6.006 Introduction to Algorithms Spring 2008 For ...

log5(lglg100 n) • (20n)7 • 5lg3n3 + 1080n2 + (lg3)n3.1 + 6006 • lg( N) N/2 . Stirling Banishes the Evil • N! ~= sqrt(2πN) * ((N/e) ^ N) • Substitute in lg(N N/2) • Reduce terms, obtain O(N) Binary Search for 23 1 3 4 9 11 15 20 24 29 34 38 1 3 4 9 11 15 20 24 29 34 38 ... x, y, z have n bits ... ................
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