The Specific Heat of a Metal
Example - How much heat is lost when a 25 g. piece of tin cools from 99.0 C to 19.0 C ? The specific heat of tin is .220 J / g. - C. Change in H = (25 g.) ( 80.0 C) ( .220 J / g. - C.) = 440 J *Read in Prentice Hall Chemistry pages 393 through 395. C. The specific heat of a substance can be determined experimentally by using the heat change equation. ................
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