Hypothesis Testing:

= 2xTcdf (-10^99, -2.05, 16) =2(0.0286) =0.0571. Decision: Since the calculated value of t does not fall into the rejection region we fail to reject H0. Also note that the p-value is larger than the significance level of 0.05. Conclusion: There is not enough evidence to conclude that the mean pH level in the water is different from 8.5. Let’s ... ................
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