Lecture 8: Solving Ax = b: row reduced form R
1 2 2 2 A = ⎣ 2 4 6 8 ⎦ . 3 6 8 10 The third row of A is the sum of its first and second rows, so we know that if Ax = b the third component of b equals the sum of its first and second components. If b does not satisfy b3 = b1 + b2 the system has no solution. If a ... 1 0 2 ⎢ ⎢ ⎣ ⎥ ⎥ ... ................
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