Physics - Oak Park Independent



AP Physics 5: Circular and Rotational Motion Name __________________________

A. Circular Motion

1. constant perimeter (tangential) speed: vt = 2πr/T

a. distance = circumference of the circle: 2πr

b. time = time for one revolution: T (period)

2. constant inward (centripetal) acceleration: ac = v2/r

3. centripetal force, Fc = mac = mv2/r

a. turning on a road problems

| v = 2πr/T |

| |

|ac |

| |

| |

| |

|when the road is horizontal: Fc = Ff = μsmg |

|roads are banked in order to reduce the amount of friction (component of|

|the Fg is || to Fc) |

b. horizontal loop problem (mass on a string)

| Ft-x = Fc = mv2/r |

| |

|θ |

|Ft Ft-y = Fg = mg |

| |

|v = 2πr/T |

|Ft = (Fc2 + Fg2)½ |

|tanθ = Fg/Fc (θ is measured from horizontal) |

c. vertical loop problem (mass on a string)

|top: Fnet = Fc = Ft + Fg ∴ Ft = Fc – Fg |

| |

| |

|Fg Ft |

| |

| |

| |

| |

| |

| |

| |

|Fg Ft |

| |

| |

|bottom: Fnet = Fc = Ft – Fg ∴ Ft = Fc + Fg |

|if on a roller coaster: Fn = Ft |

4. Newton's law of universal gravity, Fg = GMm/r2

a. G = 6.67 x 10-11 N•m2/kg2

b. M = mplanet and m = msatellite

c. r is the distance, measured from center to center

d. g = GM/r2

e. Fg = Fc: GMm/r2 = mv2/r ∴ v = (GM/r)½

v = 2πr/T

m Fg = Fg M

r

| |Mass (kg) |Radius (m) |r from Earth (m) |

|Earth |5.98 x 1024 |6.38 x 106 | |

|Moon |7.35 x 1022 |1.74 x 106 |3.84 x 108 |

|Sun |1.99 x 1030 |6.96 x 108 |1.50 x 1011 |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

B. Newton's Laws—Rotation

1. torque, τ = r⊥Fr (tau—Greek letter for t)

point

of

rotation r 90o Fr

a. r = perpendicular distance from axis of rotation to rotating force Fr

b. when r is not perpendicular to Fr, then τ = rFrsinθ

c. torque units are m•N (not N•m—work)

2. First Law: Object remains at rest or uniform rotation as long as no net torque (τnet) acts on it

a. measured as the moment of inertia, I = βmr2

b. β corrects for mass distribution (β = 1 for a hoop)

3. Second Law: Fr = βma (acceleration at the rim)

(Frolling = ma + βma = (1 + β)ma)

4. equilibrium (τnet = 0)

a. no acceleration (velocity can be non-zero)

b. center of mass: rcm = Σ(rimi)/Σmi

rcm Fcm = Fg1 + Fg2

m1 m2

r1 m1g r2 m2g

| τCM = τ1 + τ2 |

|rcm(m1 + m2)g = r1m1g + r2m2g |

|rcm = (r1m1 + r2m2)(m1 + m2) |

c. first condition: all forces act through the center

1. solving first condition problems (general)

|draw free body diagram |

|resolve non-||, non-⊥ forces into || and ⊥ components |

|v = 0: || and ⊥ to horizontal |

|v ≠ 0: || and ⊥ to velocity |

|||: F||A + F||B + F||C + . . . = 0 |

|⊥: F⊥A + F⊥B + F⊥C + . . . = 0 |

|solve for unknown |

2. solving first condition problems (special case)

|draw free body diagram |

|if there are only three forces and two of the forces are ⊥ to each |

|other, then proceed |

|rearrange forces into a tail to tip diagram (vector sum) |

|use trigonometry to solve for unknown sides φ |

|θ + φ = 90o |

|C |

|sinθ = cosφ = B/C B |

|cosθ = sinφ = A/C θ |

|tanθ = B/A, tanφ = A/B A |

d. second condition: forces act away from the center

1. solving center of mass problems

| |

| |

| |

| |

|Fg1 r1 cm r2 Fg2 |

|system is NOT rotating ∴ τ1 + τ2 = 0 |

|τ1 = τ2 → r1F1 = r2F2 → r1m1g = r2m2g ∴ r1m1 = r2m2 |

2. solving two supports problems

| |

|FL m2 FR |

| |

|rR m1 |

|r1 |

|r2 |

| |

|when support bar has mass: assume all of its mass is in its center of |

|gravity (geometric center) |

|assume point of rotation on left end ∴ rL = 0 and τL = 0 |

|τR – τ1 – τ2 = 0 ∴ τR = τ1 + τ2 → rRFR = r1m1g + r2m2g |

|solve for FL: FL + FR = m1g + m2g |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

C. Conservation Laws—Rotation

1. rotational kinetic energy, Kr = ½βmv2 (J)

a. v is the velocity at the rim

b. rolling kinetic energy: Krolling = ½(1 + β)mv2

2. rotational momentum, L = rβmv (kg•m2/s)

a. when τnet = 0, then ΔL = 0

b. change r and/or β will change v

orbiting planet spinning diver

Kepler's Law

(A1 → 2 = A3 → 4)

r1v1 = r2v2 r1β1v1 = r2β2v2

3. mixed linear and rotation motion problems

a. Summary of translational and rotational formulas

|Variable |Translational |Rotational |Rolling |

|force |F = ma |Fr = βma |F = (1 + β)ma |

|momentum |p = mv |L = rβmv |p + L = (1 + rβ)mv |

|kinetic energy |K = ½mv2 |Kr = ½βmv2 |K = ½(1 + β)mv2 |

b. conservation of energy problems

|ball rolling down a ramp m |

|β = 2/5 |

| |

|h |

| |

|How fast is the ball moving when descends h m? |

|Krolling = Ug |

|½(1 + β)mv2 = mgh |

|7/10v2 = gh |

|v = (10/7gh)½ |

|blocks and pulleys |

| |

| |

|μk m2 |

|r2 |

|x β |

| |

| |

| |

|What is the system's speed after m3 descends x m? |

|Ug-3 – Wf = K1 + K2 + K3 |

|m3gx – μkm1gx = ½(m1 + βm2 + m3)v'2 |

|v' = [2(m3 – μkm1)gx/(m1 + βm2 + m3)]½ |

c. conservation of momentum problems

|jumping on a merry-go-round |

| |

|m vm |

| |

|M, rM, βM |

| |

| |

| |

|How fast is the system going after the boy, m, runs at a stationary |

|merry-go-round at velocity, vm and jumps on at the edge? |

|(convert boy's linear motion to rotational motion, where r is the rM and|

|β = 1: L = rMβmvm) |

|Lm + LM = L' |

|rmβmmvm + rMβMMvM = (rmβmm + rMβMM)v' |

|mvm = (mm + βMM)v' |

|v' = mvm/(mm + βMM) |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

D. Simple Harmonic Motion (SHM)

1. oscillating mass on a spring

a. acceleration is NOT constant ∴ kinematic formulas are invalid

b. displacement, velocity and acceleration oscillate between +A and –A, where A = amplitude

1. x = +A, when t = 0 (pictured above)

|time |t = 0 |t = ¼T |t = ½T |t = ¾T |t = T |

|displacement |+A |0 |-A |0 |+A |

|velocity |0 |-vmax |0 |+vmax |0 |

|acceleration |-amax |0 |+amax |0 |-amax |

2. x = 0, when t = 0 (heading downward)

|time |t = 0 |t = ¼T |t = ½T |t = ¾T |t = T |

|displacement |0 |-A |0 |+A |0 |

|velocity |-vmax |0 |+vmax |0 |-vmax |

|acceleration |0 |+amax |0 |-amax |0 |

c. maximum acceleration, amax = A(k/m)

|Steps |Algebra |

|start with |Fs = ma |

|substitute kA for Fs |kA = ma |

|solve for a |amax = A(k/m) |

d. maximum velocity, vmax = A(k/m)½

|Steps |Algebra |

|start with |Us = K |

|substitute ½kA2 for Us and ½mv2 for K |½kA2 = ½mv2 |

|solve for v |vmax = A(k/m)½ |

e. velocity at x, in terms of vmax: vx = vmax[1 – (x2/A2)]½

|Steps |Algebra |

|start with |Kx + USx = Umax |

|substitute for Us and K |½mvx2 + ½kx2 = ½kA2 |

|solve for vx2 |vx2 = (k/m)(A2 – x2) |

|multiply-divide by A2 |vx2 = A2(k/m)[(A2/A2) – (x2/A2)] |

|square root both sides |vx = A(k/m)½[(1 – (x2/A2)]½ |

|substitute vmax for A(k/m)½ |vx = vmax[1 – (x2/A2)]½ |

f. time for one cycle, period, T = 2π(m/k)½

|Steps |Algebra |

|start with |vmax = A(k/m)½ |

|substitute 2πA/T for vmax |2πA/T = A(k/m)½ |

|simplify |2π/T = (k/m)½ |

|solve for T |T = 2π/(k/m)½ |

|substitute (m/k)½ for 1/(k/m)½ |T = 2π(m/k)½ |

g. formulas at midpoint, 0, and extremes, A

| |midpoint |extreme |

|x |0 |xmax = A |

|v |vmax = 2πA/T = -A(k/m)½ |0 |

|a |0 |amax = vmax2/A = -A(k/m) |

|U |0 |Umax = ½kA2 |

|K |Kmax = ½mv2 |0 |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

2. pendulum

[pic]

a. period of the simple pendulum, T = 2π(L/g)½

|Steps |Algebra |

|start with |F = kx |

|substitute mgsinθrad for F |mgsinθrad = kx |

|substitute Lθrad for x |mgsinθrad = kLθrad |

|for small angles sinθrad = θrad |mg = kL |

|solve for k |k = mg/L |

|start with |T = 2π(m/k)½ |

|substitute mg/L for k |T = 2π(m/mg/L)½ |

|simplify |T = 2π(L/g)½ |

b. notice that m cancels out of the equation, so the period only depends on the L and g

3. damped harmonic motion

[pic]

a. amplitude of oscillating spring or swinging pendulum will decrease until it stops—damping

b. damping is due to friction and air resistance

1. forces always oppose direction of velocity

2. damping is enhanced if oscillator is placed in viscous fluid (car shock absorbers)

c. forced damping is accomplished with motors that are programmed to oppose velocity (earthquake protected buildings)

4. resonance

a. object can be set to oscillate by an external force—forced vibration

b. when forced vibration matches natural vibration, then amplitude builds with each vibration—resonance

c. examples

1. child swinging

2. building during an earthquake

3. air inside a musical instrument

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

A. Circular Motion

Centripetal Force Lab

Measure the period of a whirling mass using two techniques, and then vary the tension and radius to see their effects on the period.

a. Collect the following data.

|Control |

|string length, L |0.5 m |

|hanging weight, m1 |100 g |

|stopper mass, m2 | |

|time (10 orbits), t | |

| | | | |

|Double L |Half m1 |

|m1 |100 g |m1 |50 g |

|string length, L |1.0 m |string length, L |0.5 m |

|time (10 orbits), t | |time (10 orbits), t | |

| | | |

| | |Control |Double L |Half m1 |

|T1 | | | | |

|Fg1 | | | | |

|Fg2 | | | | |

|θ | | | | |

|Fc | | | | |

|r | | | | |

|v | | | | |

|T2 | | | | |

|%Δ | | | | |

c. Do the results from this experiment seem reasonable?

|Double L | |

|Half m1 | |

Questions 1-16 Briefly explain your answer.

1. When a tetherball is whirling around the pole, the net force is directed

(A) toward the top of the pole

(B) toward the ground

(C) horizontally away from the pole

(D) horizontally toward the pole

| |

2. You are standing in a bus that makes a sharp left turn. Which of the following is true?

(A) you lean to the left because of centripetal force

(B) you lean to the right because of inertia

(C) you lean straight ahead because of the net force is forward

(D) you lean to the right because of centrifugal force

| |

3. You drive your car too fast around a curve and the car starts to skid. What is the correct description of this situation?

(A) car's engine is not strong enough to keep the car from being pushed out

(B) friction between the tires and the road is not strong enough to keep the car in a circle

(C) car is too heavy to make the turn

(D) none of the above

| |

4. A steel ball is whirling around in a circle on the end of a string, when the string breaks. Which path will it follow?

A B C

| |

5. Two stones A and B have the same mass. They are tied to strings and whirled in horizontal circles. The radius of the circular path for stones A is twice the radius of stone B's path. If the period of motion is the same for both stones, what is the tension in cord A compared to cord B

(A) TA = TB (B) TA = 2TB (C)TA = ½TB

| |

6. A rider in a "barrel of fun" finds herself stuck with her back to the wall as the barrel spins about a vertical axis. Which diagram shows the forces acting on her?

(A) (B) (C) (D)

| |

7. You are on a Ferris wheel moving in a vertical circle. Which is true when you are at the top of the wheel?

(A) Fn < Fg (B) Fn = Fg (C) Fn > Fg

| |

8. You driving along a rural road. Which is true when you are at the lowest point along a dip in the road?

(A) Fn < Fg (B) Fn = Fg (C) Fn > Fg

| |

9. You swing a ball on the end of a string in a vertical circle. Which is true of the centripetal force at the top of the circle?

(A) Fc = Ft + Fg (B) Fc = Ft – Fg (C) Fc = Fg – Ft

| |

10. Which is stronger the Earth's pull on the Moon or the Moon's pull on the Earth?

(A) Earth's pull (B) Moon's pull (C) they are equal

| |

11. If the distance between the Earth and Moon were doubled, then the force of gravity would be

(A) equal (B) 2 x (C) ½ x (D) ¼ x

| |

12. You weigh yourself in Denver at 1 mile above sea level. How would your weight compare to here?

(A) less (B) the same (C) more (D)

| |

13. Satellites A and B are of equal mass. A experiences twice the force of gravity compared to B. What is the ratio of radius A compared to radius B?

(A) 1/2 (B) 1/√2 (C) 1/4 (D) 2/1

| |

14. Is there a net force acting on an astronaut floating in orbit around the Earth while on a space walk?

(A) yes (B) no

| |

15. If you weighed yourself at the equator, would you weigh more or less than at the poles?

(A) less (B) the same (C) more

| |

16. When the Apollo Missions went to the moon they passed a point where the gravitational attractions from the moon and the earth are equal. What is the ratio of the distances to the Moon and Earth where this happened? (mEarth = 100mMoon)

(A) 1/100 (B) 1/10 (C) 10/1 (D) 100/1

| |

17. A car is traveling east on the north side of a circular track. (r = 50 m) takes 16 s to make one lap.

a. Determine

|v | |

|ac | |

|direction ac | |

b. What direction will the car skid on the icy north side?

| |

18. A rock is whirling in a horizontal circle on the end of a 2.0 m string with a 0.50 s period of revolution. Determine

a. What is the direction of centripetal acceleration when the rock is on the north side of the string?

| |

b. What is the rock's velocity?

| |

c. What is the centripetal acceleration?

| |

d. The string breaks when the rock is on the north side of the string. Which way will the rock fly off?

| |

19. The earth is 1.5 x 1011 m from the sun and makes one complete circular orbit in 1 year.

a. What is the period of orbit in seconds?

| |

b. What is the earth’s orbital velocity?

| |

c. What is the centripetal acceleration of the earth toward the sun?

| |

20. A driver of a 1000-kg sports car attempts a turn whose radius of curvature is 50 m on a road where μ = 0.8.

a. What is the fastest that the driver can make the turn?

| |

b. Could the driver make the turn at this speed

(1) with a 2,000-kg SUV? Explain

| |

(2) when the road is wet? Explain

| |

21. A 2-kg mass is moving at 5 m/s in a horizontal circle of radius 1 m at the end of a cord.

a. What is the horizontal component of tension?

| |

b. What is the vertical component of tension?

| |

c. What is the overall tension in the cord?

| |

d. What angle does the cord make with the horizontal?

| |

22. A 2-kg mass is moving at 5 m/s in a vertical circle of radius 1 m at the end of a cord.

a. What is the tension in the cord at the top of the circle?

| |

b. What is the tension in the cord at the bottom?

| |

23. A 1-kg pendulum bob swings back and forth from a 2-m string that can support 15 N of tension without breaking.

a. What is the maximum speed that the bob can reach at the bottom of the swing without breaking the string?

| |

b. What is the maximum height measured from vertical that the bob can reach?

| |

24. How would the force of gravity be affected if the Earth

a. had the same mass but a smaller radius?

|Between Earth and Moon |On the Earth's surface |

| | |

b. had the same radius but a smaller mass?

|Between Earth and Moon |On the Earth's surface |

| | |

25. Determine the acceleration due to gravity on the planet compared to Earth.

|Mass |Radius (x Earth) |Acceleration (x gEarth) |

|m = mEarth |r = rEarth |g |

|m = mEarth |r = 2rEarth | |

|m = mEarth |r = ½rEarth | |

|m = 2mEarth |r = rEarth | |

|m = ½mEarth |r = rEarth | |

26. What is the acceleration due to gravity (g) on Mars?

( m = 6.4 x 1023 kg, r = 3.4 x 106 m)

| |

27. Consider the following changes to earth.

I Increase earth's mass

II Decrease earth's mass

III Increase earth's radius

IV Decrease earth's radius

|Which changes would decrease the acceleration due to gravity| |

|on the earth's surface? | |

|Which changes would increase the acceleration due to gravity| |

|on the earth's surface? | |

|Which changes would decrease the acceleration due to gravity| |

|on the moon? | |

|Which changes would increase the acceleration due to gravity| |

|on the moon? | |

28. What is the acceleration due to gravity (g) on the moon's surface? (refer to astronomical data on the Formula Sheet)

| |

B. Newton's Laws—Rotation

Equilibrium Lab

a. Extend from the table edge a ½-m stick with a 50-g mass at 0 cm and measure the balance point (CM).

50 g

½-m stick |← rr → |← r50 →

table | | |

50 cm 25 cm 0 cm

(1) Collect the following data.

|rr |r50 |ruler mass, mr |

| | | |

(2) Calculate the following from the data.

| |Formula |Calculation |

|mr | | |

|%Δ | | |

b. Extend from the table edge a ½-m stick with 50-g at 40 cm, 10-g at 15 cm and 20-g at 5 cm and measure the balance point (CM).

50 g 10 g 20 g

mr

½-m stick| | | | |

table 50 40 25 15 5 0 cm

(1) Collect the following data.

|center of mass, CM | |

(2) Calculate the following from the data.

| |Formula |Calculation |

|CM | | |

|%Δ | | |

c. Determine the missing equilibrium vector using spring scales and compare the results to the calculated values.

(1) Collect the following data.

| | | | |

|Experiment |Scale A |Scale B |Scale C |

| |( |Force |

|Experiment |1 |2 |3 |

|Ax | | | | |

|Bx | | | | |

|Cx | | | | |

|Ay | | | | |

|By | | | | |

|Cy | | | | |

|C | | | | |

|θ | | | | |

|%Δ | | | | |

d. Explore the relationship between center-of-mass and balance by performing the following.

(1) Stand with your heels and back against a wall and try to bend over and touch your toes. Explain

| |

(2) Stand facing the wall with your toes against the wall and try to stand on your toes. Explain

| |

(3) Rest a meter stick on two fingers. Slowly bring your fingers together. Explain

| |

Questions 29-36 Briefly explain your answer.

29. You are using a wrench to loosen a rusty nut. Which will produce the greatest torque?

A B

C

D

| |

30. It is easier to stay upright on a moving bike compared to a stationary bike because of

(A) Newton's first law (B) Newton's second law

(C) Newton's third law (D) All of Newton's laws

| |

Questions 31-32 Four objects have the same mass and radius.

axis of rotation → ?

F

(A) hollow cylinder, β = 1 (B) solid cylinder, β = 1/2

(C) hollow ball, β = 2/3 (D) solid ball, β = 2/5

31. Which object would have the greatest moment of inertia?

| |

32. Which object would have the greatest rotational acceleration?

| |

33. 3 identical balls descend 3 identical ramps (except for μs). Ball A slides down ramp A (μs = 0), ball B rolls down ramp B (μs = .3) and ball C slides down ramp C (μs = .6). Which is true of their velocities when the reach the end of their ramp?

(A) vA > vB = vC (B) vA > vB > vC (C) vA = vB = vC

| |

34. A 1-kg block is hung at the end of a rod 1-m long. The balance point is 0.25 m from the end holding the block, what is the mass of the rod?

|← 0.25 m →|← 0.25 m →|

center of rod

1 kg

(A) 0.25 kg (B) 0.5 kg (C) 1 kg (D) 2 kg

| |

35. What is the total mass of the mobile? (rods are massless)

1 m 2 m A

B 1 m 3 m 1 kg

(A) 5 kg (B) 6 kg (C) 7 kg (D) 8 kg

| |

36. Consider the two configurations of interlocking blocks on the edge of a table. Which of the following is true?

A B

(A) A tips (B) B tips (C) both tip (D) neither tip

| |

37. Consider the door as viewed from above.

Determine

a. The torque when F1 = 45 N and r1 = 1 m.

| |

b. The force, F2, where r2 = 0.4 m, that will generate the same torque as part a.

| |

38. A 5-kg disk (β = ½) rolls down a 30o incline. Determine

a. The parallel component of Fg.

| |

b. The disk's acceleration at the rim.

| |

39. A 25-kg box rests on the edge of a merry-go-round (r = 2 m).

a. What is the maximum force of friction between the box and merry-go-round (μs = 0.80)?

| |

b. What is the maximum velocity before the box slips off?

| |

c. What is the acceleration of the 200-kg merry-go-round (β = ½) exerting by a 50-N force along the outer rim?

| |

d. How much time will it take to reach the maximum velocity before the box slips off of the merry-go-round?

| |

e. Would this time increase or decrease if μ = 1.0?

| |

40. The 100-N block is stationary and μs = 0.40.

a. What is the minimum weight W?

| |

b. What is the maximum weight W?

| |

41. Consider the stop light, which has a mass of 30 kg. What are the tensions in the two wires?

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

| |

42. Consider the diagram of the chandelier.

Determine

a. F1.

| |

b. F2.

| |

43. A 5-m, 75-kg plank is extended 2 m over the edge of a building. What is the maximum distance that a 25-kg child walks out from the building's

edge without tipping the plank?

| |

44. Consider the diagram of the printing press

on a table. Determine

a. F1.

| |

b. F2.

| |

45. A 50-kg box is anchored to the ceiling and wall by cords.

a. Draw a triangle showing the vector

sum of the three forces acting on the 30o

50-kg box. Ft-w

Ft-c Fg

b. Calculate the tension in the ceiling cord.

| |

c. Calculate the tension in the wall cord.

| |

46. A 2200-kg trailer is attached to a stationary truck.

[pic]

Determine the

a. normal force on the trailer tires at A.

| |

b. normal force on the support B.

| |

47. A plank is placed on two scales, which are then zeroed. A 172-cm-tall student lies on the plank resulting in the reading shown.

[pic]

a. What is the student's mass?

| |

b. What is the distance from her feet to her center-of-mass?

| |

48. A 200-N sign hangs from the end of a 5-m pole, which is held at a 37o angle by a horizontal guy wire.

guy wire

pole

37o

Determine the tension in the guy wire.

| |

C. Conservation Laws—Rotation

1 + β lab

Roll different objects down an incline and calculate the final velocity and (1 + β) for each and compare the calculated values with the ideal values.

a. Collect the following data.

|Ring |Disk |

|height, h | |height, h | |

|distance, d | |distance, d | |

|time, t | |time, t | |

| | |

|height, h | |height, h | |

|distance, d | |distance, d | |

|time, t | |time, t | |

| | | |

| | |Ring |Disk |Ball |Cart |

|v | | | | | |

|1 + β | | | | | |

c. Calculate the percent difference with the ideal values.

| |Formula |Calculation |

| | |Ring |Disk |Ball |Cart |

| |Ideal values |2 |3/2 |7/5 |1 |

|% Δ | | | | | |

49. A hoop, cylinder and sphere roll down a 1-m ramp inclined 30o at the same time that a box slides down a frictionless ramp that is also 1 m long and inclined 30o.

a. Derive a formula for determining the velocity of each object when it reaches the bottom of the ramp.

| |

b. What are the velocities of each when they reach the bottom of the ramp? (1) :

|Hoop (β = 1) | |

|Cylinder (β = 1/2) | |

|Sphere (β = 2/5) | |

|Box: (β = 0) | |

c. What is the order in which they reach the bottom?

| |

50. Determine the velocity of a Yo-Yo (β = ½) that "rolls" down its string a distance of 0.50 m.

| |

51. A marble (β = 2/5) rolls from rest down a ramp and around a loop (radius = 10 m). Determine

A

B

H 10 m

a. the minimum velocity at B.

| |

b. the minimum height H at A.

| |

52. A string is attached to a 1.0-kg block and is wrapped round a pulley (β = ½, m = 2.0 kg). The block is released from rest and accelerates downward while the pulley rotates.

What is the block's velocity after descending 1 m?

| |

53. Two weights (m1 = 0.40 kg, m2 = 0.60 kg) are connected by a cord that hangs from a pulley (β = ½, M = 0.50 kg).

M

m2

1 m

m1

What is the velocity of m2 after descending 1 m?

| |

54. A string attached to a 20-kg block resting on a table passes over a pulley (β = ½, m = 4 kg) and attaches to a 14-kg mass hanging over the edge of the table. The 20-kg box slide along the table (μ = 0.25) while the 14-kg mass descends 1 m.

20 kg

1 m

14 kg

What is the hanging mass' velocity after descending 1 m?

| |

55. What is the angular momentum of a 0.2-kg ball traveling at 9 m/s on the end of a string in a circle of radius 1 m?

| |

56. What is the angular momentum of Earth, m = 6.0 x 1024 kg?

a. about its axis of rotation (β = 2/5, rplanet = 6.4 x 106 m)

| |

b. in its orbit around the Sun (β = 1, rorbit = 1.5 x 1011 m)

| |

57. Rotation formulas can be derived by replacing L instead of p and I instead of m. since K = p2/2m, then Kr = L2/2I.

a. Prove Kr = ½βmv2 = L2/2I using L = rβmv and I = βmr2.

| |

b. A 10-N force accelerates the rim of a stationary flywheel (β = ½, m = 25 kg, r = 0.50 m) for 60 s. Determine the

(1) moment of inertia.

| |

(2) velocity.

| |

(3) angular momentum,

| |

(4) kinetic energy.

| |

58. Halley's comet follows an elliptical orbit, where its closest approach to the sun is 8.9 x 1010 m and its farthest distance is 5.3 x 1012 m. How many times faster does the comet travel at its fastest compared to its slowest?

| |

59. The rim of a disk (β = ½, m = M, r = R) rotates at a velocity, V. A ring (β = 1, m = M, r = R) is dropped on top of the disk.

a. Calculate Ltotal before the ring is dropped on the disk.

| |

b. Calculate the velocity after the ring is dropped.

| |

60. A child (m = 42 kg) runs toward a stationary merry-go-round (β = ½, m = 180 kg, r = 1.2 m) along a tangent at 3 m/s. The child jumps on the merry-go-round and sets it rotating.

3 m/s

β = ½

42 kg 180 kg

1.2 m

What is the speed of the merry-go-round after the child jumps on?

| |

61. Tarzan (100 kg) is on a ledge that is 20 m above Jane (45 kg), who is trapped on a lower ledge. Tarzan grabs a long vine and swings down from the ledge and grabs Jane, who is stationary. The two swing over to a rock ledge on the other side of the river gorge that is 10 m higher than the rock ledge where Jane is trapped. Assuming the vine is long enough, can Tarzan and Jane reach the other side?

T

J

a. Calculate Tarzan's velocity when he grabs Jane.

| |

b. Calculate the velocity after Tarzan grabs Jane.

| |

c. Calculate how high Tarzan swings to the other side.

| |

d. Did Tarzan and Jane make it?

| |

e. What could Tarzan have done to save Jane?

| |

f. How high would Tarzan have to start to save Jane?

| |

g. What minimum initial velocity would Tarzan need to save Jane starting from the original ledge?

| |

62. A 1-kg, disk (β = ½) is placed on a 2-m ramp where the top is 1 m above the base of the ramp. The disk is placed at the top and rolls down to the base of the ramp.

a. What is the disk's velocity when reaches the base?

| |

b. How much time does it take the disk to travel the 2 m?

| |

c. Predict how the following alterations would change the disk's velocity at and time to reach the base of ramp?

|Alteration | Final Velocity |Time |

|A 2.0-kg disk is used | | |

|A 1.0-kg ring (β = 1) is used | | |

|A 3-m ramp is used, but h = 1 m | | |

63. A string attached to a 10-kg box resting on a table passes over a pulley (β = ½, m = 1 kg) and attaches to a 5-kg mass hanging over the edge of the table. The 10-kg box slide 1 m along the table (μ = 0.3) while the 5-kg mass descends.

1 m

a. How much kinetic energy does the system have at the point where the 5-kg mass has descended 1 m?

| |

b. What is the maximum velocity of the system?

| |

64. Halley's Comet has a velocity of 3.88 x 104 m/s when it is 8.9 x 1010 m from the sun. How fast is it traveling when it is 5.3 x 1012 m from the sun?

| |

65. What is the angular momentum of the Moon?

(m = 7.35 x 1022 kg, rmoon = 1.74 x 106 m, rorbit = 3.84 x 108 m, Torbit = Trotation = 2.42 x 106 s)

a. about its axis of rotation (β = 2/5)

| |

b. in its orbit around the Earth (β = 1)

| |

66. A student (m = 75 kg) runs at 5 m/s tangentially toward a stationary merry-go-round (β = ½, m = 150 kg, r = 2 m), jumps on the merry-go-round and sets it rotating.

a. What is the velocity of the student after he jumps on to the merry-go-round?

| |

b. What is the percentage of the student's kinetic energy that is lost in the "collision" with the merry-go-round?

| |

67. A 2-kg block and a 1-kg sphere hang from 2-m strings. The sphere is raised to a horizontal position and swings toward the block and collides with it.

a. What is the sphere's velocity before the collision?

| |

Assume that the collision is inelastic.

b. What is the sphere-block's velocity after the collision?

| |

c. What is the maximum height reached after the collision?

| |

d. What is the maximum height reached after the collision if the block and sphere exchange positions initially?

| |

The sphere is raised to a horizontal position initially and then collides elastically with the block.

e. What are the velocities of the block and sphere after the collision?

| |

f. What are the maximum heights reached by the block and sphere?

| |

g. Was potential energy conserved after the collision?

| |

D. Simple Harmonic Motion (SHM)

Simple Harmonic Motion Lab

a. Measure the length L and time t for 10 oscillations of a spring with different hanging masses m, determine k using two methods and compare the results.

(1) Collect the following data.

|m (kg) |0 |0.10 |0.20 |0.30 |0.40 |0.50 |

|L (m) | | | | | | |

|t (s) | | | | | | |

(2) Calculate the following using the data.

| |Formula |Calculation |

| |added mass |0.10 |

|T | | |

(3) Calculate the percent difference between the two values of k.

| |

b. Measure the pendulum period for different releasing angles θ and seeing which angles give the most ideal values for T.

(1) Collect the following data.

|L (m) | |

|θ (o) |10o |20o |30o |40o |50o |60o |

|t (s) | | | | | | |

| | | | | | | |

| | | | | | | |

| | | | | | | |

(2) Calculate the following from the data.

| |Formula |Calculation |

| |

(4) Which angles produce values for T that are closest to the one based on the pendulum's length?

| |

Questions 68-85 Briefly explain your answer.

Questions 68-71 A spring bob in SHM has amplitude A and period T.

68. What is the total distance traveled by the bob after time T?

(A) 0 (B) ½A (C) 2A (D) 4A

| |

69. What is the total displacement after time T?

(A) 0 (B) ½A (C) 2A (D) 4A

| |

70. How long does it take the bob to travel a distance of 6A?

(A) ½T (B) ¾T (C) 5/4T (D) 3/2T

| |

71. At what point in the motion is v = 0 and a = 0 simultaneously?

(A) x = 0 (B) 0 < x < A(C) x = A (D) no point

| |

Questions 72-73 A single spring stretches a distance of 60 cm with an applied force of 1 N. A second identical spring is attached to the first.

72. How much force is needed to stretch the two spring 60 cm if the second spring is attached parallel to the first?

(A) ½ N (B) 1 N (C) 2 N (D) 4 N

| |

73. How much force is needed to stretch the two spring 60 cm if the second spring is attached in series to the first?

(A) ½ N (B) 1 N (C) 2 N (D) 4 N

| |

74. A mass on the end of a spring oscillates in simple harmonic motion with amplitude A. If the mass doubles but the amplitude is not changed, what happen to the total energy?

(A) decrease (B) no change (C) increase (D)

| |

75. If the amplitude of a simple harmonic oscillator is doubled, which quantity will change the most?

(A) T (B) v (C) a (D) K + U

| |

Questions 76-77 An air-track glider with springs attached at each end oscillates with period T.

76. If the mass of the glider is doubled, what is the new period?

(A) T/√2 (B) T (C) √2T (D) 2T

| |

77. If identical springs are added in parallel to each side of the original mass, what is the new period?

(A) T/√2 (B) T (C) √2T (D) 2T

| |

78. Which will change the period of oscillation of a mass hanging on the end of a spring?

(A) move the oscillator to an elevator rising at constant speed

(B) move the oscillator to an elevator accelerating up

(C) move the oscillator to the Moon

(D) none of the above

| |

Questions 79-80 Consider the periods of pendulums A and B,

79. Which period is greater when LA = LB, but mA > mB?

(A) A (B) B (C) the same

| |

80. Which period is greater when mA = mB, but LA > LB?

(A) A (B) B (C) the same

| |

81. A grandfather clock has a weight at the bottom of the pendulum that can be moved up or down. If the clock is running slow, should the weight be moved up or down?

(A) up (B) down (C) neither will work (D)

| |

82. Which will decrease the period of a pendulum?

(A) move the pendulum to an elevator rising at constant speed

(B) move the pendulum to an elevator accelerating up

(C) move the pendulum to an elevator accelerating down

(D) move the pendulum to the Moon

| |

83. After a pendulum starts swinging, its amplitude gradually decreases with time because of friction. What happens to the period of the pendulum during this time

(A) decreases (B) no change (C) increases

| |

84. When you sit on a swing, the period of oscillation is T1. When you stand on the same swing, the period of oscillation is T2. Which is true?

(A) T1 < T2 (B) T1 = T2 (C) T1 > T2

| |

85. When a 50 kg person sits on a swing, the period of oscillation is T1, when a 100 kg person sits on the same swing, the period of oscillation is T2. Which is true?

(A) T1 < T2 (B) T1 = T2 (C) T1 > T2

| |

86. Consider the diagram in your notes of one cycle of SHM.

a. Determine the time in terms of T for each situation.

| |Maximum up |Zero |Maximum down |

|Acceleration | | | |

|Velocity | | | |

b. Determine the following when m = 1 kg, k = 100 N/m and A = 0.1 m.

(1) maximum acceleration

| |

(2) maximum velocity

| |

(3) period

| |

(4) maximum kinetic energy

| |

(5) maximum potential energy

| |

(6) velocity when x = 0.05 m

| |

c. Graph the potential energy (----), kinetic energy (•••) and total energy (––) for one complete oscillation.

|0.5 J | | | | |

| | | | | |

|0 J | | | | |

| |¼T |¾T |

d. complete the following chart (x = +A at t = 0 s)

|t |¼T |½T |¾T |1T |

|x | | | | |

|v | | | | |

|a | | | | |

|F | | | | |

e. How do the following change if the amplitude is 0.2 m?

|Max acceleration |Max velocity |Period |

| | | |

87. A 1-kg ball on the end of a 1-m string is set in motion by pulling the ball out so that it is raised 0.015 m. Determine

a. the maximum speed

| |

b. the period of oscillation.

| |

c. What would the period be with the following changes?

|m = 4 kg |L = 4 m |g = 40 m/s2 |

| | | |

88. Consider the diagram of one cycle of SHM.

[pic]

a. Determine the time (in terms of T) for each of the following.

| |Maximum up |Zero |Maximum down |

|Acceleration | | | |

|Velocity | | | |

b. Determine the following when m = 1 kg, k = 100 N/m and A = 0.25 m.

(1) maximum acceleration

| |

(2) maximum velocity

| |

(3) period

| |

(4) maximum kinetic energy

| |

(5) maximum potential energy

| |

(6) velocity when x = 0.20 m

| |

c. Graph the potential energy, kinetic energy and total energy for one complete oscillation.

|3 J | | | | |

| | | | | |

|0 J | | | | |

| |¼T |¾T |

d. complete the following chart (x = 0 at t = 0 s)

|t |¼T |½T |¾T |1T |

|x | | | | |

|v | | | | |

|a | | | | |

|F | | | | |

e. Determine the following values when A = 0.50 m.

(1) maximum acceleration

| |

(2) maximum velocity

| |

(3) period

| |

89. A 1-kg ball swings from the ceiling on the end of a 2-m string. The ball starts its swing from a position that is

0.2 m above its lowest point.

a. What is the maximum speed of the ball?

| |

b. What is the period of oscillation for the pendulum?

| |

Practice Multiple Choice (No calculator)

Briefly explain why the answer is correct in the space provided.

|1 |

2. A racing car is moving around the circular track of radius 300 m. At the instant when the car's velocity is directed due east, its acceleration is 3 m/s2 directed due south. When viewed from above, the car is moving

(A) clockwise at 30 m/s (B) counterclockwise at 30 m/s

(C) clockwise at 10 m/s d. counterclockwise at 10 m/s

| |

3. The disk is rotating counterclockwise when the ball is projected outward at the instant the disk is in the position shown.

Which of the following best shows the subsequent direction of the ball relative to the ground?

(A) 〈 (B) ™ (C) ⋄ (D) ⎛

| |

4. A person weighing 800 N on earth travels to another planet with the same mass as earth, but twice the radius. The person's weight on this other planet is most nearly

(A) 200 N (B) 400 N (C) 800 N (D) 1600 N

| |

5. A ball is released from rest at position P swings through position Q then to position R where the string is again horizontal.

What are the directions of the ball's acceleration at positions, Q and R?

Q R Q R

(A) ® ® (B) ® ⋄

(C) 〈 ® (D) 〈 ⇓

| |

6. A 5-kg sphere is connected to a 10-kg sphere by a rod.

[pic]

The center of mass is closest to

(A) A (B) B (C) C (D) D

| |

7. A ball attached to a string is moved at constant speed in a horizontal circular path. A target is located near the path of the ball as shown in the diagram.

[pic]

At which point along the ball's path should the string be released, if the ball is to hit the target?

(A) A (B) B (C) C (D) D

| |

8. The diagram shows a 5.0-kg bucket of water being swung in a horizontal circle of 0.70-m radius at a constant speed of 2.0 m/s.

The centripetal force on the bucket of water is

(A) 5.7 N (B) 29 N (C) 14 N (D) 200 N

| |

Questions 9-10 refer to a ball that is tossed straight up from the surface of a small asteroid with no atmosphere. The ball rises to a height equal to the asteroid's radius and then falls straight down toward the surface of the asteroid.

9. What forces act on the ball while it is on the way up?

(A) a decreasing gravitational force that acts downward

(B) an increasing gravitational force that acts downward

(C) a constant gravitational force that acts downward

(D) a constant gravitational force that acts downward and a decreasing force that acts upward

| |

10. The acceleration of the ball at the top of its path is

(A) at its maximum value for the ball's flight

(B) equal to the acceleration at the surface

(C) equal to one-half the acceleration at the surface

(D) equal to one-fourth the acceleration at the surface

| |

Questions 11-12 A 125-N board is 4 m long and is supported by vertical chains at each end. A person weighing 500 N is sitting on the board. The tension in the right chain is 250 N.

11. What is the tension in the left chain?

(A) 250 N (B) 375 N (C) 500 N (D) 625 N

| |

12. How far from the left end of the board is the person sitting?

(A) 0.4 m (B) 1.5 m (C) 2 m (D) 2.5 m

| |

13. A square piece of plywood on a horizontal tabletop is subjected to the two horizontal forces shown above.

[pic]

Where should a third force of magnitude 5 N be applied to put the piece of plywood into equilibrium?

| A B |

|C |

| | | | |

| D | | | |

| |

| |

Questions 14-15 A 100-N weight is suspended by two cords.

[pic]

14. The tension in the ceiling cord is

(A) 50 N (B) 100 N (C) 170 N (D) 200 N

| |

15. The tension in the wall cord is

(A) 50 N (B) 100 N (C) 170 N (D) 200 N

| |

16. The diagram represents two satellites of equal mass, A and B, in circular orbits around a planet.

[pic]

Comparing the gravitational force between satellite and planet, B's gravitational force compared to A's is

(A) half as great (B) twice as great

(C) one-fourth as great (D) four times as great

| |

17. The radius of the earth is approximately 6,000 km. The acceleration of an astronaut in a perfectly circular orbit 6,000 km above the earth would be most nearly

(A) 0 m/s2 (B) 2.5 m/s2 (C) 5 m/s2 (D) 10 m/s2

| |

18. A 5-m, 100-kg plank rests on a ledge with 2 m extended out.

[pic]

How far can a 50-kg person walk out on the plank past the edge of the building before the plank just begins to tip?

(A) ½ m (B) 1 m (C) 3/2 m (D) 2 m

| |

19. The system is balanced when hanging by the rope.

[pic]

What is the mass of the fish?

(A) 1.5 kg (B) 2 kg (C) 3 kg (D) 6 kg

| |

20. A ball attached to a string is whirled around in a horizontal circle with radius r, speed v and tension T. If the radius is increased to 4r and the tension remains the same, then the speed of the ball is

(A) ¼v (B) ½v (C) v (D) 2v

| |

21. A 0.4-kg object swings on the end of a string. At the bottom of the swing, the tension in the string is 6 N. What is the centripetal force acting on the object at the bottom of the swing?

(A) 4 N (B) 2 N (C) 6 N (D) 10 N

| |

22. Two wheels, fixed to each other, are free to rotate about a frictionless axis perpendicular to the page. Four forces are exerted tangentially to the rims of the wheels.

[pic]

The net torque on the system about the axis is

(A) zero (B) FR (C) 2FR (D) 5FR

| |

23. Mars has a mass 1/10 that of Earth and a diameter 1/2 that of Earth. The acceleration of a falling body near the surface of Mars is most nearly

(A) g/5 (B) 2g/5 (C) g/2 (D) g

| |

24. A satellite of mass m and speed v moves in a stable, circular orbit around a planet of mass M. What is the radius of the satellite’s orbit?

(A) GM/mv (B) Gv/mM

(C) GM/v2 (D) GmM/v

| |

25. A wheel of radius R is mounted on an axle so that the wheel is in a vertical plane. Three small objects having masses m, M, and 2M, respectively, are mounted on the rim.

[pic]

What is m in terms of M when the wheel is stationary?

(A) 1/2 M (B) M (C) 3/2 M (D) 2 M

| |

26. In each case the unknown mass m is balanced by a known mass M1 or M2.

[pic]

What is the value of m in terms of the known masses?

(A) M1 + M2 (B) (M1 + M2)/2

(C) M1M2 (D) (M1M2)½

| |

27. An asteroid moves in an elliptic orbit with the Sun at one focus.

Which of the following increases as the asteroid moves from point P in its orbit to point Q?

(A) Speed (B) Angular momentum

(C) Total energy (D) Potential energy

| |

28. A satellite S is in an elliptical orbit around a planet P with r1 and r2 being its closest and farthest distances, respectively, from the center of the planet. If the satellite has a speed v1 at its closest distance, what is its speed at its farthest distance?

(A) (r1/r2)v1 (B) (r2/r1)v1

(C) (r2 – r1)v1 (D) ½(r1 + r2)v1

| |

29. A satellite of mass M moves in a circular orbit of radius R at a constant speed v. Which must be true?

I. The net force on the satellite is equal to Mv2/R and is directed toward the center of the orbit.

II. The net work done on the satellite by gravity in one revolution is zero.

III. The angular momentum of the satellite is a constant.

(A) I only (B) III only (C) I and II (D) I, II, and III

| |

Questions 30-31 A sphere of mass M, radius R, and β = 2/5, is released from rest at the top of an inclined plane of height h.

[pic]

30. If the plane is frictionless, what is the speed of the center of mass of the sphere at the bottom of the incline?

(A) (2gh)½ (B) 2Mgh (C) 2MghR2 (D) 5gh

| |

31. If the plane has friction so that the sphere rolls without slipping, what is the speed at the bottom of the incline?

(A) (2gh)½ (B) 2Mgh (C) 2MghR2 (D) (10gh/7)½

| |

32. For which motions is there a variable force involved?

(A) Constant speed in a straight line

(B) Simple harmonic motion

(C) Constant speed in a circle

(D) Constant acceleration in a straight line

| |

33. A particle of mass, m, moves with a constant speed v along the dashed line y = a.

When the x-coordinate of the particle is xo, the magnitude of the angular momentum of the particle with respect to the origin of the system is

(A) zero (B) mva (C) mvxo (D) mv(vo2 + a2)½

| |

Questions 34-38 A block oscillates without friction on the end of a spring. The minimum and maximum lengths of the spring as it oscillates are, respectively, xmin and xmax.

[pic]

The graphs below can represent quantities associated with the oscillation as functions of the length x of the spring.

(A) (B)

(C) (D)

34. Which graph can best represent the total mechanical energy of the block-spring system as a function of x?

| |

35. Which graph can best represent the kinetic energy of the block as a function of x?

| |

36. Which graph can best represent the potential energy of the block as a function of x?

| |

37. Which graph can best represent the acceleration of the block as a function of x?

| |

38. Which graph can best represent the velocity of the block as a function of x?

| |

39. A block attached to the lower end of a vertical spring oscillates up and down. The period of oscillation depends on which of the following?

I. Mass of the block

II. Amplitude of the oscillation

III. Spring constant

(A) I only (B) II only (C) III only (D) I and III only

| |

40. When a 1-kg bob is attached to a spring, the period of oscillation is 2 s. What is the period of oscillation when a 2-kg bob is attached to the same spring?

(A) 0.5 s (B) 1.0 s (C) 1.4 s (D) 2.8 s

| |

41. A pendulum and a mass hanging on a spring both have a period of 1 s on earth. They are taken to planet X, which has twice the gravitational acceleration g as earth. Which is true about the periods of the two objects on planet X compared to their periods on earth?

(A) Both are shorter.

(B) Both are longer.

(C) The pendulum is longer and the spring is the same.

(D) The pendulum is shorter and the spring is the same.

| |

42. The graph is of the displacement x versus time t for a particle in simple harmonic motion with a period of 4 s.

[pic]

Which graph shows the potential energy of the particle as a function of time t for one cycle of motion?

(A) (B) (C) (D)

| |

Questions 43-44 Two identical springs are hung from a horizontal support. When a 1.2-kg block is suspended from the pair of springs, each spring is stretched an additional 0.15 m.

43. The spring constant of each spring is most nearly

(A) 40 N/m (B) 48 N/m (C) 60 N/m (D) 80 N/m

| |

44. In which of the following cases will the block have the same oscillating amplitude and maximum velocity?

I. The block is hung from one of the two springs.

II. The block is hung from the two springs connected one on top of the other.

III. A 0.6-kg mass is attached to the block.

(A) None (B) III only (C) I and II (D) II and III

| |

45. A ball is dropped from a height of 10 m onto a hard surface so that the collision at the surface may be assumed elastic. Under such conditions the motion of the ball is

(A) simple harmonic with a period of about 1.4 s

(B) simple harmonic with a period of about 2.8 s

(C) simple harmonic with an amplitude of 5 m

(D) periodic but not simple harmonic

| |

46. An object swings on the end of a cord as a simple pendulum with period T. Another object oscillates up and down on the end of a vertical spring, also with period T. If the masses of both objects are doubled, what are the new values for the periods?

Pendulum Spring Pendulum Spring

(A) T/√2 √2T (B) T √2T

(C) T T (D) √2T T

| |

47. When a mass m is hung on a spring, the spring stretches a distance d. If the mass is then set oscillating on the spring, the period of oscillation is proportional to

(A) (d/g)½ (B) (g/d)½ (C) (d/mg)½ (D) (m2g/d)½

| |

48. A 3-kg block is hung from a spring, causing it to stretch 12 cm at equilibrium. The 3-kg block is then replaced by a 4-kg block, and the new block is released from the spring when it is unstretched. How far will the 4-kg block fall before its direction is reversed?

(A) 9 cm (B) 18 cm (C) 24 cm (D) 32 cm

| |

49. A spring is fixed to the wall at one end. A block of mass M attached to the other end of the spring oscillates with amplitude A on a frictionless, horizontal surface. The maximum speed of the block is v.

[pic]

The spring constant is

(A) Mg/A (B) Mgv/2A (C) Mv2/2A (D) M(v/A)2

| |

50. A sphere of mass m1 is attached to a spring. A second sphere of mass m2 is suspended from a string of length L, If both spheres have the same period of oscillation, which of the following is an expression for the spring constant?

(A) L/m1g (B) g/m2L (C) m1L/g (D) m1g/L

| |

Practice Free Response

1. A roller coaster ride at an amusement park lifts a car of mass 700 kg to point A at a height of 90 m above the lowest point on the track, as shown above. The car starts from rest at point A, rolls with negligible friction down the incline and follows the track around a loop of radius 20 m. Point B, the highest point on the loop, is at a height of 50 m above the lowest point on the track.

P

a. (1) Indicate on the figure the point P at which the maximum speed of the car is attained.

(2) Calculate the value vmax of this maximum speed.

| |

b. Calculate the speed vB of the car at point B.

| |

c. (1) Draw and label vectors to represent the forces acting on the car when it is upside down at point B.

| |

| |

| |

| |

| |

(2) Calculate all the forces identified in (c1).

| |

2. A string attached to a 20-kg block resting on a table passes over a pulley (β = ½, m = 10 kg) and attaches to a 10-kg mass hanging over the edge of the table. The 20-kg box slide along the table (μ = 0.30) while the 10-kg mass descends 2 m.

2 m

Determine the

a. force of friction on the 20-kg block as it slides.

| |

b. force of gravity on the 10 kg mass.

| |

c. net force rotating the pulley.

| |

d. acceleration of the pulley at the rim.

| |

e. velocity when the system has moved 2 m.

| |

f. loss of potential energy as the 10-kg mass falls 2 m.

| |

g. work done by friction as the 20-kg block slides 2 m.

| |

h. velocity of the system

| |

3. A 0.5-kg hoop (β = 1) rolls from rest at the top of the ramp of length L = 2 m and angle θ = 30o. The table height H = 1 m.

a. Determine the potential energy of the hoop at the top of the ramp, where Ug = 0 at the floor.

| |

b. The hoop rolls down the ramp and then onto the floor. Determine the hoop's

(1) speed at the bottom of the ramp.

| |

(2) speed just before it hits the floor.

| |

(3) translational kinetic energy before it hits the floor.

| |

(4) percentage of total energy that is rotational kinetic energy just before it hits the floor.

| |

c. The hoop is replaced by a 0.5 kg solid sphere (β = 2/5), which rolls down the ramp and then onto the floor. Determine the sphere's

(1) speed at the bottom of the ramp.

| |

(2) speed just before it hits the floor.

| |

(3) translational kinetic energy before it hits the floor.

| |

(4) percentage of total energy that is rotational kinetic energy just before it hits the floor.

| |

d. Comparing a hoop (β = 1), disk (β = ½) and a sphere (β = 2/5) just before it lands on the floor, which would

(1) have the greatest % rotational kinetic energy?

| |

(2) land furthest from the base of the table?

| |

(3) have the most kinetic energy just before it landed?

| |

4. The graph shows a system in simple harmonic motion.

[pic]

Complete the chart with either +, 0, or –.

|t |0 s |1 s |2 s |3 s |

|x (m) | | | | |

|v (m/s) | | | | |

|a (m/s2) | | | | |

|F (N) | | | | |

|U (J) | | | | |

|K (J) | | | | |

6. A 3.0 kg bob swings on the end of a 1.0 m string. The potential energy U of the object as a function of distance x from its equilibrium position is shown. This particular object has a total energy E of 0.4 J.

[pic]

a. What is the bob's potential energy when its displacement is +4 cm from its equilibrium position?

| |

b. What is the greatest distance x for the pendulum bob? Explain your reasoning.

| |

c. How much time does it take the pendulum to go from the greatest +x to the greatest –x?

| |

d. Determine the bob's kinetic energy when x = -7 cm.

| |

e. What is the object's speed at x = 0?

| |

5. The mobile is in equilibrium. Object B has mass of 27 g.

[pic]

Determine the mass of objects A, C and D. (Neglect the weights of the crossbars.)

| |

7. The cart of mass m with four wheels of mass m/4 and β = ½ is released from rest and rolls from the top of a ramp of height h. After rolling down the ramp and across the horizontal surface, the cart collides and sticks with a bumper of mass 3m attached to a spring, which has a spring constant k.

[pic]

Given: m = 1 kg, h = 0.50 m, k = 250 N/m, determine

a. the potential energy of the cart at the top of the ramp.

| |

b. the speed of the cart at the bottom of the ramp.

| |

c. the carts translational kinetic energy just before the collision.

| |

d. the speed of the cart just after the collision.

| |

e. the translational kinetic energy of the cart and bumper just after the collision.

| |

f. the amount that the spring is compressed.

| |

-----------------------

m3

m1

m1

m2

Physics

is Phun

50 kg

................
................

In order to avoid copyright disputes, this page is only a partial summary.

Google Online Preview   Download