Chapter 10 Worksheet #2 Answer
[Pages:2]Name ________KEY__________ Block _______
Chapter 10 Worksheet #2
1. Calculate the energy require (in calories) to heat 10.4 g of mercury from 37.0oC to 42.0oC. Specific heat of mercury is 0.14 J/goC.
q = m c t q =10.4 g ? 0.14 J/goC ? 5.00 oC =
7.28 J ? 1 cal 4.184 J
= 1.74 cal
2. If 50. J of heat are applied to 10. g of iron, by how much will the temperature of the iron increase? The specific heat of iron is 0.45 J/goC.
t = q / m c t =50. J / 10.g ? 0.45 J/goC =
50 J goC 10.g ? 0.45 J
= 11 oC
3. Calculate the amount of energy required (in calories) to heat 145 g of water from 22.3oC to 75.0oC.
q = m c t q =145 g ? 1.00 J/goC ? (75 oC -22.3 oC) = 145 g ? 1.00 J/goC ? 52.7 oC
7641.5 cal = 7640 cal
4. If 52.5 kJ of heat is heated to a 1.02 kg block of metal, the temperature of the metal increases by 11.2oC. Calculate the specific heat capacity of the metal in J/goC. c = q / m t convert units 52.5 KJ = 52,500 J and 1.02 kg = 1,020 g c =52,500 J / 1,020.g ? 11.2 oC c = 4.595588 J/goC = 4.60 J/goC
5. If 4.524 x 103 J of heat is applied to a 742.1 g sample of iron, by how many degrees Celsius will the temperature of the iron sample increase? Specific heat is 0.45 J/goC.
t = q / m c q =4.524 x 103 J / 742.1 g ? 0.45 J/goC =
4.524 x 103 J goC = 0.013547141oC = 0.01355 oC or 1.355 x 102 oC 742.1.g ? 0.45 J
6. What was the initial temperature of a 32.5 g iron bar if 276.8 J of energy were applied resulting in a final temperature of 95.4oC? The specific heat capacity of solid iron is 0.45 J/goC.
t = q / m c t =276.8 J / 32.5 g ? 0.45 J/goC =
276.8 J goC
= 18.9 oC
32.5.g ? 0.45 J 95.4 oC -- 18.9 oC =76.5 oC
7. Are the following processes exothermic or endothermic?
a. the combustion of gasoline in a car engine
Exothermic
b. water condensing on a cold pipe
Endothermic
c. CO2 (s)
CO2 (g)
Endothermic
d. F2 (g) 2 F (g)
Exothermic
8. Why does ice float on the surface of liquid water? It is less dense then water (the Crystallized structure).
9. Perform the following conversions. a. 850 cal to J
3556.4 J
850 cal x 4.184 J = 3556.4 J 1 cal
b. 5.901 J to cal
1.421 cal
5.901 J x 1 cal = 1.421 cal 4.184 J
................
................
In order to avoid copyright disputes, this page is only a partial summary.
To fulfill the demand for quickly locating and searching documents.
It is intelligent file search solution for home and business.
Related download
- tutorial 6 gases eastern illinois university
- performance jlg industries
- conversion chart fractions inch mm 1 32 0 031 0 79 1 16 2
- myopericarditis following covid 19 vaccination updates
- confocal laser scanning microscopy tutorial
- che 214062 switch body r12 allied elec
- dpm 742 bl 4 20ma loop powered indicator with backlighting
- distributions related to the normal distribution
- tulsa district corps of engineers daily morning reservoir
- release notes for cisco ncs 560 series routers cisco ios
Related searches
- significant figures worksheet and answer key
- theme worksheet 3 answer key
- cells worksheet and answer key
- scientific notation worksheet with answer key
- classification worksheet and answer key
- math worksheet with answer key 5 grade
- chapter 9 cellular respiration answer key
- chapter 10 photosynthesis answer key
- grammar worksheet with answer key
- chapter 13 1 rna answer key
- theme worksheet 2 answer key
- stoichiometry worksheet 2 answer key