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2 [sin6x + cos6x] — 3[sin4x + cos4x] + 1 = 0 cos2 9 + cos2 +9) — 2 cos oc cosO cos (oc +9) 9 96t ŒrTILG5. Sin 0 (tan 39 — tan 9) 6T6ïr cos 3 e sin 39 sin O cos 9 COS 36 sin 90 — [tan 279— tan O] cos 27 0 sin- c) 1800 cosA + cosB + cosC = 1 +4 sin —sin — 12 (2017) November • 2015 ................
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