LIMITING REAGENT Practice Problems

48.2 g HCl x (1 mole HCl) x ( 1 mole Cl2) x (70.90 g Cl2) = 23.4 g Cl2 (36.46 g HCl) ( 4 mole HCl) (1 mole Cl2) THE ANSWER TO A LIMITING REACTANT PROBLEM IS THE SMALLER OF THE TWO NUMBERS, ONCE THAT AMOUNT OF PRODUCT IS MADE, THE REACTION STOPS! Answer = … ................
................