CHAPTER 10: COORDINATION CHEMISTRY II: BONDING
138
Chapter 10 Coordination Chemistry II: Bonding
CHAPTER 10: COORDINATION CHEMISTRY II: BONDING
10.1 a.
Tetrahedral d 6, 4 unpaired electrons
b.
[Co(H2O)6]2+, high spin octahedral d 7, 3 unpaired electrons
c.
[Cr(H2O)6]3+, octahedral d 3, 3 unpaired electrons
d.
square planar d 7, 1 unpaired electron
e. 10.2 a.
5.1 BM = = nn 2; n 4.2 4
[M(H2O)6]3+ with 1 unpaired electron. d1:
M = Ti
b.
[MBr4]? with the maximum number of unpaired electrons (5).
M3+ with 5 d electrons: M = Fe
c.
Diamagnetic [M(CN)6]3?. The strong field cyano ligand favors
low spin. M3+ with 6 d electrons: M = Co
d.
[M(H2O)6]2+ having LFSE =
3 5
o
.
Both high spin d4 and d9 have the correct
o.
High spin d4: M = Cr
0.6
d9: M = Cu
0.6
? 0.4
? 0.4
10.3 a.
K3[M(CN)6] M is first row transition metal, 3 unpaired electrons. M3+ with 3 d electrons: M = Cr
Copyright ? 2014 Pearson Education, Inc.
Chapter 10 Coordination Chemistry II: Bonding
139
b.
[M(H2O)6]3+ M is second row transition metal, LFSE = 2.4 o. This can be achieved
with a low spin d6 configuration. M3+ with 6 d electrons: M = Rh
0.6
? 0.4
c.
[MCl4]? M is first row transition metal, 5 unpaired electrons.
M3+ with 5 d electrons: Fe
d.
MCl2(NH3)2 M is third row d8 transition metal; two M?Cl stretching bands in IR.
Second and third row d8 complexes are often square planar. The presence of two
M?Cl stretching bands implies cis geometry of the chloro ligands.
M2+ with 8 d electrons: M = Pt
Cl
NH3
Pt
Cl
NH3
10.4 Angular overlap calculations for d 8 and d 9 ions show no energy difference between D4h and Oh when exclusively considering interactions. Both d 8 geometries have energies of -3e; both d 9 geometries have energies of -6e. In general, stability constants decrease as more ligands are added; the sequence for nickel is the common one. The huge drop in stability constant between the second and third ethylenediamine on Cu2+ is a result of the d 9 Jahn-Teller effect. The first two en ligands add in a square-planar geometry, with water molecules in the axial positions, and the coordination of these two mondentate ligands allows for the Jahn-Teller distortion. Adding a third en ligand requires a geometry change and with a preference for uniform M--N bond distances towards the six nitrogen atoms. This is counter to the Jahn-Teller distortion, and the third addition is much less favorable than the first two.
10.5 [M(H2O)6]2+ M is first row transition metal, ? = 3.9 BM. The magnetic moment implies 3
unpaired electrons, which would give rise to 33 5 = 3.9 BM. There are two possibilities,
d3 and d7:
M2+ , d3 : M = V
M2+ , d7: M = Co
10.6 a. b. c. d.
[Cr(H2O)6]2+ n = 4
4(6) 4.9 B
[Cr(CN)6]4? n = 2
2(4) 2.8 B
[FeCl4]?
n = 5
5(7) 5.9 B
[Fe(CN)6]3? n = 1
1(3) 1.7 B
e.
[Ni(H2O)6]2+ n = 2
2(4) 2.8 B
f.
[Cu(en)2(H2O)2]2+ n = 1
1(3) 1.7 B
Copyright ? 2014 Pearson Education, Inc.
140
Chapter 10 Coordination Chemistry II: Bonding
10.7 Fe(H2O)4(CN)2 is really [Fe(H2O)6]2[Fe(CN)6], all containing Fe(II). [Fe(H2O)6]2+ is high spin d 6, with = 4.9 ?B; [Fe(CN)6]4? is low spin d 6 , with = 0 ?B. The average value is then 2 ? 4.9/3 = 3.3 ?B.
2.67 unpaired electrons gives 2.67 4.67 3.53 ?B.
10.8 Co(II) is d 7. In tetrahedral complexes, it is generally high spin and has 3 unpaired electrons; in octahedral complexes, it is also typically high spin and also has 3 unpaired electrons; in square planar complexes, it has 1 unpaired electron. The magnetic moments can be calculated as
n(n 2) 3.9, 3.9, and 1.7 B, respectively.
10.9 For the red compounds (Me and Et at high temperatures, Pr, pip, and pyr at all temperatures), the larger magnetic moment indicates approximately 5 unpaired electrons, appropriate for high-spin Fe(III) species. At low temperatures for the Me and Et compounds, the magnetic moment indicates 3 to 4 unpaired electrons, an average value indicating an equilibrium mixture of high and low spin species. The low spin octahedral complexes have 1 unpaired electron. Increasing the size of the R groups changes the structure enough that it is locked into high-spin species at all temperatures.
10.10 Both [M(H2O)6]2+ and [M(NH3)6]2+ should show the double-humped curve of Figure 10.12, with larger values for the NH3 compounds. Therefore, the difference between these curves shows the same general features as in Figure 10.12.
10.11
These can be verified using the approach introduced in Chapters 4 and 5, in which a character of +1 is counted for each operation that leaves a vector unchanged, a character of ?1 for each operation that leaves a vector in its position, but with the direction reversed. The general transformation matrix for rotation is provided in Figure 4.16. Application is of this matrix is necessary to deduce the characters involving rotations.
10.12 The e column gives d orbital energies for complexes involving donor ligands only; the Total column gives energies for complexes of ligands that act as both donors and acceptors:
a.
ML2, using positions 1 and 6:
e
z2
2
x2?y2
0
xy
0
xz
0
yz
0
e
Total
0
2e
0
0
0
0
?2
?2 e
?2
?2 e
b.
ML3, using positions 2, 11, 12:
z2 x2?y2
xy xz
yz
e
e
0.75
0
1.125
?1.5
1.125
?1.5
0
?1.5
0
?1.5
Total
0.75e 1.125 e ? 1.5 e 1.125 e ? 1.5 e
?1.5 e ?1.5 e
Copyright ? 2014 Pearson Education, Inc.
Chapter 10 Coordination Chemistry II: Bonding
141
c. d. e. 10.13
ML5, C4v, using positions 1, 2, 3, 4, 5:
e
e
z2
2
0
x2?y2
3
0
xy
0
?4
xz
0
?3
yz
0
?3
Total
2e 3e ?4e ?3e ?3e
ML5, D3h, using positions 1, 2, 6, 11, 12:
z2 x2?y2
e
e
2.75
0
1.125
?1.5
xy
1.125
?1.5
xz
0
?3.5
yz
0
?3.5
Total
2.75e 1.125 e ? 1.5 e 1.125 e ? 1.5 e
?3.5 e ?3.5 e
ML8, cube, positions 7, 8, 9, 10, doubled for the other four corners:
e
e
z2
0
?5.33
x2?y2
0
?5.33
Total
?5.33 e ?5.33 e
xy
2.67
?1.78
2.67 e ? 1.78 e
xz
2.67
?1.78
2.67 e ? 1.78 e
yz
2.67
?1.78
2.67 e ? 1.78 e
Metal d orbitals, NH3 influence
e
e Total
z2
1
x2?y2
3
0
1e
0
3e
xy
0
0
0
xz
0
0
0
yz
0
0
0
Metal d orbitals, Cl? influence
e
z2
2
x2?y2
0
e Total
0
2e
0
0
xy
0
0
0
xz
0
yz
0
2
2 e
2
2 e
Ligand NH3:
e
1
0
2
?1
3
?1
4
?1
5
?1
6
0
Total
0
?1e ?1e ?1e ?1e
0
Ligand Cl?:
e
1
?1
2
0
3
0
4
0
5
0
6
?1
e
Total
?2 ?1e ? 2 e
0
0
0
0
0
0
0
0
?2 ?1e ? 2 e
Overall energy = ?8 e(NH3) ? 4 e(Cl) ? 8 e(Cl) + 4 e(Cl) = ?8 e(NH3) ? 4 e(Cl) ? 4 e(Cl) The metal electrons are still unpaired, one in the dxy orbital and one each in the dxz and dyz, raised by interaction with Cl?. Four of the ligand orbitals are lowered by e(NH3) and two are lowered
Copyright ? 2014 Pearson Education, Inc.
142
Chapter 10 Coordination Chemistry II: Bonding
by e(Cl) + 2 e(Cl); each contains a pair of ligand electrons. The precise orbital energies cannot be calculated since the angular overlap parameters for NH3 and Cl towards Cr(III) are not provided. Table 10.13 does provide the necessary parameters for trans-[Cr(NH3)4F2]+ .
10.14 a.
If we assume these ligands have similar donor abilities, the energies below are obtained for the molecular orbitals with high d orbital character.
metal d orbitals
z2
x2-y2
xy
xz
yz
1.125e
2.75e
b.
For consideration of L as a -acceptor in the axial position, the identical energy level
diagram is obtained regardless of whether L is assigned to position 1 or 6. The xz and yz
orbitals are each stabilized by e.
z2
metal d orbitals
x2-y2
xy
xz
yz
1.125e e
2.75e
For consideration of L in an equatorial position, the angular overlap result is different
depending on whether the -acceptor is placed in position 2 or position 11/12. This is problematic since all three equatorial positions are indistinguishable.
For L in position 2:
z2
metal 1.125ee d orbitals
x2-y2 xy
yz xz
1.125e e
Copyright ? 2014 Pearson Education, Inc.
2.75e
................
................
In order to avoid copyright disputes, this page is only a partial summary.
To fulfill the demand for quickly locating and searching documents.
It is intelligent file search solution for home and business.
Related searches
- tom sawyer chapter 10 summary
- chapter 10 photosynthesis quizlet
- chapter 10 photosynthesis pdf
- 10 cool chemistry experiments
- chapter 10 photosynthesis key
- chapter 10 photosynthesis answer key
- chapter 10 photosynthesis answers
- chapter 10 photosynthesis reading guide
- chapter 10 vocabulary us history
- the outsiders chapter 10 answers
- chapter 10 outsiders questions quizlet
- chapter 10 biology test answers