Math 241, Quiz 11. 4/8/13. Name
16 2y 0 dy= 4 3 Z 4 4 (16 y2)3=2 dy: We now employ a trigonometric substitution by considering to be the angle in a right triangle with arms of lengths p 16 y2 and yand hypotenuse 4 such that sin = y=4 and cos = (1=4) p 16 y 2. It follows that dy= 4cos d and (16 y)3=2 = (4cos )3. The integral computation now becomes 4 3 Z 4 4 ................
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