Let u=sin(6x),so du =6cos(6x dx x u

[Pages:1]Let u = sin(6x), so du = 6 cos(6x) dx. When x = 0, u = 0;

when

x

=

12

,

u

=

1.

Thus,

/12 0

cos(6x)

sin(sin(6x))

dx

=

1 0

sin

u

1 6

du

=

1 6

[- cos u]10

=

-

1 6

(cos

1

-

1)

=

1 6

-

1 6

cos

1.

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