Integration of cos^2x sin2x/(2cosx-sinx)^2

x y= 2sin^2 x y=1- sinx find x values in the range 0 Integral (x^2cosx)/(1+sinx)^2 dx with limits from 0 to pi/4 equating the coefficients of sin x and x, or otherwise, find constants A and B that satisfie the identity. A(2sinx +cosx) +B(2cosx - sinx) = sinx + 8cosx I got A= 2, B = 3, which the answers said were correct. ................
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