13
2 x y
p
2y 12 2x11y
Rewrite 4 as 22 and 8 as 23
Common index: 12.
Multiply first index and exponents by 4, second by 3
Add exponents (even on the 2)
Simplify by dividing exponents by index, remainder is left inside
Our Solution
2
If there is a binomial in the radical then we need to keep that binomial together
through the entire problem.
Example 8.
p
3x(y + z) 3 9x(y + z)2
p
p
3x(y + z) 3 32x(y + z)2
p
6
33x3(y + z)334x2(y + z)4
p
6
37x5(y + z)7
p
3(y + z) 6 3x5(y + z)
p
Rewrite 9 as 32
Common index: 6. Multiply first group by 3, second by 2
Add exponents, keep (y + z) as binomial
Simplify, dividing exponent by index, remainder inside
Our Solution
The same process is used for dividing mixed index as with multilpying mixed
index. The only difference is our final answer can¡¯t have a radical over the denominator.
Example 9.
p
6
x4 y 3z 2
p
8
x7 y 2z
r
24
x16 y 12z 8
x21y 6z 3
p
24
x?5 y 6z 5
r
y 6z 5
x5
r
x7
x7
12
r
12
y 6z 5
x5
12
p
12
!
x7 y 6z 5
x
Common index is 24. Multiply first group by 4, second by 3
Subtract exponents
Negative exponent moves to denominator
Can ¡ät have denominator in radical, need 12x ¡äs, or 7 more
Multiply numerator and denominator by
¡Ì
12
x7
Our Solution
Beginning and Intermediate Algebra by Tyler Wallace is licensed under a Creative Commons
Attribution 3.0 Unported License. ()
3
8.7
Practice - Radicals of Mixed Index
Reduce the following radicals.
p
1) 8 16x4 y 6
3)
5)
p
12
2)
64x4 y 6z 8
4)
p
4
9x2 y 6
q
4
25x3
16x5
p
q
6
16x2
9y 4
6)
15
x9 y 12z 6
p
10
p
64x8 y 4
7)
12
x6 y 9
8)
9)
p
8
8x3 y 6
10)
11)
p
9
8x3 y 6
12)
Combine the following radicals.
¡Ì ¡Ì
13) 3 5 6
35)
15)
¡Ì ¡Ì
x 3 7y
37)
17)
¡Ì ¡Ì
x3 x?2
39)
p
5
41)
19)
21)
23)
p
4
¡Ì
4
¡Ì
x2 y xy
xy 2
2
p
3
2
x2 y
¡Ì
5
2 3
a bc a b c
¡Ì ¡Ì
4
25) a a3
27)
¡Ì
¡Ì
5 2
b b3
29)
xy 3
31)
p
¡Ì
4
33)
p
3
p
3xy 2z 4 9x3 yz 2
9ab3
p
3
p
4
25y 2
16
81x8 y 12
p
p
27a5(b + 1) 3 81a(b + 1)4
p
¡Ì
3
a2
¡Ì
4
a
p
4
x2 y 3
¡Ì
3 xy
¡Ì
¡Ì
5
ab3c
a2b3c?1
43)
p
4
(3x ? 1)3
45)
p
3
(2x + 1)2
p
5
p
5
(3x ? 1)3
(2x + 1)2
¡Ì
¡Ì
3
74 5
¡Ì ¡Ì
16) 3 y 5 3z
14)
x2 y
p
4
9x3 yz 2
4
18)
¡Ì
4
3x
¡Ì
20)
¡Ì
ab
¡Ì
5
y+4
2a2b2
22)
¡Ì
5
24)
p
6
26)
¡Ì
3
28)
¡Ì
4
30)
32)
34)
¡Ì
5
a2b3
¡Ì
6
¡Ì
3 3
a
3
ab
36)
x2 yz 2
38)
x5
40)
2
a
¡Ì
2x3 y 3
4 3 4
abc
a2b
p
5
x2 yz 3
x2
p
¡Ì
¡Ì
4
¡Ì
3
4xy 2
2
ab c
¡Ì
3
8x (y + z)5
x2
p
3
4x2(y + z)2
¡Ì
5
x
¡Ì
5
a4b2
¡Ì
3
42)
p
5
ab2
x3 y 4z 9
p
xy ?2z
44)
p
3
46)
p
4
(5 ? 3x)3
ab
p
3
p
(2 + 5x)2
p
4
(2 + 5x)
p
3
(5 ? 3x)2
Beginning and Intermediate Algebra by Tyler Wallace is licensed under a Creative Commons
Attribution 3.0 Unported License. ()
5
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