SIMPLE INTEREST SOLUTION - EXAMPURA
[Pages:24]SIMPLE INTEREST SOLUTION
1. (b) Rate (nj) % = 4%
Simple Interest
(lk/kj.k C;kt)= Rs. 150 Time (le;) = 6 months (ekg)
Amount 7
Principal 6
+1
=
6 12
=1 2
year
Let the principal
(ewy/u)= Rs. P
Required Rate% =
1 ?100 = 5 5 %
63
9
We know (ge tkurs gS,a)
3. (d) Note SI for every year will be same.
2.
SI = P ? R ? T 100
uksV% izR;sd o"kZ ds fy, lk/kj.k C;kt cjkcj gksxkA
Simple Interest for 3 years
(3 o"kks? dk lk/kj.k C=;k3t?) 5 = 15%
T Where (tgk?),
Simple Interest for 4 years
SI Simple Interest (lk/kj.k C;kt)
(4 o"kks? dk lk/kj.k C=;k4t?) 5 = 20%
A E P Principal (ewy/u)
Difference in interest (C;kt dk varj)
T R Rate (nj)
G U T Time (le;) A IT P?4?1
T 150 = 2 ?100
= (20 ? 15) = 5% According to question 5% of sum = 42
(iz'ukuqlk, j)
42 Sum = 5 ?100 = Rs. 840
H S 150?200
T IN P=
4
= Rs. 7500
4. (c) Let the rate of interest for two different sources is r 1 and r 2 respectively.
(a) Let principal (ekuk fd ewy/u=) 6P,
ekuk fd nks vyx&vyx lzksrksa ls C;kt nrj1?e'k%
A Hence, Amount
(feJ/u) = 6P ?
7 6 = 7P
vkSrj2 gSA
According to the question
(iz'ukuqlk, j)
H SI = 7P ? 6P = P T Time (le;) = 3 years (o"kZ)
1500?r ?13 100
?
1500?r ?2 3 100
= 13.50
SI = P ? R ? T 100
4500 r 1 ? 4500 r 2 = 1350 1350
(r1 ? r 2) = 4500 = 0.3%
6P?R?3 P = 100
Hence, Required difference in rates
(njksa dk vHkh"V=v0a.r3j%)
R=
100 18
=50 9
= 5 5% 9
Alternate:Note: In such type of questions to save
Alternate:- / oSdfYid fof/:Let the difference in rates (ekuk fd njksa dk varj) = d% According to the question (iz'ukuqlk, j)
your valuable time try to think like that.
uksVbl%izdkj ds iz'uksa esa uhps nh x;h fof/ ds vuqlkj
d =
13.50 1500
?100 3
=1350 4500
lkspus dk iz;kl djsaA
5. (a) Let the sum lent at 8% is
= 0.3% x then
sum lent at 10% is (10000 ?
x)
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ekuk fd 8? C;kt nj ij x #i;s dtZ fn;k x;k rFkk 10% nj ij (10000 ? x) #i;s dk dtZ fn;k x;kA According to the question (iz'ukuqlk, j)
8
10
x ? 100 ? 1 + (10000 ? x) ? 100 ? 1
5 units = Rs. 10,000
1 unit = Rs. 2,000
Hence amount invested at 8%
(8? dh nj
ij fuos'k dh x;h jkf'k=) 2 units (;wfuV)
= 2 ? 2000 = Rs. 4000
Amount invested at 10% (10? dh nj ij
9.2 = 10000 ? 100 ? 1
fuos'k dh x;h jkf'=k)3 units (;wfuV)
= 3 ? 2000 = Rs. 6000
6. (c) Time = 2 years 3 months
8 x +10(10000? )x
100
100
= 920
8 x + 100000 ? 10 x = 92000
= 2 +
3 =9 12 4
years
?2 x + 100000 = 92000 ?2 x = 92000 ? 100000 ?2 x = ? 8000
SI = P ? R ? T
We know
100
T x = 4000
Hence, Amount lent at ( 8% C;kt nj ij dtZ
A E nh x;h jkf'k8)% = Rs. 4000
T Amount lent at (10? C;kt nj ij dtZ nh x;h
G U jkf'k)10% = (10000 ? 4000)
P = Rs. 1600, T =
9 4 years, SI = Rs. 252
Put values in the above formula
fof/ esa eku j[kus ,ij)
(mijksDr
A IT = Rs. 6000
Alternate:-/ oSdfYid fof/:-
1600?R?9 252 = 4?100
T Note:- In such type questions to save
252 = 36 R
H S your valuable time follow the given below
method.
T IN uksVb%l izdkj ds iz'uksa esas vius cgqewY; le; ds
252 R = 36 = 7%
cpr ds fy, vki uhps nh x;h fof/ dk iz;ksx dj 7.
A ldrs gSaA
By alligation Method (feJ.k fu;e ds }kjk)
(b) Let the principal
(ekuk fd ewy/u=) 9 units
Hence simple interest
TH (lk/kj.k C;kt)=
4 9 ?9 = 4 units
(i)
Ist part
IInd part
Let, Rate of interest (C;kt nj) = R%
8%
10%
R = T (Given)
By using formula,
9.2%
SI = P ? R ? T 100
Ratio of
0.8
quantity
2
1.2
:
3
9?R?R
400
4 = 100 R2 = 9
R =
20 3
= 6 2% 3
According to the question (2 + 3) units = Rs. 10,000
8. (c) Principal = Rs. 400,
(iz'ukuqlk, j)
Amount = Rs. 480
Simple Interest = Rs. (480 ? 400)
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= Rs. 80 Time = 4 years
=
2 ?100 5 10
= 4%
Rate% =
SI ? 100 P ? T
Rate% =
80?100 400?4
=8000 1600
= 5%
10. (c) Principal
Interest
5
2
+
2 5
New rate of interest = (5 + 2) = 7%
Required time =
2 ?100 58
= 5 years
400?7?4
Interest =
100 = 112
11. (a) Principal (ewy/u)= Rs. 1750
9.
Hence amount = Rs. (400 + 112)
= Rs. 512
Alternate:-
Note:- In such type of questions to save
T your valuable time follow the given below
method.
A E uksVb%l&izdkj ds iz'uksa esas vius cgqewY; le; ds
T cpr ds fy, vki uhps nh x;h fof/ dk iz;ksx dj
G U ldrs gSaA
A IT Increased in rates (nj esa o`f=?4 ? 2 = 8%
Hence increased in amount
(feJ/u esa o`f?)
T 8
H S = 400 ? 100 = 32 T IN Hence new amount
(u;k feJ/u)
Rs. (480 + 32) = Rs. 512
(a) Let principal
A (ekuk fd ewy/u=) 5 units
H Hence interest = 5 ? T Time = 10 years,
2 5 = 2 units
Let the first part (ekuk fd igyk Hkk=xx) Hence second part (blfy, nwljk Hkkx)
= (1750 ? x)
According to the question (iz'ukuqlk, j)
8
6
x ? 100 ? 1 = (1750 ? x) ? 100 ? 1
4 x = 5250 ? 3 x 7 x = 5250 x = 750
First part (igyk Hkkx=)Rs. 750
Second part (nwljk Hkkx)
= Rs. (1750 ? 750) = Rs. 1000 Required interest
(vHkh"V C;kt)
8 = 750 ? 100 = Rs. 60
Alternate:Note:- In such type of questions to save your valuable time follow the given below method.
By using formula,
uksVb%l&izdkj ds iz'uksa esa vius cgqewY; le; ds
Rate% =
2 ?100 5 10
= 4%
cpr ds fy, vki uhps nh x;h fof/ dk iz;ksx dj ldrs gSaA
Alternate:-
Let, Principal (ekuk fd ewy/u=) 100
Note:- In such type of questions to save your valuable time follow the given below method.
usits in both cases (nksuksa fLFkfr;ksa esa)
Ist part
II nd part
Total
uksVb%l&izdkj ds iz'uksa esa vius cgqewY; leP;ridnscipal 100 ?3 :
100
+ ?4
700 units
cpr ds fy, vki uhps nh x;h fof/ dk iz;ksx dj Interest 8 ?3 : 6 ?4
ldrs gSaA
Note: Interest is same in both cases
(nksuksa
Principal
Interest
fLFkfr;ksa esas C;kt cjkcj gksxkA)
5
2
+
2 5
According to the question 700 units = Rs. 1750
(iz'ukuqlk, j)
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1750 1 unit = Rs. 700
Ist part 4%
IIn d part 5%
1750 24 units = Rs. 700 ? 24 = Rs. 60
4.4 %
Hence, required interest (vHkh"V C;kt)
= Rs. 60
0.6
:
0.4
Ratio of
12. (d) Avg. rate of interest (vkSlr C;kt nj)
amounts
3
:
2
Hence Required Ratio (vHkh"V vuqikr)
300 = 1550
?100 3
=200 31
%
=3: 2
14. (b) Time (le;) = 4 years (o"kZ)
By using mixture and Alligation Rule
Let sum = 5 units
(feJ.k fu;e ds }kjk,)
Ist part
T 5%
IInd part 8%
Hence interest = 5 ?
1 5 = 1 unit
Required rate% =
1 100 5 ? 4 = 5%
A E 200 G UT 31
%
15. (a)
Amount (Rs.) 520
Time (years)
5
A IT Note: Always remember to solve such
T type of questions multiply by 31 in both
+48 568
+2 7
H S parts.
Hence interest in 2 years = Rs. 48
uksVb%l izdkj ds iz'uksa dk gy djrs gq, ges'kk nksuksa
T IN Hkkx 31 ls xq.kk djsaA
Interest in 1 years = Rs.
48 2 = Rs. 24
A Ist part H 155%
IInd part 248%
Interest in 5 years = Rs. 24 ? 5 = Rs. 120 We know,
SI = Amount ? Principal
T Principal = Rs. (520 ? 120) = Rs. 400
200 %
16. (c) Let the latter amount = Rs.
x
According to the question,
48
45
Ratio of
amounts 16
15
Required Ratio (vHkh"V vuqi=k1r)6 : 15 13. (b) Avg. rate of interest (vkSlr C;kt nj)
500?12?4 + ?x10?4
100
100
4x 240 + 10 = 480
4x 10 = 240
=
440 5000
?100 2
= 4.4%
x = 600 Hence latter amount =
Rs. 600
By using mixture and alligation rule
Alternate:-
(feJ.k fu;e ds }kjk,)
Note: In such type of questions to save
your valuable time follow the given below
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method.
uksVb%l&izdkj ds iz'uksa esa vius cgqewY; le; ds cpr ds fy, vki uhps nh x;h fof/ dk iz;ksx dj ldrs gSaA Interest on first part (igys Hkkx ij C;kt)
28 = 2500 ? 100 = Rs. 700 Remaining S.I. that is received from C
( C ls izkIr 'ks"k lk/kj.k C;kt)
= Rs. 1120 ? Rs. 700 = Rs. 420
500?12?4 = 100 = Rs. 240
Principal
(ewy/u)= 420 ?
100 28 = Rs. 1500
Remaining interest ('ks"k C;k=t)Rs. (480
? 240) = Rs. 240
19. (d)
Amount
Time
Hence Required amount (vHkh"V feJ/u)
(Rs.)
(years)
756
2
17.
240 = (4?10) ?100 = Rs. 600
(c) Let initial capital
T = 100 units 100
(ek=kk fd vkjafHkd laif?k)
A TE 8%
31 4
%
AGITU 8%
1
4
31 4
H ST difference T IN According to the question
(iz'ukuqlk, j) 20.
1 4 unit = Rs. 61.50
A 1 unit = Rs. 61.50 ? 4 = Rs. 246
100 units = Rs. 24600
H Hence, Required capital (vHkh"V laif?k)
T = Rs. 24600
+117 873
Hence interest
1.5 years
3
1 2
in
1
1 2
years
= Rs. 117
Interest in 1 year =
117 3 ? 2 = Rs. 78
Interest in 2 years = Rs. 78 ? 2 = Rs. 156 Principal = Rs. (756 ? 156) = Rs. 600
Required rate % =
78 600 ?100 = 13%
(c) Amount = Rs. 7000 Total interest in 5 years
10
50
1
= 5? 3 % = 3 % = 6
Principal 6
Amount (6 + 1)
Alternate:-
?1000
?1000
Difference in percentage (? esa varj)
6000
7000
31 = 8% ? 4 %
Hence Required principal = 21. (a) Time = 4 years
Rs. 6000
1 4 % = 61.50
100% = 24600 18. (d) Let sum lent to c = Rs. x
Sum
Amount
40
41
+1 unit
According to the question (iz'ukuqlk, j) Total interest of 4 years (4 o"kks? dk dqy C;kt)= 4 ? 7% = 28% S.I. received from B ( B ls izkIr lk/kj.k C;kt) 22
Required rate% =
1 ?100 40 1
? 4 =
10%
(d) Let the sum = Rs. P, T
8 1 = 12 yrs,
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15 T2 = 12 years
55.50
100 units =
1.5 ? 100 = Rs. 3700
According to the question,
24. (c) same as question no. 5 we will use the
P?5?15 ? P?4?8 100 ?12 100 ?12
= 129
alligation method (iz'u la[;k 5 dh rjg ge
;gk? Hkh feJ.k fu;e dk iz;ksx djsaxs)
6%
10%
43P
1200
= 129
P = Rs. 3600 Hence required sum
(vHkh"V ;ksx)
9.2 %
= Rs. 3600
0.8 : 3.2
Alternate:-
Let sum (ekuk fd ;ksx=) 100 units
According to the question,
T 100
(8?4)%
(15?5)%
GA TE 32
75
A ITU 43 units
1
:
Parts are
4
1000
1000
(4+1) ?4, (4+1) ?1
800, 200 25. (d) Total interest paid in 3 years
(3 o"kks? esa dqy
C;kt dk Hkqxr=ku12) ? 3 = 36%
Interest (C;kt) = Rs. 5400
According to the questions (iz'ukuqlk, j)
36% of sum = Rs. 5400
H ST difference
43 units = Rs. 129
T IN 1 unit = Rs. 3
100 units = Rs. 3 ? 100 = Rs. 300
A yearly sum = Rs. 12 ? 300 = Rs. 3600
Note:- Time is given in months and
rate% is given per annum. Hence we
26.
H multiplied the answer by 12.
T uksVl%e;&ekg esa fn;k x;k gS vkSj nj izfr'kr okf"kd
5400
1% of sum = Rs.
36
5400 sum = 36 ?100 = Rs. 15000
Hence, required sum (vHkh"V ;ksx)
= Rs. 15000
(c) Amount (Rs.)
Time (years)
gS blfy, geus m?kj dks 12 ls xq.kk dj fn;k gSA
1012
+55.20
23. (a) Let the sum = 100 units
21
2
+1
1 2
years
100
1067.20
4
11.5%
10%
Interest
in
3 2
years = Rs. 55.20
11.5
10
3 Interest in 2 years = Rs. 55.20
Interest in 1 year (1 o"kZ esa C;kt)
1.5 According to the question, 1.5 units = 55.50
55.50 1 units = 1.5
55.20 = 3 ? 2 = Rs. 36.80
Interest in 4 years (4 o"kks? esa C;kt)
= 36.80 ? 4 = Rs. 147.2 Principal = Amount ? Interest
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= 1067.20 ? 147.20 = Rs. 920
36.80
Required Rate% =
920 ?100 = 4%
27. (a)
Amount (Rs.)
720 +300
1020
Time (years)
2 +3
5
25?R?R 16 = 100 R2 = 64
R = 8% 31. (a) Let the principal
= 100 units
(ekuk fd ewy/u)
100
10%
12
1 2
%
gain
Interest in 3 years = Rs. 300
10
12.5
28. 29.
Interest in 1 years = Rs. 100
Interest in 2 years = Rs. 100 ? 2 =
Rs. 200
Required Sum = 720 ? 200 =
Rs. 520
T (d) Number of days in a years
(1 o"kZ esa fnuksa dh=l3a6[5;k)
A E Total money (dqy #i;s)= 1 ? 365
T = Rs. 365
G Time = 1 year,
U Rate% = 5%
A IT 365?100
T Sum =
5?1 = Rs. 7300
H S (d) Let the amount invested (ekuk fd fuos'k dh
T IN x;h jkf'k)= Rs. P
According to the question,
A P?9?2 +P?10?2 100 100
= 760
H (18P+20P)
32.
100
= 760
T 38P = 76000, P = 2000
Alternate:-
+2.5
According to the question, 2.5 units = Rs. 1250
1250 1 unit = Rs. 2.5 = Rs. 500
100 units = Rs. 500 ? 100 = Rs. 50,000
Hence, total principal (dqy ewy/u)
= Rs. 50,000 Alternate:-
1 12 2 % ? 10% = 2.5%
2.5% = 1250 (given) 100% = 50000
(c) T1 = 15 months =
15 12 years,
1
15
R1 = 7 2 % = 2 %
Total interest percent (dqy C;kt nj)
= (9 ? 2)% + (10 ? 2)%
8 T2 = 8 months = 12 years,
38% = 760
100% = 2000 Hence required principal = Rs. 2000
1
25
R2 = 12 2 % = 2 %
30. (a) Let sum = 25 units
Let the principal = P
Sum
Interest
According to the question,
25
16
?
16 25
P?15?15 ? P?25?8 12?2?100 12?2?100
= 32.50
Time(t) = Rate(R%) (Given)
225P ?200P 2400 2400
= 32.50
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25P 2400 = 32.50 P = Rs. 3120
Hence required principal =
Rs. 3120
Ist part 32%
IInd part 40%
33. (a) Sum 72
Amount 81
+9
Ratio of amounts
35 %
5
:3
interest
By using formula,
16000
Required part (vHkh"V H=kk(x5)+ 3) ? 5
34. 35. 36.
Time =
9 ?100?4 72 25
= 2 years
(a) Total days =
T May June July Aug. Sept
21 + 30 + 31 + 31 + 10
A E = 123 days
T By using formula,
G U 7300?5?123 A IT SI = 100?365 = Rs. 123
H ST (c) Gain% =
6
1%?2 4
?
(4
?
2)%
T IN = 12.5% ? 8% = 4.5%
Principa = Rs. 5000
A Required gain = 5000 ?
4.5 100 = Rs. 225
(c) Principal = Rs. 16000, Interest = Rs. 700
H Avg. rate of interest (vkSlr C;kt nj)
T 700
35
= Rs. 10,000 37. (b) Let principal = P,
Amount = 3 P Interest = 3P ? P = 2P According to the question,
P?R?20 2P = 100 R = 10%
Let after t year it will become double
(ekuk fdt o"kZ ds ckn ;g nksxquk gks tk,xk)
Hence, interest = 2P ? P = P
P?10?t P 100 t = 10 years
Alternate:Note: In such type of questions to save your valuable time follow the given below method.
uksVb%l izdkj ds iz'uksa esa vius cgqewY; le; ds cpr ds fy, vki uhps nh x;h fof/ dk iz;ksx dj ldrs gSaA)
= 16000 ?100 = 8 %
Now, By alligation Rule
Ist part
IIn d part
4% ? 8
5% ? 8
(feJ.k fu;e ds }kjk,)
Principal 1
1
Amount
Interest
Time (Years)
3 diff. 2 diff.
2
?
1 2
1
20
?
1 2
10
35 8
% ? 8
Hence required time = 10 years 38. (c) Let the first part = x
Note: To make your calculation easier multipling each part by 8.
second part = (1500 ? x) According to the question,
uksVv%iuh x.kuk dks vklku djus ds fy, izR;sd Hkkx dks 8 ls xq.kk dj nsaA
x ?10?5 =(1500? )x?12.5?4
100
100
50 x = (1500 ? x)50
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