SEPARATION OF VARIABLES
[Pages:37]Differential Equations
SEPARATION OF VARIABLES
Graham S McDonald A Tutorial Module for learning the technique
of separation of variables
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c 2004 g.s.mcdonald@salford.ac.uk
Table of contents
1. Theory 2. Exercises 3. Answers 4. Standard integrals 5. Tips on using solutions
Full worked solutions
Section 1: Theory
3
1. Theory
If one can re-arrange an ordinary differential equation into the following standard form:
dy = f (x)g(y),
dx
then the solution may be found by the technique of SEPARATION OF VARIABLES:
dy = f (x) dx .
g(y)
This result is obtained by dividing the standard form by g(y), and then integrating both sides with respect to x.
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Section 2: Exercises
4
2. Exercises
Click on Exercise links for full worked solutions (there are 16 exercises in total)
Exercise 1. Find the general solution of dy = 3x2e-y and the particular solution
dx that satisfies the condition y(0) = 1
Exercise 2. dy y
Find the general solution of = dx x
Exercise 3.
dy y + 1
Solve the equation =
given the boundary condition: y = 1
dx x - 1
at x = 0
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Section 2: Exercises
5
Exercise 4. Solve y2 dy = x and find the particular solution when y(0) = 1
dx
Exercise 5. Find the solution of dy = e2x+y that has y = 0 when x = 0
dx
Exercise 6.
xy dy
Find the general solution of
=
x + 1 dx
Exercise 7. Find the general solution of x sin2 y. dy = (x + 1)2
dx
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Section 2: Exercises
6
Exercise 8.
Solve
dy dx
= -2x tan y
subject
to
the
condition:
y
=
2
when
x=0
Exercise 9. Solve (1 + x2) dy + xy = 0
dx and find the particular solution when
y(0) = 2
Exercise 10.
dy Solve x
= y2 + 1
and find the particular solution when
y(1) = 1
dx
Exercise 11. Find the general solution of x dy = y2 - 1
dx
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Section 2: Exercises
7
Exercise 12.
1 dy
x
Find the general solution of y dx = x2 + 1
Exercise 13.
dy
y
Solve =
and find the particular solution when y(1) = 3
dx x(x + 1)
Exercise 14. Find the general solution of sec x ? dy = sec2 y
dx
Exercise 15. Find the general solution of cosec3x dy = cos2 y
dx
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Section 2: Exercises
8
Exercise 16. Find the general solution of (1 - x2) dy + x(y - a) = 0 , where a is
dx a constant
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