CHM 130 - Quartzland
CHM 130
PRACTICE WORKSHEET #1
1. A mass of 7.50 pounds is equivalent to how many grams,
decagrams and milligrams.
2. A liquid has a specific gravity of 0.80. What is the volume
of 500. grams of the liquid?
3. What is the mass of 62.0 mL of water?
4. A cubic block of metal is 2.0 inches on each side and has a
mass of 550.0 grams. Calculate the density of the metal in g/cc.
5. Calculate the density of 45.0 grams of a liquid that occupies
25.0 mL.
6. Convert 32.0OC to _________OF.
7. 4.60 meters is equivalent to how many cm, dm, and yds?
8. -12.0OF would be given as ______OC.
9. 150.0 cc of a substance (Sp. G. equals 1.44) will have what mass?
10. A 4.65 gram sample of hydrated salt was found to have a
constant mass of 3.88 grams after heating. Calculate the
percentage of water in the hydrated salt.
11. Calculate the density of 22.8 mL of a liquid that has a mass
of 32.2 grams.
12. Convert -32.0OF to ________OC.
13. Calculate the number of dam equivalent to 2.50 miles.
(1.00 mile = 5280 ft.)
14. 40.0oC is equivalent to _______OF.
15. A block that is 20. mm by 2.0 cm by 2.00 inches has a mass of
35.4 grams. Calculate its' density.
16. Express 4.00 kg as tons. (1.00 ton = 2000. pounds)
17. 100.0OF would be given as _________OC.
18. 40.0 mL of a alcohol (Sp. G. = 0.78) will have a mass of
how many grams?
19. A metal ring weighing 15.0 grams was placed into a graduated cylinder
containing 43.8 mL of water. The water level rose to 46.3 mL after the ring
was placed into the graduated cylinder. Calculate the density of the ring in
g/cc.
20. What would be the volume of 0.450 Kilograms of water at 4OC?
21. Calculate the density of 32.8 mL of a liquid that has a mass
of 26.6 grams.
22. Convert -12.0OC to _________OF.
23. 450. dL is equivalent to how many kiloLiters, dkL, and gallons?
24. 100.0OF is equivalent to _________ OC.
25. A block that is 5.0 mm by 2.0 inches by 1.00 dm has a mass
of 32.9 grams. Calculate its' density in g/cc.
26. 5.00 yards is equivalent to how many hm, m and dm?
27. Calculate the mass of 800. mL of mercury (Sp. G. equals 13.6).
28. 8200. milligrams is equivalent to how many dag, dg and pounds?
29. What would be the mass of 1.25 Liters of water at 4OC?
30. 40.0 grams of alcohol (Sp. G. = 0.78) will occupy what volume?
31. A graduated cylinder when empty has a mass of 125.30 grams and
when filled with 27.7 mL of a unknown liquid it has a mass of
162.25 grams. Calculate the density of the liquid in g/cc.
32. Convert 32.0OC to __________OF.
33. Convert 750. mL to kiloLiters, L and cubic centimeters.
34. The temperature -50.0OF is equivalent to ________OC.
35. A block that is 40. mm by 2.0 cm by 2.00 inches has a mass of 72.4 grams.
Calculate its' density in g/cc.
36. 2.50 meters is equivalent to how many dm, m and yards?
37. Calculate the volume occupied by 670. grams of alcohol
(Sp. G. = 0.80)
38. 946.0 decagrams is equivalent to how many kg, dg and pounds?
39. What would be the volume of 1.000 Kilograms of water at 4OC?
40. A 40.0 gram rock was placed in a graduated cylinder containing
36.6 mL of water. The new water level was 42.2 mL. Calculate
the density of the rock in g/mL.
41. 450. mL is equivalent to how many kiloLiters, dL and quarts?
42. A block that is 20. mm by 2.0 cm by 1.00 dm has a mass of 85.4
grams. Calculate its' density.
43. 2.50 yards is equivalent to how many dam, m and dm?
44. Calculate the volume occupied by 800. grams of concentrated
sulfuric acid (Sp. G. = 1.80)
45. 820.0 milliLiters is equivalent to how many cubic centimeters,
Liters, and hL?
46. What would be the volume of 0.450 Kilograms of water at 4oC?
47. 40.0 mL of an alcohol (Sp. G. = 0.78) will have a mass of how
many grams?
48. The high temperature in Phoenix last summer was reported to be 122 OF.
What is this temperature in degrees Celsius?
49. A block of metal is 4.0 inches thick, 4.0 cm wide, and 1.00 dm long and has a
mass of 2.000 kilograms. Calculate the density of the metal in grams/cc.
50. A liquid has a specific gravity of 0.80. What is the volume of 900. grams of
the liquid?
................
................
In order to avoid copyright disputes, this page is only a partial summary.
To fulfill the demand for quickly locating and searching documents.
It is intelligent file search solution for home and business.