Area between sinx and cosx
Using that interpretation, we note that cosx lies above sinx, on [0 , π/4]. (And, since the above answer came out as 0, we can just double the area between the curves on [0 , π/4].)Area = 2⋅∫0π/4 (cosx - sinx)dx = 2 (sinx + cosx)]0π/4 = 2√2 - 2 James C. answered • 01/24/21 BS in Mathematics with 20+ years of teaching experience ................
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