Version 001 – HW03-More Ideal Gas Law Practice – sparks ...
1.3873 L 2.1271 L 3.2119 L correct 4.25823 L 5.2147 L Explanation: n = 4.86 kg C6H12O6· 1000 g 1 kg · mol C6H12O6 180 g C6H12O6 · 3 mol CH4 1 mol C6H12O6 = 81 mol CH4 T = 323 K P = 770 torr· 1 atm 760 torr = 1.01316 atm Applying the ideal gas law equation, P V = nRT V = nRT P V = (81 mol) 0.08206 L·atm mol·K (323 K) 1.01316 atm = 2119.05 ... ................
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