Ms. Westendorf's Physical Science - Home



Potential EnergyDO YOUR WORK ON A SEPARATE SHEET OF PAPER. ?SHOW YOUR WORK AND INCLUDE UNITS!1. Define potential energy.Energy due to position.2. ?What is the formula for potential energy?GPE = mgh3. ?What unit is used for potential energy? ?Joules – 1 N x m4. ?Which has more potential energy:a. A 25 kg mass or a 30 kg mass at the top of a hill.30 kg massb. A car at the top of the hill or the bottom of the hill.car at the top of the hillc. A plane on the ground or a plane in the air.plane in the aird. A full plane or an empty plane (both are flying at the same height)full plane5. ?John has an object suspended in air. ?It has a mass of 50 kilograms and is 50 meters above the ground. ?Calculate the object’s potential energy.GPE = mghGPE = ? Jm = 50 kgg = 9.8 m/s2h = 50 mGPE = 50 kg x 9.8 m/s2 x 50 mGPE = 24,500 J6. ?Ms. Westendorf drops an object from 10 meters. ?She knows it did 50 J of work. ?What is the mass of the object?GPE = mghGPE = 50 Jm = ? kgg = 9.8 m/s2h = 10 m50 J = m x 9.8 m/s2 x 10 m50 J = m x 98m = 0.51 kg7. ?Brian has an object suspended in air. ?It has a mass of 100kg and is 25 meters off the ground. ?What is the object’s potential energy?GPE = mghGPE = ? Jm = 100 kgg = 9.8 m/s2h = 25 mGPE = 100 kg x 9.8 m/s2 x 25 mGPE = 24,500 J8. ?The mass of a rock is 1220 kg. It had 400 J of potential energy before it rolled down a hill. ?Calculate the height of the hill.GPE = mghGPE = 400 Jm = 1220 kgg = 9.8 m/s2h = ? m400 J = 1220 kg x 9.8 m/s2 x h400 J = 11,956 x hh = 0.033 m ................
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