18.01 Single Variable Calculus Fall ... - MIT OpenCourseWare

1 − cos(2x) x sin(2x) sin2xdx = dx = + c 2 2 − 4 The full strategy for these types of problems is to keep applying Method B until you can apply MethodA(whenoneof m or n isodd). Example 3. sin2 x cos2xdx. ApplyingMethodBtwiceyields 1 − cos2x 1 + cos2x 1 1 2 2 dx = 4 − 4 cos22x dx 1 1 1 1 = 4 − 8 (1 + cos4x) dx = 8 x − 32 sin4x + c ... ................
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