OHMS LAW CIRCLE
OHMS LAW
E2 P
R E
E X I E
R
I2 X R P
(P) (I) R
WATTS AMPS
OHMS VOLTS
E2 (R) (E) P X R
P
E P P I X R
I I2 I
A water heater has a single 5500 watt element, the voltage measures 240. What is the correct value in ohms for this element _______ ? If you measured the element and got a reading of 6 ohms how many amps would the element have to draw @ 240 volts ________ ?
A Stainless Steel wire 8’ long measures 75 ohms, how much voltage would have to be applied to make the wire give off 85 watts of energy ________?
Line voltage measures 124 volts, the motor pulls 7.5 amps while running. What should the ohm measurement be across the running windings __________?
Answers … Problem 1
Part (a) Known is wattage & voltage – looking at the wheel to find ohms the section that would work is E squared divided by P Answer 10.47 ohms.
Part (b) Known is ohms & voltage looking at the wheel to find amps the section that would work is E divided by R so the answer is 40 amps. As the circuit is fused at 30 Amps the element would have be to be replaced.
Problem 2 The section that would work is under volts you know P & R so the answer to that is the square root 79.84 volts.
Problem 3 under ohms you know amps (I) & volts (E) so E divided by I = 16.53 ohms
................
................
In order to avoid copyright disputes, this page is only a partial summary.
To fulfill the demand for quickly locating and searching documents.
It is intelligent file search solution for home and business.
Related download
Related searches
- circle highest grade completed
- 1 tampa general circle tampa fl 33606
- 5 tampa general circle tampa
- bright circle in vision
- simon sinek golden circle ted
- 6 tampa general circle 33606
- law of cosines vs law of sines
- amp ohms and speaker ohms
- amps and ohms to volts
- guitar amp speaker ohms choice
- volts amps watts ohms explained
- volts amps ohms relationship