Junior Certifi cate Ordinary Level Maths Solutions SEC 2013 ...
Junior Certificate Ordinary Level Maths Solutions SEC 2013 Sample Paper 2
1. = 6 ? ( 2 ? 2) = 6 ? 4 = 24 cm2
2. (a)
p r2h = (3.14)(3)(3)(10) = 282.6 cm3
(b) Base of carton B = 5 ? 5 = 25
_2_8_2_.6_ 25
=
11.304
= 11.3 cm
(c) Container: Cylindrical Tin A
Reason: The surface area of Tin A = 2prh = 2(3.14)(3)(10) = 188.4 but that of Carton B = 4(11.3 ? 5) + 2(5 ? 5) = 276
Less material is therefore needed for the cylinder, assuming that the materials used cost the same.
3. (a) 08:50
(b) 10:15 09:75
_?_0_8_:5_0_
=
_0_8_:_5_0_ 1 hour
25
minutes
(c) 75 minutes = 1 hour 15 mins
8:50
_?_1_:1_5_ 07:35
07:35
(d) 133.88 ? 74.99 ? 25.00
= 33.89
(e)
Speed
=
_D_i_s_ta_n_c_e_ Time
=
__4_6_4__k_m___ 1 hour 25 m
=
_4_6_4_ 85
?
60
=327.5 km/hr
1
No. of students
4. Multiple possible answers. Examples:
Question Q1. What colour are your eyes?
Q2. What size T-shirt do you wear ? small, medium, large, extra large?
Q3. How many people are in your class? Q4. How old are you? 5. (a) UK 50, Ireland 50 (b)
8
6
4
2
Type of data Categorical data where the categories are not ordered Ordered categorical data Discrete numerical data Continuous numerical data
UK
No. of students
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 Number of hours Ireland
8 6 4 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 Number of hours
(c) Similarity: UK students and Irish students spent a maximum of 25 hours on social networking sites.
Difference: A lot more UK students spend from 20 to 24 hours on networking sites compared to Irish students.
(d) Answer: Yes
Reason: The majority of UK people spend from 13 to 22 hours networking, whereas Irish people are more varied, ranging from 3 to 20 hours in general.
2
6.
Colour
Frequency
Relative frequency
_F_r_e_q_u_e_n_c_y_ Total
% of total (Relative frequency ? 100)
Red 123
_1_2_3_ 240
51.25%
Blue 78
_7_8__ 240
32.5%
White 39
_3_9__ 240
16.25%
Total 240
(a) There may be more red disks in the bag.
(b)
Colour
Red
Probability
_1_2_3_ 240
Blue
_7__8_ 240
White
_3__9_ 240
(d) Answer: Yes
Reason: There must be a minimum of three disks (red, blue and white) and a students takes out only one at a time and replaces it.
(e) Answer: 5 Red, 3 Blue, 2 White Reason: It might explain why P(Red) = 51%, P(Blue) = 33% and P(White) = 16%
7. (a)
A name is picked at random from a list of 50 girls and 50 boys A = A girl's name is picked
A fair coin is tossed once B = A head is the outcome
One card is drawn at random from a pack of playing cards. C = The card is a diamond
A day is chosen at random from a list of the days of the week. D = The name of the day contains the letter a.
One number is picked at random from the set {1, 2, 3, 4, 5, 7, 11, 13} E = The number chosen is a prime number Prime = {2, 3, 5, 7, 11, 13}
Probability
_5__0_ 100
=
_1_ 2
_1_ 2
_1_3_ 52
=
_1_ 4
1
_6_ 8
=
_3_ 4
3
(b)
B
CX A
E
D
0
0.33 0.5
1
(c) Example: The probability of choosing the letter F from the word FACE.
(d) Example: The probability that tomorrow is Friday if today is Thursday.
(e) See scale above.
8. (a) Multiple answers.
List 1 8 8 8 8 8 List 2 1 8 8 8 9
Any set of five numbers when added together and divided by 5 give 8.
(b) List 1 7 7 7 7 7 7 The number 7 must occur the most often. List 2 7 7 7 1 2 3
230?
9. (a) |ABC| = 50?, |DEF| = 110?
(b)
M
115?
N
P
90?
O 40?
In order of magnitude: O N M P
10. (a) A + B + C = 180?
(b) C + D = 180?
(c) A + B + C = C + D (since equal to 180?) A + B = C ? C + D A + B = D
Hence, | A| + | B| = | D|
(d) 180 ? 112 = 68?
180 ? 47 ? 68 = a
47?
65? = a
?
68? 112?
4
11. (a) 180 ? 36 = 144 ? 2
(b) & (c)
= 72?
A
36?
Bisector D
72? 36? B
72? C
(d) |DBC| = 72? ? 2 = 36? since bisected.
|DCB| = 72?
from part (a)
|BDC| = 180 ? 72 ? 36 = 72?
(e) Yes, BDC is isosceles, since |BCD| = |BDC| = 72?. By theorem |BD| = |BC|.
(f) (g) 12. (a)
|AC| = 9.3 cm, |BC| = 5.7 cm
_|A_C__| |BC|
=
1.632
sin 25? = 0.423 sin 50? = 0.766
cos 25? = 0.906 cos 50? = 0.643
tan 25? = 0.466 tan 50? = 1.192
(b) (i) Answer: Incorrect Reason: tan 50? = 1.192, which is greater than 1.
(ii) Answer: Incorrect Reason: sin 25? = 0.423 But sin 50? = 0.766 and not 0.846.
(iii) Answer: Incorrect Reason: cos 25? = 0.906 But cos 50? = 0.643.
5
13. (a) Multiple possible answers, e.g. 5 metres.
(b)
sin
22
=
_h_ 5
h = 5 sin 22?
5 metres
String
h
h = 1.873032967 h = 1.9 metres
14.
1
2
22? Find the height h of the kite above the ground
3
4
15. (a)
y
5
4 X1 Y1 3 A(0,3)
2
1
?2 ?1 0 ?1
X2 Y2 B(4,0)
x 12345
?2
_______________
(b) _(4__?_0__)2__+_(_0 ? 3)2 _(4_)_2__+_(?3)2
16 + 9
___
25
= 5 units
(c) |OA| = 3, |OB| = 4
(d) |AB|2 = |OA|2 + |OB|2 |AB|2 = 32 + 42 |AB|2 = 9 + 16 |AB|2 = 25
___
|AB| = 25 = 5 units
6
16. (a) (b)
Midpoint of B(1,2) and D(5,6)
( ) _1_+2__5_,
_2_+__6_ 2
= (3,4)
E = (6,7)
(c) Answer: Bee 2
Reason: Journey of Bee 1 = 10__u_n_i_ts__________ _______________
Journey of Bee 2 = _(5__?__1_)2 + (_6__?_7_)_2 + (6 ? 5)2 + (2 ? 6)2
= _1_6_ + 1_+__1 + 16 = 17 + 17
= 8.25 units
7
Junior Certificate Ordinary Level Maths Solutions Sample Paper 2, no. 1
1.
250
+ 950
1,200 g
_1_,2_0_0_ 1,000
=
1.2
kg
2. A, D, B, E, C
3. Example of numerical data: How many people are in your family?
Example of categorical data: What is your favourite colour? (Multiple possible answers)
4. (a) 247 km ? 5 = 1,235 km
(b) 175 km ? 3 = 525 km
(c) 1,235 + 525 = 1,760 ? 8 = 220 km
(d) 225 ? 9 = 2,025 ? 1,760 = 265 km 5.
6. (a) A = 110?, B = 90?, C = 300?, D = 55?
(b) 360? - (166? + 32? + 46?) 360? - 244? 116? = X Answer: X = 116? Explanation: A full revolution adds up to 360?.
8
................
................
In order to avoid copyright disputes, this page is only a partial summary.
To fulfill the demand for quickly locating and searching documents.
It is intelligent file search solution for home and business.
Related download
- mathematics project maths phase 1
- 9709 w12 ms 61 gce guide
- junior certifi cate ordinary level maths solutions sec 2013
- november 2012 revision maths maths gcse and a level
- 0580 s12 ms 42 physics maths tutor
- university of cambridge international examinations general
- 2012 leaving cert ordinary level official sample paper 1
- the effects of mathematics anxiety on primary students
- mathematics project maths phase 3
- mark scheme for the may june 2012 question paper for the
Related searches
- ordinary level mathematics study notes
- ordinary level exam result 2017
- 8th class maths solutions book
- ordinary level results 2018
- ordinary level results 2019
- ncert class 8 maths solutions learn cbse
- ordinary level mathematics past papers
- ncert maths solutions class 9
- ordinary level physics notes pdf
- ncert class 8 maths solutions pdf
- ncert maths solutions class 8
- maths solutions class 8