THE GREEKS BLACK AND SCHOLES (BS) FORMULA
[Pages:19]THE GREEKS
BLACK AND SCHOLES (BS) FORMULA
The equilibrium price of the call option (C; European on a non-dividend paying stock) is shown by Black and Scholes to be:
Ct = StN (d1) Xe r(T t)N (d2);
Moreover d1 and d2 are given by
d1
=
ln(
St X
)
+
(r + p
1 2
T
2)(T t
t) ;
d2
=
ln(
St X
)
+
(r p
1 2
T
2)(T t
t)
p
Note that d2 = d1
T
Delta of a (European; non-dividend paying stock) call option:
The delta of a derivative security, , is de...ned as the rate of change of its price with respect to the price of the underlying asset.
For a European (on a non-dividend paying stock) call option is given by
=
#Ct #St
=
N (d1)
+
St
#N (d1) #St
+
Xe r(T t)#N (d2)
(1)
#St
where we have applied the product rule:
#[StN (d1)] #St
=
#St #St
N
(d1)
+
St
#N (d1) #St
=
=
N
(d1)
+
St
#N (d1) #St
Next we apply the chain rule
#N (d1) = #N (d1) #d1
(2)
#St
#d1 #St
Since
N (d1)
=
Z
d1 1
p1 2
e
X2
2 dx
it follows that
#N (d1) #d1
=
N 0(d1)
=
p1 2
e
d21 2
(3)
By using
d1;2
=
ln(
St X
)
+
(r p T
1 2
2)(T t
t)
we have
#d1 = #d2 = p1
(4)
#St #St St T t
Using equations (2)-(4) it can be shown that
St
#N (d1) #St
=
Xe
r(T
t)#N (d2) #St
or
StN 0(d1) = Xe r(T t)N 0(d2)
Thus equation (1) reduces to
=
#Ct #St
=
N (d1)
>
0
(5)
A delta neutral position:
Consider the following portfolio:
A short position in one call and a long position
in
#C #S
=
stocks:
#C
=C
S)
#S
#
#C #C
=
= 0:
#S
#S #S
The delta of the investor's hedge position is therefore
zero.
The delta of the asset position o?sets the delta of the option position.
A position with a delta of zero is referred to as being delta neutral.
It is important to realize that the investor's position only remains delta hedged (or delta neutral) for a relatively short period of time. This is because delta changes with both changes in the stock and the passage of time.
The Gamma of a call option:
The second derivative of the call option with respect to the price of the stock is called the Gamma of the option and is given by
#2Ct #St2
=
# #St
=
#N (d1) #St
(6)
Recall that from equation (2) we have
where and
#N (d1) = #N (d1) #d1
#St
#d1 #St
#N (d1) #d1
=
N 0(d1)
=
1 p
2
e
d21 2
#d1 = #d2 =
1 p
#St #St St T t
and the time to maturity for an at the money call option:
Recall that
=
#Ct #St
=
N (d1)
Thus applying the chain rule gives
# #
=
N
0(d1)
#d1 #
;
where
N 0(d1)
=
1 p
2
e
d21
2 >0
For
an
at
the
money
call
option
(St
=
X ),
since
ln(
St X
)
=
0, we have
d1 = (r +p21 2)
=
(r
+
1 2
2)p
Thus
#d1 = (r +p12 2) > 0
#
2
It
can
be
shown
that
#2 #2
<
0
BLACK AND SCHOLES (BS) FORMULA
The equilibrium price of the call option (C; European on a non-dividend paying stock) is shown by Black and Scholes to be:
Ct = StN (d1) Xe r(T t)N (d2);
where d1 and d2 are given by
d1
=
ln(
St X
)
+
(r + p
1 2
T
2)(T t
t) ;
d2
=
ln(
St X
)
+
(r p
1 2
T
2)(T t
t)
or
p d2 = d1
................
................
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