PHYSICAL SCIENCES Grade 12 TERM 3 RESOURCE PACK
[Pages:146]PHYSICAL SCIENCES Grade 12
TERM 3
RESOURCE
PACK
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Contents
Worksheets
3
Topic 10: Electric Circuits
4
Topic 11: Electrodynamics
17
Topic 12: Optical Phenomena and Properties of Matter
32
Topic 13: Electrochemistry
43
Topic 14: The Chemical Industry
63
Formal Experiment: Electric Circuits
75
Technical Instructions
76
Learner's Worksheet
79
Marking Guidelines
85
Assessments91
Topic 10: Electric Circuits
92
Topic 11: Electrodynamics
108
Topic 12: Optical Phenomena and Properties of Matter
119
Topic 13: Electrochemistry
131
Topic 14: The Chemical Industry
140
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WORKSHEETS
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RESOURCE PACK
TOPIC 10: Electric Circuits
WORKSHEET QUESTIONS
TOTAL: 62 MARKS
1. Learners conduct an investigation to determine the emf and internal resistance (r) of the battery. They set up a circuit as shown in the diagram below and measure the potential difference using the voltmeter for different currents in the circuit.
r
A
V
The results obtained are shown in the graph below.
Graph of potential difference versus current
1,5
Potential difference (V)
1,0
0,5
0
0
0,5
1,0
Current (A)
1.1 Use the graph to determine the emf of the battery.
(1)
1.2 Calculate the gradient of the graph.
(3)
1.3 What physical property is represented by the magnitude of the gradient of the graph?(2)
4Grade 12 Physical Sciences
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WORKSHEETS
TOPIC 10
TOPIC 10: ELECTRIC CIRCUITS
1.4 How does the voltmeter reading change as the ammeter reading increases? Write
down INCREASES, DECREASES or REMAINS UNCHANGED. Use the formula
emf = I(R + r) to explain the answer.
(3)
2. The battery in the following circuit has an emf of 24 V and an internal resistance of 1,5 .
S1
V1
V2
R
A
10
15
S2
R is a resistor with an unknown resistance. The light bulb has a resistance of 15 . The resistance of the switches, S1 and S2 , ammeter and conducting wires can be ignored.
2.1 State Ohm's law in words.
(3)
2.2 What is meant by the internal resistance of the battery?
(2)
2.3 Calculate the effective resistance of the 10 resistor and light bulb.
(3)
When the switch S1 is closed, the bulb converts 576 J of energy per minute.
2.4 Calculate the reading on the voltmeter V2 when the switch is closed.
(4)
2.5 Calculate the reading on the ammeter.
(3)
2.6 Determine the resistance of resistor R.
(4)
2.7 Briefly explain what will happen to the reading on voltmeter V1 when switch S2 is
opened.
(4)
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RESOURCE PACK
3. Learners conduct an investigation to verify Ohm's law. They measure the current through a conducting wire for different potential differences across its ends. The results obtained are shown in the graph below.
Current (A)
00,.99 00,.88 00,.77 00,.66 00,.55 00,.44 00,.33 00,.22 00,.11 00
00 1,.0
2,.0 3.,0 4,.0 5,.0 6,.0 7,.0 Potential difference (V)
3.1 Which one of the measured quantities is the dependent variable?
(1)
3.2 The graph deviates from Ohm's law at some point.
3.2.1 Write down the coordinates of the plotted point on the graph beyond which
Ohm's law is not obeyed
(2)
3.2.2 Give a possible reason for the deviation from Ohm's law as shown in the
graph. Assume that all measurements are correct.
(2)
3.3 Calculate the gradient of the graph for the section where Ohm's law is obeyed. Use
this to calculate the resistance of the conducting wire.
(4)
4. Three resistors, R1 , R2 and R3 , are connected to a battery, as shown in the circuit diagram below. The internal resistance of the battery is 0,3 . The resistance of R2 and R3 is equal. The resistance of R1 is half that of R2 . When both switches are open, the voltmeter across the battery reads 9 V.
9 V
S1
r
N
S2
0,3
V1
R1 =R
R2 =2R
R3 =2R
A
P
Q
6Grade 12 Physical Sciences
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WORKSHEETS
TOPIC 10
TOPIC 10: ELECTRIC CIRCUITS
4.1 What is the emf of the battery? Give reason for the answer.
(2)
4.2 When switches S1 and S2 are closed, the reading on the ammeter is 3 A. Calculate the resistance of R1 .(5)
4.3 Switch S1 is now opened.
4.3.1 How will the resistance of the circuit change? Write down only INCREASES,
DECREASES or REMAINS THE SAME.
(1)
4.3.2 What effect will this have on the "lost volts"? Explain the answer.
(3)
5. The battery in the circuit below has an emf of 12 V and an internal resistance of 0,2 . The resistance of the connecting wires can be ignored.
15 I
0,2
V
12 V
9
8
I
2
5.1 Calculate the current through the battery.
(6)
5.2 How will the reading on the voltmeter be affected if the 9 resistor is removed and replaced with a conducting wire of negligible resistance? Explain the answer. (4)
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RESOURCE PACK
CONSOLIDATION QUESTIONS
TOTAL: 52 MARKS
1. 1.1In an experiment, learners use the circuit below to determine the internal resistance of a cell.
E r
V
The circuit consists of a cell of emf E and internal resistance r. A voltmeter is placed across a variable resistor which can be set to known values R.
The equation used by the learners is:
1 V
=
r ER
+
1 E
They obtain the graph below.
Graph of 1 versus 1
V
R
2,0
1,5
1 V
(V -1 )
1,0
0,5
00
1
2
3
4
5
1 ( -1 )
R
1.1.1 Write down a mathematical relationship for the slope of the graph.
(1)
Use the information in the graph and calculate the:
1.1.2 emf of the cell.
(2)
1.1.3 internal resistance of the cell.
(3)
8Grade 12 Physical Sciences
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